Morphocompletion for #225 ⟨a, b | abaab=ba⟩

Back:⟨a, b | abaab=ba⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaab ⇒ ba
2. ababa ⇒ baaab
3. aabbaa ⇒ baaaab
4. baaabab ⇒ abba
5. baabaaab ⇒ abbaa
6. abbaaaab ⇒ babaa
7. baaabba ⇒ abbaaab
8. aaabbaba ⇒ baaaaabb
9. abbaaaba ⇒ babaaaab
10. ababbaaa ⇒ bbaaaaab
11. baaabaaabb ⇒ aababba
12. babaaaabb ⇒ ababba
13. baabaaaabb ⇒ aabbaba
14. abbaabaaaab ⇒ bbaaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb
Length 3:[3/0] baa, [3/1] aab, [3/2] aba, [3/3] aaa, [3/4] abb, [3/5] bba, [3/6] bab
Length 4:[4/0] baaa, [4/1] aaab, [4/2] abba, [4/3] aabb, [4/4] baab, [4/5] abaa, [4/6] aaba
Length 5:[5/0] baaab, [5/1] abbaa, [5/2] aaabb, [5/3] aaaab, [5/4] baaba, [5/5] aabba, [5/6] abaaa
Length 6:[6/0] abbaaa, [6/1] baaaba, [6/2] baaaab, [6/3] baabaa, [6/4] baaabb, [6/5] aaabba, [6/6] aaaabb
Length 7:[7/0] baabaaa, [7/1] baaaabb, [7/2] abaaaab, [7/3] aabaaab, [7/4] babbaaa, [7/5] ababbaa, [7/6] bbaaaba

Considering [length 3 / frequency 0] baa=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaab=ba⟩.