Morphocompletion for #2016 ⟨a, b | aabbbbba=ab⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aabbbbba ⇒ ab
2. ababbbbba ⇒ abb
3. aabbbbbb ⇒ abbbbbba
4. abbabbbbba ⇒ abbb
5. ababbbbbb ⇒ abbbbbbba
6. abbbabbbbba ⇒ abbbb
7. abbabbbbbb ⇒ abbbbbbbba
8. abbbbabbbbba ⇒ abbbbb
9. abbbabbbbbb ⇒ abbbbbbbbba
10. abbbbbabbbbba ⇒ abbbbbb
11. abbbbabbbbbb ⇒ abbbbbbbbbba
12. abbbbbbabbbbba ⇒ abbbbbbb
13. abbbbbabbbbbb ⇒ abbbbbbbbbbba
14. abbbbbbbabbbbba ⇒ abbbbbbbb
15. abbbbbbabbbbbb ⇒ abbbbbbbbbbbba
16. abbbbbbbbabbbbba ⇒ abbbbbbbbb
17. abbbbbbbabbbbbb ⇒ abbbbbbbbbbbbba
18. abbbbbbbbbabbbbba ⇒ abbbbbbbbbb
19. abbbbbbbbabbbbbb ⇒ abbbbbbbbbbbbbba
20. abbbbbbbbbbabbbbba ⇒ abbbbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb171lf:162,ls:9,rf:136,rs:10
[2/1]ab56lf:38,lp:18,rf:20,rp:20,rs:1,re:1,lprp:18
[2/2]ba40lf:29,ls:11,rf:9,rs:9
[2/3]aa4lf:2,lp:2
[3/0]bbb135lf:126,ls:9,rf:117,rs:9
[3/1]abb52lf:36,lp:16,rf:19,rp:19,rs:1,re:1,lprp:16
[3/2]bba38lf:27,ls:11,rf:9,rs:9
[3/3]bab18lf:18,a:1
[3/4]aab4lf:2,lp:2
[3/5]aba4lf:2,lp:2,a:1
[4/0]bbbb101lf:92,ls:9,rf:99,rs:8
[4/1]abbb48lf:34,lp:14,rf:18,rp:18,rs:1,re:1,lprp:14
[4/2]bbba36lf:25,ls:11,rf:9,rs:9
[4/3]babb18lf:18,a:1
[4/4]bbab16lf:16,a:2
[4/5]aabb4lf:2,lp:2
[4/6]abab4lf:2,lp:2,a:1
[5/0]bbbbb69lf:60,ls:9,rf:82,rs:7
[5/1]abbbb44lf:32,lp:12,rf:17,rp:17,rs:1,re:1,lprp:12
[5/2]bbbba34lf:23,ls:11,rf:9,rs:9
[5/3]babbb18lf:18,a:1
[5/4]bbabb16lf:16,a:2
[5/5]bbbab14lf:14,a:3
[5/6]aabbb4lf:2,lp:2
[6/0]abbbbb40lf:30,lp:10,rf:16,rp:16,rs:1,re:1,lprp:10
[6/1]bbbbbb39lf:30,ls:9,rf:66,rs:6,a:5
[6/2]bbbbba32lf:21,ls:11,rf:9,rs:9
[6/3]babbbb18lf:18,a:1
[6/4]bbabbb16lf:16,a:2
[6/5]bbbabb14lf:14,a:3
[6/6]bbbbab12lf:12,a:4
[7/0]abbbbbb34lf:17,lp:8,ls:9,rf:15,rp:15,rs:1,re:1,lprp:8,lsrp:18,a:5
[7/1]abbbbba26lf:13,lp:2,ls:11
[7/2]babbbbb18lf:18,a:1
[7/3]bbabbbb16lf:16,a:2
[7/4]bbbabbb14lf:14,a:3
[7/5]bbbbbbb13lf:13,rf:51,rs:5,a:6
[7/6]bbbbabb12lf:12,a:4

Considering [length 6 / frequency 0] abbbbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbbbba=ab⟩.