Morphocompletion for #2057 ⟨a, b | abababba=ab⟩

Solved by morph:2/0,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbaa ⇒ ababab
2. abbabba ⇒ abababb
3. abababba ⇒ ab
4. abbbbaa ⇒ abbabab
5. abbbabba ⇒ abbababb
6. abbababba ⇒ abb
7. abbbbbaa ⇒ abbbabab
8. abababababb ⇒ abbba
9. abababbbba ⇒ abbabababb
10. abbbbabba ⇒ abbbababb
11. abbbababba ⇒ abbb
12. abbbbbbaa ⇒ abbbbabab
13. abbababababb ⇒ abbbba
14. abbbbbabba ⇒ abbbbababb
15. abbbbababba ⇒ abbbb
16. abbbbbbbaa ⇒ abbbbbabab
17. abbbababababb ⇒ abbbbba
18. abbbbbababba ⇒ abbbbb
...

Collecting factors up to length 7 / frequency 4:

[2/0]ab64lf:46,lp:18,rf:39,rp:18,rs:6,re:1,lprp:18,lprs:6
[2/1]bb61lf:58,ls:3,rf:41,rs:9
[2/2]ba53lf:43,ls:10,rf:24,rs:3
[2/3]aa10lf:5,ls:5,a:17
[3/0]abb46lf:28,lp:15,ls:3,rf:20,rp:15,rs:6,re:1,lprp:13,lsrp:3,lprs:5
[3/1]bba35lf:25,ls:10,rf:11,rs:3
[3/2]bbb30lf:30,rf:21,rs:3,a:3
[3/3]bab28lf:28,rf:21,rs:5
[4/0]abbb25lf:13,lp:12,rf:11,rp:11,rs:1,re:1,lprp:9,lprs:1,a:3
[4/1]abba24lf:12,lp:3,ls:9,rf:3,rp:3,lsrp:1
[4/2]abab21lf:18,lp:3,rf:13,rp:2,rs:5
[4/3]bbbb17lf:17,rf:10,rs:2,a:5
[5/0]babba18lf:9,ls:9
[5/1]abbbb17lf:9,lp:8,rf:7,rp:7,rs:1,re:1,lprp:5,lprs:1,a:5
[5/2]babab15lf:15,rf:11,rs:5
[5/3]ababb12lf:9,ls:3,rf:5,rs:5
[6/0]bababb12lf:9,ls:3,rf:5,rs:5
[6/1]ababab12lf:9,lp:3,rf:3,rp:2,rs:1,re:1
[6/2]abbbbb10lf:5,lp:5,rf:3,rp:3,rs:1,re:1,lprp:2,lprs:1,a:9
[6/3]ababba10lf:5,ls:5

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: wordLimit

#Rule
1. ab ⇒ c
2. cccba ⇒ c
3. cccbc ⇒ cb
4. cbba ⇒ cccccb
5. cbcba ⇒ cccb
6. cbccba ⇒ cb
7. cbbc ⇒ cccccbb
8. cbcbc ⇒ cccbb
9. cbccbc ⇒ cbb
10. cbbba ⇒ cbccccb
11. cbbbc ⇒ cbccccbb
12. cbbbba ⇒ cccccccccccccccccbbb
13. cbbbbc ⇒ cccccccccccccccccbbbb
...

Collecting factors up to length 6 / frequency 7:

[2/0]cb26lf:16,lp:10,rf:13,rp:5,rs:5,re:2,lprp:4,lprs:4,a:2
[2/1]bc16lf:10,ls:6,rf:2,a:3
[2/2]bb12lf:12,rf:9,rs:6,a:5
[2/3]ba12lf:6,ls:6,a:2
[2/4]cc8lf:6,lp:2,rf:50,rp:6,a:2
[3/0]cbc14lf:7,lp:4,ls:3,rf:2,rp:2,a:3
[3/1]cbb12lf:6,lp:6,rf:6,rp:1,rs:4,re:1,lprs:2,a:5
[3/2]bbb6lf:6,rf:3,rs:2,a:15
[3/3]bbc6lf:3,ls:3,a:18
[3/4]bba6lf:3,ls:3,a:8
[3/5]cba6lf:3,ls:3,a:2
[3/6]ccb4lf:4,rf:8,rs:3,a:2
[4/0]cbbb8lf:4,lp:4,rf:2,rs:1,lprs:1,a:15
[4/1]bbbc4lf:2,ls:2,a:19
[4/2]bbba4lf:2,ls:2,a:15
[4/3]cbcb4lf:2,lp:2,a:6
[4/4]cbcc4lf:2,lp:2,rf:2,rp:2,a:4
[4/5]ccbc4lf:2,ls:2,a:3
[4/6]ccba4lf:2,ls:2,a:2
[5/0]cbbbb4lf:2,lp:2,rf:1,rs:1,lprs:1,a:17
[5/1]cbccb4lf:2,lp:2,a:4
[5/2]bbbbc2lf:1,ls:1,a:20
[5/3]bbbba2lf:1,ls:1,a:17
[5/4]bccbc2lf:1,ls:1,a:5
[5/5]bccba2lf:1,ls:1,a:4
[5/6]ccbbb0rf:2,rs:1,a:17

Considering [length 2 / frequency 0] cb=d.

Step 3

Rewriting system is complete. See ⟨a, b | abababba=ab⟩.