| Back: | ⟨a, b | abbaaaab=ba⟩ |
|---|
Solved by morph:5/1,2/4. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: arenaTotalLimit
| # | Rule |
|---|---|
| 1. | abbaaaab ⇒ ba |
| 2. | babaaaab ⇒ abbaaaba |
| 3. | abbaaaaabbaaaba ⇒ baabaaaab |
| 4. | baabaaaabbbaaaab ⇒ abbaaaaabbaaabba |
| 5. | babaaaaabbaaaba ⇒ abbaaabaabaaaab |
| 6. | baaabaaaabbbaaaabaaab ⇒ abbaaaaabbaaaaabbaaba |
| 7. | abbaaaaabbaaaaabbaaabba ⇒ baaabaaaabbbaaaab |
| 8. | baaabaaaabbbaaaabbbaaaab ⇒ abbaaaaabbaaaaabbaaabbba |
| 9. | baabaaaabbbaaaaabbaaaba ⇒ abbaaaaabbaaabbaabaaaab |
| 10. | babaaaaabbaaaaabbaaabba ⇒ abbaaabaaabaaaabbbaaaab |
| 11. | abbaaaaabbaaaaabbaaaaabbaaba ⇒ baaaabaaaabbbaaaabaaab |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb |
|---|---|
| Length 3: | [3/0] aaa, [3/1] aab, [3/2] baa, [3/3] abb |
| Length 4: | [4/0] aaab, [4/1] aaaa, [4/2] baaa, [4/3] abba |
| Length 5: | [5/0] aaaab, [5/1] baaaa, [5/2] bbaaa, [5/3] abbaa |
| Length 6: | [6/0] abbaaa, [6/1] aaaabb, [6/2] baaaab, [6/3] aaabba |
Considering [length 5 / frequency 1] baaaa=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: wordLimit
| # | Rule |
|---|---|
| 1. | ca ⇒ abcc |
| 2. | ba ⇒ abcb |
| 3. | aaaabcbbccbcbbcbbccbccbcbbccbcbbcbbccbcbbcbbccbccbcbbccbccbcbbccbcbbcbbccbccbcbbccbcbbcbbccbcbbcbbccbccbcbbccbcbbcbbccbcbbcbbccbccbcbbccbccbcbbccbcbbcbbccbccbcbbccbcb ⇒ bc |
| 4. | abcabcabcabcb ⇒ c |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] bc, [2/1] cb, [2/2] bb, [2/3] cc, [2/4] ab, [2/5] aa, [2/6] ca |
|---|---|
| Length 3: | [3/0] bcb, [3/1] cbb, [3/2] bbc, [3/3] ccb, [3/4] cbc, [3/5] bcc, [3/6] abc |
| Length 4: | [4/0] bcbb, [4/1] cbbc, [4/2] bccb, [4/3] ccbc, [4/4] cbcb, [4/5] bbcc, [4/6] bbcb |
| Length 5: | [5/0] bcbbc, [5/1] bccbc, [5/2] ccbcb, [5/3] bbccb, [5/4] cbbcc, [5/5] cbcbb, [5/6] bbcbb |
Considering [length 2 / frequency 4] ab=d.
Rewriting system is complete. See ⟨a, b | abbaaaab=ba⟩.