Morphocompletion for #2262 ⟨a, b | aabbaba=aab⟩

Solved by morph:5/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aabbaba ⇒ aab
2. aababbaba ⇒ aabab
3. aabababbaba ⇒ aababab
4. aababababbaba ⇒ aabababab
5. aabababababbaba ⇒ aababababab
6. aababababababbaba ⇒ aabababababab
7. aabababababababbaba ⇒ aababababababab
8. aababababababababbaba ⇒ aabababababababab
9. aabababababababababbaba ⇒ aababababababababab
10. aababababababababababbaba ⇒ aabababababababababab
11. aabababababababababababbaba ⇒ aababababababababababab
12. aababababababababababababbaba ⇒ aabababababababababababab
13. aabababababababababababababbaba ⇒ aababababababababababababab
14. aababababababababababababababbaba ⇒ aabababababababababababababab
15. aabababababababababababababababbaba ⇒ aababababababababababababababab
16. aababababababababababababababababbaba ⇒ aabababababababababababababababab
...

Collecting factors up to length 8 / frequency 7:

[2/0]ba168lf:152,ls:16,rf:120
[2/1]ab152lf:152,rf:136,rs:16
[2/2]aa32lf:16,lp:16,rf:16,rp:16,lprp:16
[2/3]bb16lf:16
[3/0]aba152lf:136,ls:16,rf:120
[3/1]bab136lf:136,rf:120,rs:15
[3/2]aab32lf:16,lp:16,rf:16,rp:16,rs:1,re:1,lprp:16,lprs:1
[3/3]bba16lf:16
[3/4]abb16lf:16
[4/0]baba137lf:121,ls:16,rf:105
[4/1]abab120lf:120,rf:120,rs:15,a:1
[4/2]aaba30lf:15,lp:15,rf:15,rp:15,lprp:15,a:1
[4/3]bbab16lf:16
[4/4]abba16lf:16
[4/5]babb15lf:15,a:1
[4/6]aabb2lf:1,lp:1
[5/0]babab105lf:105,rf:105,rs:14,a:2
[5/1]ababa105lf:105,rf:105,a:2
[5/2]bbaba32lf:16,ls:16
[5/3]aabab30lf:15,lp:15,rf:15,rp:15,rs:1,re:1,lprp:15,lprs:1,a:1
[5/4]abbab16lf:16
[5/5]babba15lf:15,a:1
[5/6]ababb15lf:15,a:1
[6/0]ababab105lf:105,rf:105,rs:14,a:2
[6/1]bababa91lf:91,rf:91,a:3
[6/2]abbaba32lf:16,ls:16
[6/3]aababa28lf:14,lp:14,rf:14,rp:14,lprp:14,a:2
[6/4]babbab15lf:15,a:1
[6/5]ababba15lf:15,a:1
[6/6]bababb14lf:14,a:2
[7/0]bababab91lf:91,rf:91,rs:13,a:3
[7/1]abababa91lf:91,rf:91,a:3
[7/2]babbaba30lf:15,ls:15,a:1
[7/3]aababab28lf:14,lp:14,rf:14,rp:14,rs:1,re:1,lprp:14,lprs:1,a:2
[7/4]ababbab15lf:15,a:1
[7/5]bababba14lf:14,a:2
[7/6]abababb14lf:14,a:2

Considering [length 5 / frequency 2] bbaba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbaba=aab⟩.