Morphocompletion for #2032 ⟨a, b | abaaabba=ba⟩

Solved by morph:7/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abaaabba ⇒ ba
2. abaaabbba ⇒ bba
3. abaaabbbba ⇒ bbba
4. abaaabbbbba ⇒ bbbba
5. abaaabbbbbba ⇒ bbbbba
6. abaaabbbbbbba ⇒ bbbbbba
7. abaaabbbbbbbba ⇒ bbbbbbba
8. abaaabbbbbbbbba ⇒ bbbbbbbba
9. abaaabbbbbbbbbba ⇒ bbbbbbbbba
10. abaaabbbbbbbbbbba ⇒ bbbbbbbbbba
11. abaaabbbbbbbbbbbba ⇒ bbbbbbbbbbba
12. abaaabbbbbbbbbbbbba ⇒ bbbbbbbbbbbba
13. abaaabbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbba
14. abaaabbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbba
15. abaaabbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbba
16. abaaabbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbba
17. abaaabbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbba
18. abaaabbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbba
19. abaaabbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbba
20. abaaabbbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb210lf:210,rf:190,rp:19
[2/1]ba60lf:40,ls:20,rf:20,rp:1,rs:20,re:1,lsrp:1,lsrs:20
[2/2]ab60lf:40,lp:20
[2/3]aa40lf:40
[3/0]bbb190lf:190,rf:171,rp:18,a:1
[3/1]bba40lf:20,ls:20,rf:19,rp:1,rs:19,re:1,lsrp:1,lsrs:19
[3/2]aba40lf:20,lp:20
[3/3]baa20lf:20
[3/4]abb20lf:20
[3/5]aab20lf:20
[3/6]aaa20lf:20
[4/0]bbbb171lf:171,rf:153,rp:17,a:2
[4/1]abaa40lf:20,lp:20
[4/2]bbba38lf:19,ls:19,rf:18,rp:1,rs:18,re:1,lsrp:1,lsrs:18,a:1
[4/3]baaa20lf:20
[4/4]aabb20lf:20
[4/5]aaab20lf:20
[4/6]abbb19lf:19,a:1
[5/0]bbbbb153lf:153,rf:136,rp:16,a:3
[5/1]abaaa40lf:20,lp:20
[5/2]bbbba36lf:18,ls:18,rf:17,rp:1,rs:17,re:1,lsrp:1,lsrs:17,a:2
[5/3]baaab20lf:20
[5/4]aaabb20lf:20
[5/5]aabbb19lf:19,a:1
[5/6]abbbb18lf:18,a:2
[6/0]bbbbbb136lf:136,rf:120,rp:15,a:4
[6/1]abaaab40lf:20,lp:20
[6/2]bbbbba34lf:17,ls:17,rf:16,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:3
[6/3]baaabb20lf:20
[6/4]aaabbb19lf:19,a:1
[6/5]aabbbb18lf:18,a:2
[6/6]abbbbb17lf:17,a:3
[7/0]bbbbbbb120lf:120,rf:105,rp:14,a:5
[7/1]abaaabb40lf:20,lp:20
[7/2]bbbbbba32lf:16,ls:16,rf:15,rp:1,rs:15,re:1,lsrp:1,lsrs:15,a:4
[7/3]baaabbb19lf:19,a:1
[7/4]aaabbbb18lf:18,a:2
[7/5]aabbbbb17lf:17,a:3
[7/6]abbbbbb16lf:16,a:4

Considering [length 7 / frequency 1] abaaabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaabba=ba⟩.