| Back: | ⟨a, b | ababbaab=ba⟩ |
|---|
Solved by morph:5/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | ababbaab ⇒ ba |
| 2. | ababbaba ⇒ baabbaab |
| 3. | ababababbba ⇒ babaabbbaab |
| 4. | baabbaabbbaab ⇒ ababbba |
| 5. | ababbaaababbba ⇒ baaabbaabbbaab |
| 6. | ababababbabba ⇒ babaabbabbaab |
| 7. | baabbaabbbaba ⇒ ababbbaabbaab |
| 8. | baabbaabbabbaab ⇒ ababbabba |
| 9. | ababbaaababbabba ⇒ baaabbaabbabbaab |
| 10. | baabbaabbabbaba ⇒ ababbabbaabbaab |
| 11. | baabbaabbababbba ⇒ ababbbabaabbbaab |
| 12. | babaabbbaabbabbaab ⇒ ababababbbba |
| 13. | babaabbabbaabbabbaab ⇒ ababababbabbba |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ba | 70 | lf:55,lp:7,ls:8,rf:42,rp:6,rs:5,re:1,lsrp:5,lprs:4 |
|---|---|---|---|
| [2/1] | ab | 64 | lf:53,lp:6,ls:5,rf:44,rp:7,rs:8,lsrp:4,lprs:5 |
| [2/2] | bb | 36 | lf:36,rf:31 |
| [2/3] | aa | 23 | lf:23,rf:20 |
| [3/0] | bba | 35 | lf:30,ls:5,rf:22,rs:4 |
| [3/1] | abb | 30 | lf:30,rf:22 |
| [3/2] | bab | 28 | lf:26,lp:2,rf:19,rp:2 |
| [3/3] | aba | 27 | lf:18,lp:6,ls:3,rf:14,rp:7,lsrp:2 |
| [3/4] | baa | 26 | lf:21,lp:5,rf:18,rp:3 |
| [3/5] | aab | 26 | lf:21,ls:5,rf:18,rs:8 |
| [3/6] | bbb | 6 | lf:6,rf:9,a:2 |
| [4/0] | baab | 29 | lf:19,lp:5,ls:5,rf:16,rp:1,rs:8,lprs:3 |
| [4/1] | abba | 26 | lf:24,ls:2,rf:14,rs:1 |
| [4/2] | abab | 19 | lf:13,lp:6,rf:11,rp:7 |
| [4/3] | babb | 16 | lf:16,rf:12 |
| [4/4] | baba | 15 | lf:10,lp:2,ls:3,rf:7,rp:2,a:1 |
| [4/5] | bbaa | 14 | lf:14,rf:12 |
| [4/6] | aabb | 14 | lf:14,rf:10,a:1 |
| [5/0] | baabb | 19 | lf:14,lp:5,rf:8,rp:1,a:1 |
| [5/1] | bbaab | 17 | lf:12,ls:5,rf:12,rs:8 |
| [5/2] | babba | 15 | lf:13,ls:2,rf:7,rs:1 |
| [5/3] | ababb | 13 | lf:9,lp:4,rf:7,rp:5 |
| [5/4] | abbaa | 12 | lf:12,rf:8 |
| [5/5] | aabba | 11 | lf:11,rf:7,a:1 |
| [5/6] | abbab | 10 | lf:10,rf:5,a:1 |
| [6/0] | baabba | 16 | lf:11,lp:5,rf:5,rp:1,a:1 |
| [6/1] | abbaab | 14 | lf:10,ls:4,rf:8,rs:5 |
| [6/2] | ababba | 10 | lf:6,lp:4,rf:3,rp:2 |
| [6/3] | bbabba | 9 | lf:7,ls:2,rf:4,rs:1,a:3 |
| [6/4] | bbaabb | 7 | lf:7,rf:4,a:2 |
| [6/5] | abbabb | 7 | lf:7,rf:5,a:3 |
| [6/6] | babbaa | 7 | lf:7,rf:3 |
| [7/0] | baabbaa | 10 | lf:5,lp:5,rf:3,rp:1,a:1 |
| [7/1] | abbabba | 9 | lf:7,ls:2,rf:4,rs:1,a:3 |
| [7/2] | babbaab | 9 | lf:5,ls:4,rf:3,rs:2 |
| [7/3] | ababbba | 6 | lf:3,ls:3,rf:3,rp:3,rs:1,re:1,lsrp:1,a:2 |
| [7/4] | baabbab | 6 | lf:6,rf:2,a:3 |
| [7/5] | abbaabb | 6 | lf:6,rf:3,a:2 |
| [7/6] | ababbaa | 6 | lf:3,lp:3 |
Considering [length 5 / frequency 1] bbaab=c.
Rewriting system is complete. See ⟨a, b | ababbaab=ba⟩.