Morphocompletion for #2044 ⟨a, b | abaabbab=ba

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abaabbab ⇒ ba
2. baaabbab ⇒ abaabbba
3. abaabbaabaabbba ⇒ baaaabbab
4. baaaabbabbaabbab ⇒ abaabbaabaabbbba
5. baaabbaabaabbba ⇒ abaabbbaaaabbab
6. abaabbaabaabbaabaabbbba ⇒ baaaaabbabbaabbab
7. baaaaabbabbaabbabbaabbab ⇒ abaabbaabaabbaabaabbbbba
8. baaaabbabbaabbaabaabbba ⇒ abaabbaabaabbbbaaaabbab
9. baaabbaabaabbaabaabbbba ⇒ abaabbbaaaaabbabbaabbab
10. abaabbaabaabbaabaabbaabaabbbbba ⇒ baaaaaabbabbaabbabbaabbab
11. baaaaaabbabbaabbabbaabbabbaabbab ⇒ abaabbaabaabbaabaabbaabaabbbbbba
12. baaaaabbabbaabbabbaabbaabaabbba ⇒ abaabbaabaabbaabaabbbbbaaaabbab
13. baaaabbabbaabbaabaabbaabaabbbba ⇒ abaabbaabaabbbbaaaaabbabbaabbab
14. baaabbaabaabbaabaabbaabaabbbbba ⇒ abaabbbaaaaaabbabbaabbabbaabbab
15. abaabbaabaabbaabaabbaabaabbaabaabbbbbba ⇒ baaaaaaabbabbaabbabbaabbabbaabbab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] baa, [3/1] aab, [3/2] bba, [3/3] abb, [3/4] aba, [3/5] aaa, [3/6] bab
Length 4:[4/0] baab, [4/1] abba, [4/2] aabb, [4/3] abaa, [4/4] bbaa, [4/5] baaa, [4/6] aaba
Length 5:[5/0] aabba, [5/1] baabb, [5/2] abbaa, [5/3] abaab, [5/4] bbaab, [5/5] aabaa, [5/6] baaba
Length 6:[6/0] abbaab, [6/1] abaabb, [6/2] baabba, [6/3] baabaa, [6/4] aabbaa, [6/5] aabaab, [6/6] bbaaba
Length 7:[7/0] bbaabaa, [7/1] baabaab, [7/2] abbaaba, [7/3] abaabba, [7/4] aabbaab, [7/5] aabaabb, [7/6] baabbaa

Considering [length 3 / frequency 0] baa=c.

Step 2

Rewriting system is complete. See a, b | abaabbab=ba.