Morphocompletion for #2036 ⟨a, b | abaabaab=ba⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababa ⇒ baaab
2. aabbaa ⇒ baaaab
3. abaabaab ⇒ ba
4. baaabba ⇒ abbaaab
5. abbaaaba ⇒ babaaaab
6. baabaaabab ⇒ abba
7. abbaaaabaab ⇒ babaa
8. aababbaaab ⇒ abbaaaaabb
9. baabaabaaab ⇒ abbaa
10. baaaababba ⇒ abbaaaaabb
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab32lf:23,lp:4,ls:5,rf:13,rp:5,rs:4,lsrp:3,lprs:2
[2/1]ba30lf:22,lp:4,ls:4,rf:12,rp:5,rs:2,re:1,lsrp:2,lprs:1
[2/2]aa28lf:25,lp:2,ls:1,rf:20,rs:2
[2/3]bb6lf:6,rf:7,rs:2,a:2
[3/0]aab21lf:15,lp:2,ls:4,rf:6,rs:4,lprs:1
[3/1]baa19lf:14,lp:4,ls:1,rf:8,rp:2,rs:2,lsrp:1,lprs:1
[3/2]aba16lf:12,lp:2,ls:2,rf:2
[3/3]aaa9lf:9,rf:12,a:1
[3/4]bba8lf:6,ls:2,rf:5,rs:1,a:2
[3/5]abb8lf:6,lp:2,rf:7,rp:5,rs:2,a:2
[3/6]bab5lf:4,ls:1,rf:2,rp:2,a:1
[4/0]aaba11lf:9,lp:1,ls:1
[4/1]abba10lf:6,lp:2,ls:2,rf:5,rp:5,rs:1,re:1,lsrp:2,a:2
[4/2]baab10lf:6,lp:2,ls:2
[4/3]baaa9lf:7,lp:2,rf:6,rp:2,a:1
[4/4]aaab9lf:7,ls:2,rf:6,rs:4,a:1
[4/5]abaa7lf:6,lp:1,rf:2,rs:1
[4/6]abab6lf:4,lp:1,ls:1,a:1
[5/0]baaab8lf:5,lp:1,ls:2,rf:2,rp:1,rs:2,re:1,lprs:1,a:1
[5/1]abbaa7lf:4,lp:2,ls:1,rf:4,rp:4,rs:1,re:1,a:3
[5/2]abaab7lf:4,lp:1,ls:2
[5/3]baaba6lf:4,lp:2
[5/4]aabab5lf:3,lp:1,ls:1,a:2
[5/5]aabaa5lf:5
[5/6]aaaba5lf:4,ls:1,a:2
[6/0]baabaa6lf:4,lp:2
[6/1]abbaaa5lf:3,lp:2,rf:3,rp:3,a:3
[6/2]aabaab5lf:3,ls:2
[6/3]ababba3lf:2,ls:1,a:13
[6/4]bbaaab3lf:2,ls:1,rf:1,rs:1,a:3
[6/5]aababb3lf:2,lp:1,a:13
[6/6]baaaba3lf:2,ls:1,a:2
[7/0]aababba4lf:2,lp:1,ls:1,a:13
[7/1]abbaaab4lf:2,lp:1,ls:1,rf:1,rp:1,rs:1,re:1,a:3
[7/2]baabaab4lf:2,lp:1,ls:1
[7/3]baabaaa3lf:2,lp:1,a:2
[7/4]abaabaa3lf:2,lp:1
[7/5]baaaaba3lf:2,lp:1,a:13
[7/6]aabaaab3lf:2,ls:1,a:2

Considering [length 3 / frequency 0] aab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaabaab=ba⟩.