Morphocompletion for #2021 ⟨a, b | abaaaaab=ba

Solved by morph:6/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaaaab ⇒ ba
2. baaaaaab ⇒ abaaaaba
3. baaaaaaab ⇒ aabaaabaa
4. baaaaaaaab ⇒ aaabaabaaa
5. baaaaaaaaab ⇒ aaaababaaaa
6. baaaaaaaaaab ⇒ aaaaabbaaaaa
7. baaaaaaaaaaabb ⇒ aaaaaabbaaaaba
8. bbaaaaaaaaaaab ⇒ abaaaabbaaaaaa
9. baaaaaaaaaaaabb ⇒ aaaaaaabbaaabaa
10. aaaaaabbaaaaabaaaaa ⇒ baaaaaaaaaaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] baa, [3/2] aab, [3/3] abb, [3/4] aba, [3/5] bba, [3/6] bab
Length 4:[4/0] aaaa, [4/1] baaa, [4/2] aaab, [4/3] aabb, [4/4] abaa, [4/5] bbaa, [4/6] aaba
Length 5:[5/0] aaaaa, [5/1] baaaa, [5/2] aaaab, [5/3] aaabb, [5/4] abaaa, [5/5] bbaaa, [5/6] aabaa
Length 6:[6/0] aaaaaa, [6/1] baaaaa, [6/2] aaaaab, [6/3] aaaabb, [6/4] abaaaa, [6/5] bbaaaa, [6/6] aabaaa
Length 7:[7/0] aaaaaaa, [7/1] aaaaaab, [7/2] baaaaaa, [7/3] aaaaabb, [7/4] abaaaaa, [7/5] bbaaaaa, [7/6] baaaaab

Considering [length 6 / frequency 1] baaaaa=c.

Step 2

Rewriting system is complete. See a, b | abaaaaab=ba.