Morphocompletion for #2187 ⟨a, b | aaabbaa=baa⟩

Back:⟨a, b | aaabbaa=baa⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbaa ⇒ baa
2. aaabbbaa ⇒ bbaa
3. aaabbabaa ⇒ babaa
4. aaabbbbaa ⇒ bbbaa
5. aaabbabbaa ⇒ babbaa
6. aaabbbabaa ⇒ bbabaa
7. aaabbbbbaa ⇒ bbbbaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] baa, [3/1] aaa, [3/2] bba, [3/3] abb, [3/4] bbb, [3/5] aab, [3/6] bab
Length 4:[4/0] aaab, [4/1] bbaa, [4/2] aabb, [4/3] bbba, [4/4] abbb, [4/5] abba, [4/6] abaa
Length 5:[5/0] aaabb, [5/1] bbbaa, [5/2] babaa, [5/3] abbaa, [5/4] aabbb, [5/5] aabba, [5/6] bbbba
Length 6:[6/0] aaabbb, [6/1] aaabba, [6/2] bbbbaa, [6/3] bbabaa, [6/4] babbaa, [6/5] abbbaa, [6/6] aabbbb
Length 7:[7/0] aaabbbb, [7/1] aaabbba, [7/2] aaabbab, [7/3] bbbbbaa, [7/4] bbbabaa, [7/5] bbabbaa, [7/6] abbbbaa

Considering [length 5 / frequency 0] aaabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbaa=baa⟩.