Morphocompletion for #2049 ⟨a, b | ababaaab=aa⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababaaab ⇒ aa
2. aaabaaab ⇒ ababaaaa
3. ababababaaaa ⇒ aaaaab
4. ababaaaaaaab ⇒ aaabababaaaa
5. aaaaabbabaaab ⇒ aaaaaba
6. aaaaabaabaaab ⇒ aaaaabbabaaaa
7. aaaaababbabaaab ⇒ aaaaababa
8. ababababaababaaaa ⇒ aaaaabbaaab
9. aaaaabaabbabaaab ⇒ aaaaabaaba
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa52lf:45,lp:5,ls:2,rf:39,rp:8,rs:4,re:1,lprp:4,lsrp:2,lprs:2
[2/1]ab43lf:32,lp:4,ls:7,rf:15,rp:1,rs:2,lsrp:1,lprs:2
[2/2]ba25lf:25,rf:13,rs:3
[2/3]bb3lf:3,rf:2,a:5
[3/0]aaa35lf:28,lp:5,ls:2,rf:26,rp:7,rs:3,lprp:4,lsrp:2,lprs:2
[3/1]aba26lf:22,lp:4,rf:11,rp:1,rs:3
[3/2]aab22lf:15,ls:7,rf:9,rs:2
[3/3]bab13lf:13,rf:5
[3/4]baa12lf:12,rf:5
[3/5]abb3lf:3,rf:2,a:5
[3/6]bba3lf:3,rf:2,a:5
[4/0]aaaa20lf:14,lp:4,ls:2,rf:15,rp:6,rs:3,lprp:4,lsrp:2,lprs:1,a:1
[4/1]aaab20lf:12,lp:1,ls:7,rf:8,rp:1,rs:2,lsrp:1
[4/2]abab14lf:10,lp:4,rf:4,rp:1
[4/3]abaa12lf:12,rf:4
[4/4]baba12lf:12,rf:5,rs:1
[4/5]baaa9lf:9,rf:4
[4/6]aaba6lf:6,rf:5,rs:2,a:1
[5/0]ababa13lf:9,lp:4,rf:4,rp:1,rs:1
[5/1]baaab12lf:6,ls:6,rf:1,rs:1
[5/2]aaaaa11lf:7,lp:4,rf:6,rp:6,lprp:4,a:2
[5/3]abaaa9lf:9,rf:3
[5/4]babaa8lf:8,rf:3
[5/5]aaaab6lf:5,ls:1,rf:6,rs:1,a:2
[5/6]aaaba5lf:4,lp:1,rf:4,rp:1,rs:1,a:1
[6/0]abaaab12lf:6,ls:6
[6/1]aaaaab10lf:5,lp:4,ls:1,rf:6,rp:6,rs:1,re:1,lprp:4,a:2
[6/2]ababaa7lf:5,lp:2,rf:2,rp:1
[6/3]babaaa7lf:7,rf:3
[6/4]ababab6lf:4,lp:2,rf:1,a:2
[6/5]abaaaa5lf:3,ls:2,rf:3,rs:3,a:1
[6/6]aaabaa4lf:3,lp:1,rf:1,a:1
[7/0]babaaab8lf:4,ls:4
[7/1]aaaaaba6lf:3,lp:3,rf:3,rp:3,rs:1,re:1,lprp:2,a:5
[7/2]ababaaa6lf:4,lp:2,rf:2,rp:1
[7/3]abababa6lf:4,lp:2,rf:1,a:2
[7/4]babaaaa5lf:3,ls:2,rf:3,rs:3,a:1
[7/5]aabaaab4lf:2,ls:2,a:1
[7/6]abbabaa3lf:3,rf:1,a:5

Considering [length 2 / frequency 1] ab=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababaaab=aa⟩.