Morphocompletion for #2046 ⟨a, b | abaabbba=ab

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbbaaa ⇒ ab
2. ababbb ⇒ abbbba
3. abaabbb ⇒ abbbbaa
4. abbbbbaaa ⇒ abb
5. abbbbabaaa ⇒ abab
6. abbbbaabaaa ⇒ abaab
7. abbabbb ⇒ abbbbba
8. abbbbbbaaa ⇒ abbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] bbb, [3/1] abb, [3/2] aaa, [3/3] baa, [3/4] bba, [3/5] aba, [3/6] bab
Length 4:[4/0] abbb, [4/1] baaa, [4/2] bbbb, [4/3] bbba, [4/4] bbaa, [4/5] abaa, [4/6] babb
Length 5:[5/0] abbbb, [5/1] bbaaa, [5/2] bbbba, [5/3] babbb, [5/4] bbbaa, [5/5] abaaa, [5/6] bbbbb
Length 6:[6/0] abbbba, [6/1] bbbaaa, [6/2] abbbbb, [6/3] bbbbaa, [6/4] bbabbb, [6/5] bbbbba, [6/6] abbabb
Length 7:[7/0] bbbbaaa, [7/1] abbbbaa, [7/2] abbbbbb, [7/3] abbbbab, [7/4] abbbbba, [7/5] bbbbbaa, [7/6] bbabaaa

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See a, b | abaabbba=ab.