Morphocompletion for #2036 ⟨a, b | abaabaab=ba⟩

Back:⟨a, b | abaabaab=ba⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababa ⇒ baaab
2. aabbaa ⇒ baaaab
3. abaabaab ⇒ ba
4. baaabba ⇒ abbaaab
5. abbaaaba ⇒ babaaaab
6. baabaaabab ⇒ abba
7. abbaaaabaab ⇒ babaa
8. aababbaaab ⇒ abbaaaaabb
9. baabaabaaab ⇒ abbaa
10. baaaababba ⇒ abbaaaaabb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aab, [3/1] baa, [3/2] aba, [3/3] aaa, [3/4] bba, [3/5] abb, [3/6] bab
Length 4:[4/0] aaba, [4/1] abba, [4/2] baab, [4/3] baaa, [4/4] aaab, [4/5] abaa, [4/6] abab
Length 5:[5/0] baaab, [5/1] abbaa, [5/2] abaab, [5/3] baaba, [5/4] aabab, [5/5] aabaa, [5/6] aaaba
Length 6:[6/0] baabaa, [6/1] abbaaa, [6/2] aabaab, [6/3] ababba, [6/4] bbaaab, [6/5] aababb, [6/6] baaaba
Length 7:[7/0] aababba, [7/1] abbaaab, [7/2] baabaab, [7/3] baabaaa, [7/4] abaabaa, [7/5] baaaaba, [7/6] aabaaab

Considering [length 3 / frequency 0] aab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaabaab=ba⟩.