Morphocompletion for #2087 ⟨a, b | abbbaaab=ba

Solved by morph:3/2,5/6. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abbbaaab ⇒ ba
2. babbaaab ⇒ abbbaaba
3. abbbaaaabbbaaba ⇒ baabbaaab
4. baabbaaabbbbaaab ⇒ abbbaaaabbbaabba
5. babbaaaabbbaaba ⇒ abbbaabaabbaaab
6. abbbaaaabbbaaaabbbaabba ⇒ baaabbaaabbbbaaab
7. baaabbaaabbbbaaabbbbaaab ⇒ abbbaaaabbbaaaabbbaabbba
8. baabbaaabbbbaaaabbbaaba ⇒ abbbaaaabbbaabbaabbaaab
9. babaaabbbbaaabbbbaaabaab ⇒ abbabbbaaaabbbaaaabbbaba
10. babbaaaabbbaaaabbbaabba ⇒ abbbaabaaabbaaabbbbaaab
11. abbabbbaaaabbbaaaabbbaabbba ⇒ babaaabbbbaaabbbbaaab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] aab, [3/1] baa, [3/2] abb, [3/3] bba
Length 4:[4/0] aaab, [4/1] bbaa, [4/2] abbb, [4/3] baaa
Length 5:[5/0] bbaaa, [5/1] bbbaa, [5/2] abbba, [5/3] baaab
Length 6:[6/0] abbbaa, [6/1] aaabbb, [6/2] bbaaab, [6/3] bbbaaa

Considering [length 3 / frequency 2] abb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abb ⇒ c
2. cbaac ⇒ bab
3. cbaabc ⇒ bcaacb
4. cbaaab ⇒ ba
5. cbaaba ⇒ bcaaab
6. ccaacbbaac ⇒ abcbacab
7. ccaacbbaabc ⇒ abcbaccaacb
8. bcaacbbaac ⇒ cbacab
9. bcaacbbaabc ⇒ cbaccaacb
10. cacaacbbaacb ⇒ abcbaaacbacc
11. ccaacbbaaab ⇒ abcbaca
12. ccaacbbaaba ⇒ abcbaccaaab
13. bacaacbbaacb ⇒ cbaaacbacc
14. bcaacbbaaab ⇒ cbaca
15. bcaacbbaaba ⇒ cbaccaaab
16. cbaaacbacab ⇒ bacaacbbaac
17. cacaacbbaaab ⇒ abcbaaacbaca
18. bacaacbbaaab ⇒ cbaaacbaca
19. cbaaacbaccaac ⇒ bacaacbbaabab
20. cbaaacbaccaaab ⇒ bacaacbbaaba
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] cb, [2/2] ba, [2/3] ac, [2/4] ab, [2/5] ca, [2/6] bb
Length 3:[3/0] aac, [3/1] baa, [3/2] acb, [3/3] aab, [3/4] cba, [3/5] caa, [3/6] bba
Length 4:[4/0] aacb, [4/1] cbaa, [4/2] caac, [4/3] aaab, [4/4] bbaa, [4/5] cbba, [4/6] acbb
Length 5:[5/0] cbbaa, [5/1] caacb, [5/2] acbba, [5/3] aacbb, [5/4] baaab, [5/5] ccaac, [5/6] cbaaa

Considering [length 5 / frequency 6] cbaaa=d.

Step 3

Rewriting system is complete. See a, b | abbbaaab=ba.