Morphocompletion for #220 ⟨a, b | aabba=ab

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aabbb ⇒ abbba
2. ababbb ⇒ abbbba
3. abbabbb ⇒ abbbbba
4. abbbabbb ⇒ abbbbbba
5. abbbbabbb ⇒ abbbbbbba
6. abbbbbabbb ⇒ abbbbbbbba
7. abbbbbbabbb ⇒ abbbbbbbbba
8. abbbbbbbabbb ⇒ abbbbbbbbbba
9. abbbbbbbbabbb ⇒ abbbbbbbbbbba
10. aabba ⇒ ab
11. ababba ⇒ abb
12. abbabba ⇒ abbb
13. abbbabba ⇒ abbbb
14. abbbbabba ⇒ abbbbb
15. abbbbbabba ⇒ abbbbbb
16. abbbbbbabba ⇒ abbbbbbb
17. abbbbbbbabba ⇒ abbbbbbbb
18. abbbbbbbbabba ⇒ abbbbbbbbb
19. abbbbbbbbbabba ⇒ abbbbbbbbbb
20. abbbbbbbbbbabba ⇒ abbbbbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] bbb, [3/1] abb, [3/2] bba, [3/3] bab, [3/4] aab, [3/5] aba
Length 4:[4/0] abbb, [4/1] bbbb, [4/2] abba, [4/3] babb, [4/4] bbab, [4/5] bbba, [4/6] aabb
Length 5:[5/0] bbbbb, [5/1] abbbb, [5/2] babba, [5/3] babbb, [5/4] bbabb, [5/5] bbbab, [5/6] bbbba
Length 6:[6/0] bbbbbb, [6/1] abbbbb, [6/2] bbabba, [6/3] bbabbb, [6/4] bbbabb, [6/5] bbbbab, [6/6] bbbbba
Length 7:[7/0] bbbabba, [7/1] abbbbbb, [7/2] bbbbbbb, [7/3] bbbabbb, [7/4] bbbbabb, [7/5] bbbbbab, [7/6] bbbbbba

Considering [length 7 / frequency 0] bbbabba=c.

Step 2

Rewriting system is complete. See a, b | aabba=ab.