Morphocompletion for #2184 ⟨a, b | aaabbaa=aab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbaa ⇒ aab
2. aababbaa ⇒ aabb
3. aabaabbaa ⇒ aabab
4. aaabbab ⇒ aabbbaa
5. aabbbaabaa ⇒ aaabbb
6. aabbabbaa ⇒ aabbb
7. aabbaabbaa ⇒ aabbab
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa31lf:18,lp:7,ls:6,rf:9,rp:7,rs:1,lprp:7,lsrp:6,lprs:1
[2/1]ab14lf:13,ls:1,rf:9,rs:3
[2/2]ba12lf:12,rf:3
[2/3]bb10lf:10,rf:8,rs:3
[3/0]aab15lf:10,lp:5,rf:7,rp:6,rs:1,re:1,lprp:4
[3/1]baa15lf:9,ls:6,rf:1,rs:1
[3/2]abb9lf:9,rf:5,rs:1
[3/3]bba9lf:9,rf:2
[3/4]bab4lf:3,ls:1,rf:2,rs:2,a:1
[3/5]aaa4lf:2,lp:2,rf:1,rp:1
[3/6]aba3lf:3,rf:1,a:1
[4/0]bbaa12lf:7,ls:5,rf:1,rs:1
[4/1]aabb10lf:7,lp:3,rf:5,rp:4,rs:1,re:1,lprp:2
[4/2]abba8lf:8,rf:1
[4/3]aaba5lf:3,lp:2,rf:1,rp:1,lprp:1,a:1
[4/4]aaab4lf:2,lp:2,rf:1,rp:1
[4/5]bbab3lf:2,ls:1,rf:1,rs:1,a:3
[4/6]baab3lf:3,a:2
[5/0]abbaa11lf:6,ls:5
[5/1]aabba8lf:6,lp:2,rf:1,rp:1,lprp:1
[5/2]aaabb4lf:2,lp:2,rf:1,rp:1
[5/3]aabaa4lf:2,lp:1,ls:1,a:2
[5/4]abbab3lf:2,ls:1,rf:1,rs:1,a:3
[5/5]aabbb2lf:1,lp:1,rf:3,rp:2,rs:2,re:1,lprs:1,a:3
[5/6]baabb2lf:2,a:2
[6/0]aabbaa8lf:4,lp:1,ls:3
[6/1]aabbab4lf:2,lp:1,ls:1,rf:1,rp:1,rs:1,re:1,a:3
[6/2]babbaa4lf:2,ls:2,a:1
[6/3]aaabba4lf:2,lp:2
[6/4]aababb2lf:1,lp:1,a:1
[6/5]aabbba2lf:1,lp:1,rf:1,rp:1,a:25
[6/6]baabba2lf:2,a:2
[7/0]baabbaa4lf:2,ls:2,a:2
[7/1]aabbabb2lf:1,lp:1,a:3
[7/2]bbabbaa2lf:1,ls:1,a:3
[7/3]aabaabb2lf:1,lp:1,a:2
[7/4]aababba2lf:1,lp:1,a:1
[7/5]aabbaab2lf:1,lp:1,a:5
[7/6]aabbbaa2lf:1,lp:1,rf:1,rp:1,rs:1,re:1,a:25

Considering [length 4 / frequency 0] bbaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbaa=aab⟩.