Morphocompletion for #2076 ⟨a, b | abbaabba=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababba ⇒ abbaab
2. abbbabaa ⇒ ab
3. abbabba ⇒ abbbaab
4. abbaabb ⇒ abbbaba
5. abbbbabaa ⇒ abb
6. abbbabba ⇒ abbbbaab
7. abbbaabb ⇒ abbbbaba
8. abbbbbabaa ⇒ abbb
9. abbbbaabba ⇒ abbb
10. abbbabababa ⇒ ababb
11. abbbababaab ⇒ abbba
12. abbbbbbabaa ⇒ abbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa
Length 3:[3/0] abb, [3/1] bba, [3/2] bbb, [3/3] bab, [3/4] aba, [3/5] baa, [3/6] aab
Length 4:[4/0] abbb, [4/1] abba, [4/2] baba, [4/3] bbba, [4/4] abaa, [4/5] bbab, [4/6] bbbb
Length 5:[5/0] abbba, [5/1] babaa, [5/2] abbbb, [5/3] bbbab, [5/4] babba, [5/5] bbaba, [5/6] baabb
Length 6:[6/0] abbbab, [6/1] bbabaa, [6/2] bbbaba, [6/3] bbaabb, [6/4] abbbbb, [6/5] abbbba, [6/6] bbabba
Length 7:[7/0] bbbabaa, [7/1] abbbaba, [7/2] bbbaabb, [7/3] bbbbaba, [7/4] abbbbbb, [7/5] bbbbbab, [7/6] abbbabb

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | abbaabba=ab.