Morphocompletion for #2031 ⟨a, b | abaaabba=ab⟩

Back:⟨a, b | abaaabba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbaaaa ⇒ ab
2. ababb ⇒ abbba
3. abaabb ⇒ abbbaa
4. abaaabb ⇒ abbbaaa
5. abbbbaaaa ⇒ abb
6. abbbabaaaa ⇒ abab
7. abbabb ⇒ abbbba
8. abbaabb ⇒ abbbbaa
9. abbbbbaaaa ⇒ abbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] bb, [2/2] aa, [2/3] ba
Length 3:[3/0] abb, [3/1] aaa, [3/2] bbb, [3/3] aba, [3/4] baa, [3/5] bba, [3/6] bab
Length 4:[4/0] abbb, [4/1] aaaa, [4/2] aabb, [4/3] abaa, [4/4] baaa, [4/5] babb, [4/6] bbba
Length 5:[5/0] baaaa, [5/1] abbbb, [5/2] abbba, [5/3] baabb, [5/4] bbbaa, [5/5] bbaaa, [5/6] abaaa
Length 6:[6/0] bbaaaa, [6/1] bbbaaa, [6/2] abbbbb, [6/3] abbbab, [6/4] abbbba, [6/5] bbaabb, [6/6] bbbbaa
Length 7:[7/0] bbbaaaa, [7/1] abbbbba, [7/2] abbbaba, [7/3] abbbbaa, [7/4] bbbbaaa, [7/5] abbbaaa, [7/6] babaaaa

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaabba=ab⟩.