Morphocompletion for #2062 ⟨a, b | ababbaab=ba⟩

Back:⟨a, b | ababbaab=ba⟩

Solved by morph:5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. ababbaab ⇒ ba
2. ababbaba ⇒ baabbaab
3. ababababbba ⇒ babaabbbaab
4. baabbaabbbaab ⇒ ababbba
5. ababbaaababbba ⇒ baaabbaabbbaab
6. ababababbabba ⇒ babaabbabbaab
7. baabbaabbbaba ⇒ ababbbaabbaab
8. baabbaabbabbaab ⇒ ababbabba
9. ababbaaababbabba ⇒ baaabbaabbabbaab
10. baabbaabbabbaba ⇒ ababbabbaabbaab
11. baabbaabbababbba ⇒ ababbbabaabbbaab
12. babaabbbaabbabbaab ⇒ ababababbbba
13. babaabbabbaabbabbaab ⇒ ababababbabbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] bb, [2/3] aa
Length 3:[3/0] bba, [3/1] abb, [3/2] bab, [3/3] aba, [3/4] baa, [3/5] aab, [3/6] bbb
Length 4:[4/0] baab, [4/1] abba, [4/2] abab, [4/3] babb, [4/4] baba, [4/5] bbaa, [4/6] aabb
Length 5:[5/0] baabb, [5/1] bbaab, [5/2] babba, [5/3] ababb, [5/4] abbaa, [5/5] aabba, [5/6] abbab
Length 6:[6/0] baabba, [6/1] abbaab, [6/2] ababba, [6/3] bbabba, [6/4] bbaabb, [6/5] abbabb, [6/6] babbaa
Length 7:[7/0] baabbaa, [7/1] abbabba, [7/2] babbaab, [7/3] ababbba, [7/4] baabbab, [7/5] abbaabb, [7/6] ababbaa

Considering [length 5 / frequency 1] bbaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababbaab=ba⟩.