Morphocompletion for #2068 ⟨a, b | ababbbba=ab

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbbbaa ⇒ ab
2. ababbbb ⇒ abbbbba
3. abbbbbbaa ⇒ abb
4. abbbbbabaa ⇒ abab
5. abbabbbb ⇒ abbbbbba
6. abbbbbbbaa ⇒ abbb
7. abbbbbbabaa ⇒ abbab
8. abbbbbabbaa ⇒ ababb
9. abbbbbababaa ⇒ ababab
10. abbbbbbbbaa ⇒ abbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] bbb, [3/1] abb, [3/2] baa, [3/3] bba, [3/4] bab, [3/5] aba
Length 4:[4/0] bbbb, [4/1] abbb, [4/2] bbaa, [4/3] bbba, [4/4] abaa, [4/5] bbab, [4/6] baba
Length 5:[5/0] abbbb, [5/1] bbbbb, [5/2] bbbba, [5/3] bbbaa, [5/4] babaa, [5/5] bbbab, [5/6] bbaba
Length 6:[6/0] abbbbb, [6/1] bbbbba, [6/2] bbbbaa, [6/3] bbbbbb, [6/4] babbbb, [6/5] bbbbab, [6/6] bbabaa
Length 7:[7/0] abbbbbb, [7/1] abbbbba, [7/2] bbbbbaa, [7/3] bbbbbab, [7/4] bbbbbba, [7/5] bbbabaa, [7/6] bbbbbbb

Considering [length 5 / frequency 0] abbbb=c.

Step 2

Rewriting system is complete. See a, b | ababbbba=ab.