Morphocompletion for #2073 ⟨a, b | abbaaaab=ba⟩

Solved by morph:5/1,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abbaaaab ⇒ ba
2. babaaaab ⇒ abbaaaba
3. abbaaaaabbaaaba ⇒ baabaaaab
4. baabaaaabbbaaaab ⇒ abbaaaaabbaaabba
5. babaaaaabbaaaba ⇒ abbaaabaabaaaab
6. baaabaaaabbbaaaabaaab ⇒ abbaaaaabbaaaaabbaaba
7. abbaaaaabbaaaaabbaaabba ⇒ baaabaaaabbbaaaab
8. baaabaaaabbbaaaabbbaaaab ⇒ abbaaaaabbaaaaabbaaabbba
9. baabaaaabbbaaaaabbaaaba ⇒ abbaaaaabbaaabbaabaaaab
10. babaaaaabbaaaaabbaaabba ⇒ abbaaabaaabaaaabbbaaaab
11. abbaaaaabbaaaaabbaaaaabbaaba ⇒ baaaabaaaabbbaaaabaaab
...

Collecting factors up to length 7 / frequency 4:

[2/0]aa89lf:89,rf:76
[2/1]ba53lf:40,lp:7,ls:6,rf:34,rp:4,rs:5,re:1,lsrp:3,lprs:4
[2/2]ab47lf:38,lp:4,ls:5,rf:36,rp:7,rs:6,lsrp:4,lprs:3
[2/3]bb26lf:26,rf:23
[3/0]aaa58lf:58,rf:47
[3/1]aab36lf:31,ls:5,rf:29,rs:6
[3/2]baa35lf:31,lp:4,rf:29,rp:3
[3/3]abb25lf:21,lp:4,rf:19,rp:7
[4/0]aaab33lf:28,ls:5,rf:25,rs:6
[4/1]aaaa30lf:30,rf:22
[4/2]baaa30lf:28,lp:2,rf:25,rp:2
[4/3]abba22lf:16,lp:4,ls:2,rf:15,rp:7,rs:1,lsrp:1
[5/0]aaaab24lf:20,ls:4,rf:16,rs:5
[5/1]baaaa20lf:20,rf:16,rp:1
[5/2]bbaaa18lf:18,rf:15
[5/3]abbaa18lf:14,lp:4,rf:14,rp:7
[6/0]abbaaa17lf:13,lp:4,rf:12,rp:7
[6/1]aaaabb15lf:15,rf:9,a:2
[6/2]baaaab14lf:10,ls:4,rf:10,rp:1,rs:5
[6/3]aaabba14lf:12,ls:2,rf:8,rs:1,a:2

Considering [length 5 / frequency 1] baaaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: lhsLimit

#Rule
1. ca ⇒ abcc
2. ba ⇒ abcb
3. abcabcabcabcb ⇒ c
...

Collecting factors up to length 6 / frequency 7:

[2/0]ab5lf:4,lp:1,rf:2,rp:2,a:2
[2/1]bc4lf:4,rf:2,a:2
[2/2]ca3lf:3,a:3
[2/3]cb2lf:1,ls:1,rf:1,rs:1,a:2
[2/4]cc0rf:1,rs:1,a:5
[3/0]abc5lf:4,lp:1,rf:2,rp:2,a:2
[3/1]bca3lf:3,a:3
[3/2]cab3lf:3,a:3
[3/3]bcb2lf:1,ls:1,rf:1,rs:1,a:2
[3/4]bcc0rf:1,rs:1,a:5
[4/0]abca4lf:3,lp:1,a:3
[4/1]bcab3lf:3,a:3
[4/2]cabc3lf:3,a:3
[4/3]abcb2lf:1,ls:1,rf:1,rp:1,rs:1,re:1,a:2
[4/4]abcc0rf:1,rp:1,rs:1,re:1,a:5
[5/0]abcab4lf:3,lp:1,a:3
[5/1]bcabc3lf:3,a:3
[5/2]cabca2lf:2,a:3
[5/3]cabcb2lf:1,ls:1,a:3

Considering [length 2 / frequency 0] ab=d.

Step 3

Rewriting system is complete. See ⟨a, b | abbaaaab=ba⟩.