| Back: | ⟨a, b | abbbaaab=ba⟩ |
|---|
Solved by morph:4/3,3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: arenaTotalLimit
| # | Rule |
|---|---|
| 1. | abbbaaab ⇒ ba |
| 2. | babbaaab ⇒ abbbaaba |
| 3. | abbbaaaabbbaaba ⇒ baabbaaab |
| 4. | baabbaaabbbbaaab ⇒ abbbaaaabbbaabba |
| 5. | babbaaaabbbaaba ⇒ abbbaabaabbaaab |
| 6. | abbbaaaabbbaaaabbbaabba ⇒ baaabbaaabbbbaaab |
| 7. | baaabbaaabbbbaaabbbbaaab ⇒ abbbaaaabbbaaaabbbaabbba |
| 8. | baabbaaabbbbaaaabbbaaba ⇒ abbbaaaabbbaabbaabbaaab |
| 9. | babaaabbbbaaabbbbaaabaab ⇒ abbabbbaaaabbbaaaabbbaba |
| 10. | babbaaaabbbaaaabbbaabba ⇒ abbbaabaaabbaaabbbbaaab |
| 11. | abbabbbaaaabbbaaaabbbaabbba ⇒ babaaabbbbaaabbbbaaab |
| ... |
Collecting factors up to length 7 / frequency 4:
| [2/0] | aa | 60 | lf:60,rf:51 |
|---|---|---|---|
| [2/1] | bb | 55 | lf:55,rf:48 |
| [2/2] | ba | 54 | lf:41,lp:7,ls:6,rf:35,rp:4,rs:5,re:1,lsrp:3,lprs:4 |
| [2/3] | ab | 48 | lf:39,lp:4,ls:5,rf:37,rp:7,rs:6,lsrp:4,lprs:3 |
| [3/0] | aab | 35 | lf:30,ls:5,rf:27,rs:6 |
| [3/1] | baa | 33 | lf:30,lp:3,rf:27,rp:2 |
| [3/2] | abb | 33 | lf:29,lp:4,rf:26,rp:7 |
| [3/3] | bba | 32 | lf:29,ls:3,rf:26,rs:2 |
| [4/0] | aaab | 25 | lf:21,ls:4,rf:18,rs:6 |
| [4/1] | bbaa | 25 | lf:25,rf:22 |
| [4/2] | abbb | 23 | lf:20,lp:3,rf:18,rp:6 |
| [4/3] | baaa | 22 | lf:21,lp:1,rf:18,rp:1 |
| [5/0] | bbaaa | 19 | lf:19,rf:15 |
| [5/1] | bbbaa | 19 | lf:19,rf:16 |
| [5/2] | abbba | 18 | lf:14,lp:3,ls:1,rf:14,rp:6,rs:1 |
| [5/3] | baaab | 17 | lf:12,lp:1,ls:4,rf:12,rp:1,rs:6 |
| [6/0] | abbbaa | 16 | lf:13,lp:3,rf:12,rp:6 |
| [6/1] | aaabbb | 15 | lf:15,rf:10,a:2 |
| [6/2] | bbaaab | 14 | lf:10,ls:4,rf:9,rs:6 |
| [6/3] | bbbaaa | 13 | lf:13,rf:10 |
Considering [length 4 / frequency 3] baaa=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: lhsLimit
| # | Rule |
|---|---|
| 1. | ca ⇒ abbcc |
| 2. | ba ⇒ abbcb |
| 3. | abbcabbcabbcb ⇒ c |
| ... |
Collecting factors up to length 6 / frequency 7:
| [2/0] | ab | 4 | lf:3,lp:1,rf:2,rp:2,a:2 |
|---|---|---|---|
| [2/1] | bb | 3 | lf:3,rf:2,a:2 |
| [2/2] | bc | 3 | lf:3,rf:2,a:2 |
| [2/3] | ca | 2 | lf:2,a:3 |
| [2/4] | cb | 2 | lf:1,ls:1,rf:1,rs:1,a:2 |
| [2/5] | cc | 0 | rf:1,rs:1,a:5 |
| [3/0] | abb | 4 | lf:3,lp:1,rf:2,rp:2,a:2 |
| [3/1] | bbc | 3 | lf:3,rf:2,a:2 |
| [3/2] | bca | 2 | lf:2,a:3 |
| [3/3] | cab | 2 | lf:2,a:3 |
| [3/4] | bcb | 2 | lf:1,ls:1,rf:1,rs:1,a:2 |
| [3/5] | bcc | 0 | rf:1,rs:1,a:5 |
| [4/0] | abbc | 4 | lf:3,lp:1,rf:2,rp:2,a:2 |
| [4/1] | bbca | 2 | lf:2,a:3 |
| [4/2] | bcab | 2 | lf:2,a:3 |
| [4/3] | cabb | 2 | lf:2,a:3 |
| [4/4] | bbcb | 2 | lf:1,ls:1,rf:1,rs:1,a:2 |
| [4/5] | bbcc | 0 | rf:1,rs:1,a:5 |
| [5/0] | abbca | 3 | lf:2,lp:1,a:3 |
| [5/1] | bbcab | 2 | lf:2,a:3 |
| [5/2] | bcabb | 2 | lf:2,a:3 |
| [5/3] | cabbc | 2 | lf:2,a:3 |
| [5/4] | abbcb | 2 | lf:1,ls:1,rf:1,rp:1,rs:1,re:1,a:2 |
| [5/5] | abbcc | 0 | rf:1,rp:1,rs:1,re:1,a:5 |
Considering [length 3 / frequency 0] abb=d.
Rewriting system is complete. See ⟨a, b | abbbaaab=ba⟩.