Morphocompletion for #2065 ⟨a, b | ababbaba=ab

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababbab ⇒ abbbaba
2. abbbabaa ⇒ ab
3. abbabbab ⇒ abbbbaba
4. abbbbabaa ⇒ abb
5. abbbabbab ⇒ abbbbbaba
6. abbbbbabaa ⇒ abbb
7. abbbbabbab ⇒ abbbbbbaba
8. ababbbbaba ⇒ abbbababab
9. abbbbbbabaa ⇒ abbbb
10. abbbbbabbab ⇒ abbbbbbbaba
11. abbbabababa ⇒ ababb
12. abbabbbbaba ⇒ abbbbababab
13. abbbbbbbabaa ⇒ abbbbb
14. abbbbabababa ⇒ abbabb
15. abbbbbbbbabaa ⇒ abbbbbb
16. abbbbbabababa ⇒ abbbabb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa
Length 3:[3/0] bbb, [3/1] abb, [3/2] bab, [3/3] aba, [3/4] bba, [3/5] baa
Length 4:[4/0] abbb, [4/1] bbab, [4/2] bbbb, [4/3] baba, [4/4] bbba, [4/5] abaa, [4/6] abab
Length 5:[5/0] abbbb, [5/1] abbab, [5/2] bbbab, [5/3] bbaba, [5/4] babaa, [5/5] bbbbb, [5/6] bbbba
Length 6:[6/0] bbbaba, [6/1] abbbbb, [6/2] bbabaa, [6/3] bbbbab, [6/4] babbab, [6/5] bababa, [6/6] abbbba
Length 7:[7/0] bbbabaa, [7/1] bbbbaba, [7/2] abbbbab, [7/3] bbabbab, [7/4] abababa, [7/5] abbbbba, [7/6] abbbbbb

Considering [length 7 / frequency 0] bbbabaa=c.

Step 2

Rewriting system is complete. See a, b | ababbaba=ab.