Morphocompletion for #2171 ⟨a, b | aaababa=baa⟩

Back:⟨a, b | aaababa=baa⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaababa ⇒ baa
2. aaababbaa ⇒ babaa
3. aaababbbaa ⇒ babbaa
4. aaababbabaa ⇒ bababaa
5. aaababbbbaa ⇒ babbbaa
6. aaababbabbaa ⇒ bababbaa
7. aaababbbabaa ⇒ babbabaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aaa, [3/1] baa, [3/2] aba, [3/3] bab, [3/4] bba, [3/5] abb, [3/6] aab
Length 4:[4/0] aaab, [4/1] bbaa, [4/2] babb, [4/3] abab, [4/4] aaba, [4/5] baba, [4/6] abba
Length 5:[5/0] aaaba, [5/1] aabab, [5/2] ababb, [5/3] bbbaa, [5/4] babba, [5/5] babaa, [5/6] abbaa
Length 6:[6/0] aaabab, [6/1] aababb, [6/2] bbabaa, [6/3] babbaa, [6/4] ababbb, [6/5] ababba, [6/6] bbbbaa
Length 7:[7/0] aaababb, [7/1] aababbb, [7/2] aababba, [7/3] bbbabaa, [7/4] bbabbaa, [7/5] babbbaa, [7/6] abbbbaa

Considering [length 6 / frequency 0] aaabab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaababa=baa⟩.