| Back: | ⟨a, b | abbaabba=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | ababba ⇒ abbaab |
| 2. | abbbabaa ⇒ ab |
| 3. | abbabba ⇒ abbbaab |
| 4. | abbaabb ⇒ abbbaba |
| 5. | abbbbabaa ⇒ abb |
| 6. | abbbabba ⇒ abbbbaab |
| 7. | abbbaabb ⇒ abbbbaba |
| 8. | abbbbbabaa ⇒ abbb |
| 9. | abbbbaabba ⇒ abbb |
| 10. | abbbabababa ⇒ ababb |
| 11. | abbbababaab ⇒ abbba |
| 12. | abbbbbbabaa ⇒ abbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 41 | lf:28,lp:12,ls:1,rf:18,rp:12,rs:4,re:1,lprp:12,lsrp:1,lprs:4,a:1 |
|---|---|---|---|
| [2/1] | bb | 35 | lf:33,ls:2,rf:22,rs:5,a:1 |
| [2/2] | ba | 30 | lf:25,ls:5,rf:9,rs:3,a:1 |
| [2/3] | aa | 12 | lf:8,ls:4,rf:3,a:1 |
| [3/0] | abb | 30 | lf:17,lp:11,ls:2,rf:11,rp:10,rs:2,re:1,lprp:9,lsrp:2,lprs:2,a:1 |
| [3/1] | bba | 19 | lf:15,ls:4,rf:6,rs:1,a:1 |
| [3/2] | bbb | 16 | lf:16,rf:11,rs:3,a:3 |
| [3/3] | bab | 12 | lf:12,rf:3,a:1 |
| [3/4] | aba | 12 | lf:10,lp:1,ls:1,rf:3,rp:1,rs:2,lsrp:1,a:1 |
| [3/5] | baa | 12 | lf:8,ls:4,rf:3,a:1 |
| [3/6] | aab | 5 | lf:4,ls:1,rf:3,rs:3,a:1 |
| [4/0] | abbb | 18 | lf:9,lp:9,rf:8,rp:8,rs:2,re:2,lprp:6,lprs:2,a:3 |
| [4/1] | abba | 12 | lf:6,lp:2,ls:4,rf:1,rp:1,lsrp:1,a:1 |
| [4/2] | baba | 10 | lf:9,ls:1,rf:2,rs:2,a:19 |
| [4/3] | bbba | 9 | lf:9,rf:5,rs:1,a:3 |
| [4/4] | abaa | 9 | lf:5,ls:4,a:25 |
| [4/5] | bbab | 8 | lf:8,rf:2,a:3 |
| [4/6] | bbbb | 7 | lf:7,rf:3,rs:1,a:5 |
| [5/0] | abbba | 10 | lf:5,lp:5,rf:3,rp:3,rs:1,re:1,lprp:1,lprs:1,a:3 |
| [5/1] | babaa | 9 | lf:5,ls:4,a:25 |
| [5/2] | abbbb | 8 | lf:4,lp:4,rf:3,rp:3,rs:1,re:1,lprp:1,lprs:1,a:5 |
| [5/3] | bbbab | 7 | lf:7,rf:2,a:6 |
| [5/4] | babba | 6 | lf:3,ls:3,a:1 |
| [5/5] | bbaba | 6 | lf:6,rf:2,rs:2,a:19 |
| [5/6] | baabb | 5 | lf:3,ls:2,a:5 |
| [6/0] | abbbab | 8 | lf:4,lp:4,rf:1,rp:1,a:6 |
| [6/1] | bbabaa | 8 | lf:4,ls:4,a:25 |
| [6/2] | bbbaba | 6 | lf:6,rf:2,rs:2,a:19 |
| [6/3] | bbaabb | 5 | lf:3,ls:2,a:5 |
| [6/4] | abbbbb | 4 | lf:2,lp:2,a:34 |
| [6/5] | abbbba | 4 | lf:2,lp:2,rf:2,rp:2,a:5 |
| [6/6] | bbabba | 4 | lf:2,ls:2,a:3 |
| [7/0] | bbbabaa | 8 | lf:4,ls:4,a:25 |
| [7/1] | abbbaba | 6 | lf:3,lp:3,rf:1,rp:1,rs:1,re:1,a:19 |
| [7/2] | bbbaabb | 3 | lf:2,ls:1,a:5 |
| [7/3] | bbbbaba | 3 | lf:3,rf:1,rs:1,a:32 |
| [7/4] | abbbbbb | 2 | lf:1,lp:1,a:35 |
| [7/5] | bbbbbab | 2 | lf:2,a:34 |
| [7/6] | abbbabb | 2 | lf:1,lp:1,a:6 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | abbaabba=ab⟩.