| Back: | ⟨a, b | abaab=ba⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abaab ⇒ ba |
| 2. | ababa ⇒ baaab |
| 3. | aabbaa ⇒ baaaab |
| 4. | baaabab ⇒ abba |
| 5. | baabaaab ⇒ abbaa |
| 6. | abbaaaab ⇒ babaa |
| 7. | baaabba ⇒ abbaaab |
| 8. | aaabbaba ⇒ baaaaabb |
| 9. | abbaaaba ⇒ babaaaab |
| 10. | ababbaaa ⇒ bbaaaaab |
| 11. | baaabaaabb ⇒ aababba |
| 12. | babaaaabb ⇒ ababba |
| 13. | baabaaaabb ⇒ aabbaba |
| 14. | abbaabaaaab ⇒ bbaaa |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 38 | lf:27,lp:6,ls:5,rf:17,rp:4,rs:5,lsrp:2,lprs:3 |
|---|---|---|---|
| [2/1] | aa | 38 | lf:34,lp:2,ls:2,rf:24,rp:2,rs:3 |
| [2/2] | ba | 35 | lf:25,lp:6,ls:4,rf:19,rp:6,rs:5,re:1,lsrp:3,lprs:4 |
| [2/3] | bb | 13 | lf:10,ls:3,rf:9,rp:2,rs:1,a:2 |
| [3/0] | baa | 22 | lf:16,lp:5,ls:1,rf:9,rp:3,rs:2,lsrp:1,lprs:1 |
| [3/1] | aab | 21 | lf:16,lp:1,ls:4,rf:8,rp:2,rs:5,lprs:1 |
| [3/2] | aba | 18 | lf:12,lp:3,ls:3,rf:5,rp:1,rs:1 |
| [3/3] | aaa | 18 | lf:16,lp:1,ls:1,rf:13,rs:1,a:1 |
| [3/4] | abb | 16 | lf:10,lp:3,ls:3,rf:7,rp:3,rs:1,a:2 |
| [3/5] | bba | 8 | lf:7,ls:1,rf:8,rp:2,rs:3,a:2 |
| [3/6] | bab | 7 | lf:5,lp:1,ls:1,rf:5,rp:2,a:1 |
| [4/0] | baaa | 15 | lf:11,lp:3,ls:1,rf:7,rp:3,rs:1,a:1 |
| [4/1] | aaab | 15 | lf:11,lp:1,ls:3,rf:6,rs:5,a:1 |
| [4/2] | abba | 11 | lf:7,lp:3,ls:1,rf:6,rp:3,rs:3,re:1,lsrp:1,a:2 |
| [4/3] | aabb | 10 | lf:6,lp:1,ls:3,rf:2,rp:1,rs:1,lsrp:1,a:3 |
| [4/4] | baab | 7 | lf:4,lp:2,ls:1 |
| [4/5] | abaa | 7 | lf:6,lp:1,rf:2,rs:1 |
| [4/6] | aaba | 7 | lf:6,ls:1,rf:1,rp:1,a:2 |
| [5/0] | baaab | 10 | lf:6,lp:3,ls:1,rf:2,rp:1,rs:2,re:1,lprs:1,a:1 |
| [5/1] | abbaa | 9 | lf:5,lp:3,ls:1,rf:2,rp:2,rs:1,re:1,a:3 |
| [5/2] | aaabb | 9 | lf:5,lp:1,ls:3,rf:1,rs:1,lprs:1,a:3 |
| [5/3] | aaaab | 6 | lf:4,ls:2,rf:4,rs:3,a:6 |
| [5/4] | baaba | 5 | lf:3,lp:2,a:5 |
| [5/5] | aabba | 5 | lf:3,lp:1,ls:1,rf:1,rp:1,a:3 |
| [5/6] | abaaa | 5 | lf:5,rf:1,a:5 |
| [6/0] | abbaaa | 6 | lf:3,lp:2,ls:1,rf:1,rp:1,a:3 |
| [6/1] | baaaba | 6 | lf:3,lp:2,ls:1,a:2 |
| [6/2] | baaaab | 6 | lf:4,ls:2,rf:2,rp:1,rs:2,re:1,a:6 |
| [6/3] | baabaa | 5 | lf:3,lp:2,a:5 |
| [6/4] | baaabb | 4 | lf:2,lp:1,ls:1,a:3 |
| [6/5] | aaabba | 4 | lf:2,lp:1,ls:1,a:3 |
| [6/6] | aaaabb | 4 | lf:2,ls:2,rf:1,rs:1,a:10 |
| [7/0] | baabaaa | 5 | lf:3,lp:2,a:5 |
| [7/1] | baaaabb | 4 | lf:2,ls:2,a:10 |
| [7/2] | abaaaab | 4 | lf:3,ls:1,rf:1,rs:1,a:10 |
| [7/3] | aabaaab | 3 | lf:2,ls:1,a:5 |
| [7/4] | babbaaa | 2 | lf:1,ls:1,a:27 |
| [7/5] | ababbaa | 2 | lf:1,lp:1,a:27 |
| [7/6] | bbaaaba | 2 | lf:1,ls:1,a:18 |
Considering [length 3 / frequency 0] baa=c.
Rewriting system is complete. See ⟨a, b | abaab=ba⟩.