| Back: | ⟨a, b | abbbaaab=aa⟩ |
|---|
Solved by morph:4/3. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abbbaaaa ⇒ aabbaaab |
| 2. | abbbaaab ⇒ aa |
| 3. | aaaaabbbbaaaa ⇒ aaaaababbaaab |
| 4. | aaaaabbbbaaab ⇒ aaaaaba |
| 5. | aabaaabbbbaaaa ⇒ aabaaababbaaab |
| 6. | aabaaabbbbaaab ⇒ aabaaaba |
| 7. | aabbaaabbbbaaab ⇒ aabbaaaba |
| 8. | aabbaaababbbbaaab ⇒ aabbaaababa |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 48 | lf:39,lp:6,ls:3,rf:28,rp:8,rs:1,re:1,lprp:6,lsrp:3 |
|---|---|---|---|
| [2/1] | ab | 25 | lf:18,lp:2,ls:5,rf:17,rs:3,lprs:1 |
| [2/2] | bb | 24 | lf:24,rf:5 |
| [2/3] | ba | 13 | lf:13,rf:14,rs:4 |
| [3/0] | aaa | 26 | lf:21,lp:2,ls:3,rf:13,rp:2,lprp:2,lsrp:1 |
| [3/1] | aab | 24 | lf:15,lp:4,ls:5,rf:14,rp:5,rs:3,lprp:4,lsrp:3,lprs:1 |
| [3/2] | bbb | 14 | lf:14 |
| [3/3] | abb | 12 | lf:10,lp:2,rf:5 |
| [3/4] | baa | 12 | lf:12,rf:7 |
| [3/5] | bba | 10 | lf:10,rf:5 |
| [3/6] | aba | 3 | lf:3,rf:9,rs:4,a:2 |
| [4/0] | aaab | 16 | lf:11,ls:5,rf:9,rs:3 |
| [4/1] | baaa | 12 | lf:12,rf:7 |
| [4/2] | aaaa | 12 | lf:7,lp:2,ls:3,rf:4,rp:2,lprp:2,lsrp:1,a:1 |
| [4/3] | abbb | 10 | lf:8,lp:2 |
| [4/4] | bbaa | 10 | lf:10,rf:5 |
| [4/5] | aabb | 9 | lf:7,lp:2,rf:3,rp:3,lprp:2,a:1 |
| [4/6] | bbba | 8 | lf:8 |
| [5/0] | baaab | 14 | lf:9,ls:5,rf:7,rs:3 |
| [5/1] | bbaaa | 10 | lf:10,rf:5 |
| [5/2] | bbbaa | 8 | lf:8 |
| [5/3] | bbbba | 6 | lf:6,a:2 |
| [5/4] | abbbb | 6 | lf:6,a:2 |
| [5/5] | baaaa | 6 | lf:3,ls:3,a:1 |
| [5/6] | aabbb | 5 | lf:5,a:2 |
| [6/0] | bbaaab | 12 | lf:7,ls:5,rf:5,rs:3 |
| [6/1] | bbbaaa | 8 | lf:8 |
| [6/2] | bbbbaa | 6 | lf:6,a:2 |
| [6/3] | abbbba | 6 | lf:6,a:2 |
| [6/4] | bbaaaa | 6 | lf:3,ls:3,a:1 |
| [6/5] | aabbbb | 5 | lf:5,a:2 |
| [6/6] | aaabbb | 5 | lf:5,a:2 |
| [7/0] | bbbaaab | 10 | lf:5,ls:5 |
| [7/1] | bbbbaaa | 6 | lf:6,a:2 |
| [7/2] | abbbbaa | 6 | lf:6,a:2 |
| [7/3] | bbbaaaa | 6 | lf:3,ls:3,a:1 |
| [7/4] | aabbbba | 5 | lf:5,a:2 |
| [7/5] | aaabbbb | 5 | lf:5,a:2 |
| [7/6] | abbbaaa | 4 | lf:2,lp:2 |
Considering [length 4 / frequency 3] abbb=c.
Rewriting system is complete. See ⟨a, b | abbbaaab=aa⟩.