Morphocompletion for #220 ⟨a, b | aabba=ab⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aabbb ⇒ abbba
2. ababbb ⇒ abbbba
3. abbabbb ⇒ abbbbba
4. abbbabbb ⇒ abbbbbba
5. abbbbabbb ⇒ abbbbbbba
6. abbbbbabbb ⇒ abbbbbbbba
7. abbbbbbabbb ⇒ abbbbbbbbba
8. abbbbbbbabbb ⇒ abbbbbbbbbba
9. abbbbbbbbabbb ⇒ abbbbbbbbbbba
10. aabba ⇒ ab
11. ababba ⇒ abb
12. abbabba ⇒ abbb
13. abbbabba ⇒ abbbb
14. abbbbabba ⇒ abbbbb
15. abbbbbabba ⇒ abbbbbb
16. abbbbbbabba ⇒ abbbbbbb
17. abbbbbbbabba ⇒ abbbbbbbb
18. abbbbbbbbabba ⇒ abbbbbbbbb
19. abbbbbbbbbabba ⇒ abbbbbbbbbb
20. abbbbbbbbbbabba ⇒ abbbbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb111lf:102,ls:9,rf:109,rs:10
[2/1]ab56lf:38,lp:18,rf:20,rp:20,rs:1,re:1,lprp:18
[2/2]ba40lf:29,ls:11,rf:9,rs:9
[2/3]aa4lf:2,lp:2
[3/0]bbb75lf:66,ls:9,rf:90,rs:9,a:2
[3/1]abb52lf:36,lp:16,rf:19,rp:19,rs:1,re:1,lprp:16
[3/2]bba38lf:27,ls:11,rf:9,rs:9
[3/3]bab18lf:18,a:1
[3/4]aab4lf:2,lp:2
[3/5]aba4lf:2,lp:2,a:1
[4/0]abbb46lf:23,lp:14,ls:9,rf:18,rp:18,rs:1,re:1,lprp:14,lsrp:18,a:2
[4/1]bbbb43lf:43,rf:72,rs:8,a:3
[4/2]abba26lf:13,lp:2,ls:11
[4/3]babb18lf:18,a:1
[4/4]bbab16lf:16,a:2
[4/5]bbba14lf:14,rf:9,rs:9,a:3
[4/6]aabb4lf:2,lp:2
[5/0]bbbbb31lf:31,rf:56,rs:7,a:6
[5/1]abbbb24lf:12,lp:12,rf:16,rp:16,rs:1,re:1,lprp:12,a:3
[5/2]babba20lf:10,ls:10,a:1
[5/3]babbb16lf:8,ls:8,a:5
[5/4]bbabb16lf:16,a:2
[5/5]bbbab14lf:14,a:3
[5/6]bbbba12lf:12,rf:8,rs:8,a:5
[6/0]bbbbbb21lf:21,rf:42,rs:6,a:8
[6/1]abbbbb20lf:10,lp:10,rf:14,rp:14,rs:1,re:1,lprp:10,a:6
[6/2]bbabba18lf:9,ls:9,a:2
[6/3]bbabbb14lf:7,ls:7,a:7
[6/4]bbbabb14lf:14,a:3
[6/5]bbbbab12lf:12,a:6
[6/6]bbbbba10lf:10,rf:7,rs:7,a:7
[7/0]bbbabba16lf:8,ls:8,a:3
[7/1]abbbbbb16lf:8,lp:8,rf:12,rp:12,rs:1,re:1,lprp:8,a:8
[7/2]bbbbbbb13lf:13,rf:30,rs:5,a:9
[7/3]bbbabbb12lf:6,ls:6,a:8
[7/4]bbbbabb12lf:12,a:6
[7/5]bbbbbab10lf:10,a:10
[7/6]bbbbbba8lf:8,rf:6,rs:6,a:8

Considering [length 7 / frequency 0] bbbabba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabba=ab⟩.