Morphocompletion for #2232 ⟨a, b | aababaa=aab⟩

Back:⟨a, b | aababaa=aab⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababaa ⇒ aab
2. aabbabaa ⇒ aabb
3. aabababaa ⇒ aabab
4. aabbbabaa ⇒ aabbb
5. aababbabaa ⇒ aababb
6. aabbababaa ⇒ aabbab
7. aabbbbabaa ⇒ aabbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] baa, [3/1] aab, [3/2] aba, [3/3] bab, [3/4] bba, [3/5] abb, [3/6] bbb
Length 4:[4/0] abaa, [4/1] baba, [4/2] aabb, [4/3] aaba, [4/4] bbab, [4/5] abab, [4/6] abba
Length 5:[5/0] babaa, [5/1] aabab, [5/2] bbaba, [5/3] ababa, [5/4] aabbb, [5/5] aabba, [5/6] abbab
Length 6:[6/0] bbabaa, [6/1] ababaa, [6/2] aabbab, [6/3] aababa, [6/4] abbaba, [6/5] bbbaba, [6/6] bababa
Length 7:[7/0] bbbabaa, [7/1] bababaa, [7/2] abbabaa, [7/3] aabbaba, [7/4] aabbbba, [7/5] aabbbab, [7/6] aababba

Considering [length 5 / frequency 0] babaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aababaa=aab⟩.