| Back: | ⟨a, b | aababba=baa⟩ |
|---|
Solved by morph:6/0,2/0,4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababba ⇒ baa |
| 2. | aababbbaa ⇒ babaa |
| 3. | aababbbbaa ⇒ babbaa |
| 4. | aababbbabaa ⇒ bababaa |
| 5. | aababbbbbaa ⇒ babbbaa |
| 6. | aababbbabbaa ⇒ bababbaa |
| 7. | aababbbbabaa ⇒ babbabaa |
| ... |
Collecting factors up to length 7 / frequency 3:
| [2/0] | aa | 26 | lf:13,lp:7,ls:6,rf:7,rs:7,lprs:7,lsrs:6 |
|---|---|---|---|
| [2/1] | bb | 18 | lf:18,rf:5 |
| [2/2] | ba | 18 | lf:17,ls:1,rf:16,rp:7,lsrp:1 |
| [3/0] | aab | 14 | lf:7,lp:7 |
| [3/1] | baa | 12 | lf:6,ls:6,rf:7,rp:1,rs:7,re:1,lsrs:6 |
| [3/2] | bbb | 10 | lf:10,rf:1,a:1 |
| [4/0] | aaba | 14 | lf:7,lp:7 |
| [4/1] | babb | 8 | lf:8,rf:4,rp:3 |
| [4/2] | bbaa | 8 | lf:4,ls:4,rf:3,rs:3,lsrs:3,a:1 |
| [5/0] | aabab | 14 | lf:7,lp:7 |
| [5/1] | ababb | 7 | lf:7,rf:1 |
| [5/2] | babbb | 6 | lf:6,rf:1,rp:1,a:1 |
| [6/0] | aababb | 14 | lf:7,lp:7 |
| [6/1] | ababbb | 6 | lf:6,a:1 |
| [6/2] | bbbbaa | 4 | lf:2,ls:2,a:3 |
Considering [length 6 / frequency 0] aababb=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | baa ⇒ ca |
| 2. | aacbca ⇒ caa |
| 3. | aaccacbca ⇒ caaa |
| 4. | bac ⇒ cc |
| 5. | aacbcc ⇒ cac |
| 6. | aaccacbcc ⇒ caac |
| 7. | bcaa ⇒ cacbca |
| 8. | bcac ⇒ cacbcc |
| 9. | aacbbc ⇒ cc |
| 10. | cacbbc ⇒ bcc |
| 11. | babc ⇒ cbc |
| 12. | aacbcbc ⇒ cabc |
| 13. | bcabc ⇒ cacbcbc |
| 14. | aababb ⇒ c |
| 15. | cababb ⇒ bc |
| 16. | aacbbbc ⇒ cbc |
| 17. | cacbbbc ⇒ bcbc |
| 18. | babbc ⇒ cbbc |
| 19. | aacbbbbc ⇒ cbbc |
| 20. | babbbc ⇒ cbbbc |
| ... |
Collecting factors up to length 6 / frequency 5:
| [2/0] | bc | 31 | lf:18,lp:3,ls:10,rf:14,rp:3,rs:9,re:1,lsrp:2,lprs:1,lsrs:8,a:3 |
|---|---|---|---|
| [2/1] | aa | 22 | lf:11,lp:9,ls:2,rf:4,rs:2,lprs:2,a:1 |
| [2/2] | bb | 16 | lf:14,ls:2,rf:4,a:1 |
| [2/3] | ac | 16 | lf:14,ls:2,rf:5,rs:2,a:3 |
| [2/4] | ca | 15 | lf:10,lp:3,ls:2,rf:10,rp:9,rs:2,re:1,lsrp:2,a:2 |
| [3/0] | aac | 16 | lf:8,lp:8,rf:1,rs:1,lprs:1,a:3 |
| [3/1] | bbc | 14 | lf:7,ls:7,rf:3,rs:3,lsrs:3,a:12 |
| [3/2] | bca | 10 | lf:5,lp:3,ls:2,rf:1,rs:1,lprs:1,a:3 |
| [3/3] | acb | 10 | lf:10,rf:3,a:3 |
| [3/4] | bab | 8 | lf:5,lp:3,a:1 |
| [4/0] | aacb | 12 | lf:6,lp:6,a:3 |
| [4/1] | bbbc | 8 | lf:4,ls:4,rf:1,rs:1,lsrs:1,a:17 |
| [4/2] | babb | 8 | lf:4,lp:2,ls:2,a:1 |
| [4/3] | cacb | 6 | lf:4,lp:2,rf:3,rp:3,a:11 |
| [4/4] | acbb | 5 | lf:5,a:13 |
| [5/0] | aacbb | 6 | lf:3,lp:3,a:13 |
| [5/1] | aacbc | 6 | lf:3,lp:3,a:3 |
| [5/2] | cbbbc | 4 | lf:2,ls:2,rf:1,rp:1,rs:1,re:1,a:17 |
| [5/3] | ababb | 4 | lf:2,ls:2,a:1 |
| [5/4] | acbbc | 4 | lf:2,ls:2,a:13 |
Considering [length 2 / frequency 0] bc=d.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | aacda ⇒ caa |
| 2. | cacda ⇒ daa |
| 3. | aacdc ⇒ cac |
| 4. | cacdc ⇒ dac |
| 5. | aacdd ⇒ cad |
| 6. | cacdd ⇒ dad |
| 7. | bc ⇒ d |
| 8. | aacbd ⇒ cc |
| 9. | cacbd ⇒ dc |
| 10. | baa ⇒ ca |
| 11. | bac ⇒ cc |
| 12. | bdc ⇒ dacbd |
| 13. | bad ⇒ cd |
| 14. | aacbbd ⇒ cd |
| 15. | babd ⇒ cbd |
| 16. | aababd ⇒ cc |
| 17. | cababd ⇒ dc |
| 18. | aababb ⇒ c |
| 19. | cababb ⇒ d |
| 20. | dababb ⇒ bd |
| ... |
Collecting factors up to length 6 / frequency 5:
| [2/0] | aa | 16 | lf:8,lp:7,ls:1,rf:2,rs:2,lprs:1,a:1 |
|---|---|---|---|
| [2/1] | bd | 14 | lf:7,lp:1,ls:6,rf:3,rp:1,rs:3,re:1,lprs:1,lsrs:1,a:4 |
| [2/2] | ba | 13 | lf:9,lp:4,a:1 |
| [2/3] | ca | 12 | lf:6,lp:6,rf:4,rp:4,rs:1,re:1,a:3 |
| [2/4] | ab | 11 | lf:11,a:1 |
| [3/0] | aac | 10 | lf:5,lp:5,a:14 |
| [3/1] | cac | 8 | lf:4,lp:4,rf:1,rp:1,rs:1,re:1,a:15 |
| [3/2] | bab | 7 | lf:6,lp:1,a:1 |
| [3/3] | abb | 6 | lf:3,ls:3,a:1 |
| [3/4] | abd | 6 | lf:3,ls:3,a:4 |
| [4/0] | babb | 6 | lf:3,ls:3,a:1 |
| [4/1] | cacd | 6 | lf:3,lp:3,a:15 |
| [4/2] | aacd | 6 | lf:3,lp:3,a:14 |
| [4/3] | abab | 5 | lf:5,a:1 |
| [4/4] | babd | 4 | lf:2,ls:2,a:4 |
| [5/0] | ababb | 6 | lf:3,ls:3,a:1 |
| [5/1] | ababd | 4 | lf:2,ls:2,a:4 |
| [5/2] | cabab | 4 | lf:2,lp:2,a:6 |
| [5/3] | aabab | 4 | lf:2,lp:2,a:1 |
| [5/4] | acbbd | 2 | lf:1,ls:1,a:29 |
Considering [length 4 / frequency 0] babb=e.
Rewriting system is complete. See ⟨a, b | aababba=baa⟩.