Morphocompletion for #2184 ⟨a, b | aaabbaa=aab⟩

Back:⟨a, b | aaabbaa=aab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbaa ⇒ aab
2. aababbaa ⇒ aabb
3. aabaabbaa ⇒ aabab
4. aaabbab ⇒ aabbbaa
5. aabbbaabaa ⇒ aaabbb
6. aabbabbaa ⇒ aabbb
7. aabbaabbaa ⇒ aabbab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aab, [3/1] baa, [3/2] abb, [3/3] bba, [3/4] bab, [3/5] aaa, [3/6] aba
Length 4:[4/0] bbaa, [4/1] aabb, [4/2] abba, [4/3] aaba, [4/4] aaab, [4/5] bbab, [4/6] baab
Length 5:[5/0] abbaa, [5/1] aabba, [5/2] aaabb, [5/3] aabaa, [5/4] abbab, [5/5] aabbb, [5/6] baabb
Length 6:[6/0] aabbaa, [6/1] aabbab, [6/2] babbaa, [6/3] aaabba, [6/4] aababb, [6/5] aabbba, [6/6] baabba
Length 7:[7/0] baabbaa, [7/1] aabbabb, [7/2] bbabbaa, [7/3] aabaabb, [7/4] aababba, [7/5] aabbaab, [7/6] aabbbaa

Considering [length 4 / frequency 0] bbaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbaa=aab⟩.