Morphocompletion for #2009 ⟨a, b | aabbbbaa=ab⟩

Back:⟨a, b | aabbbbaa=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbbbaa ⇒ ab
2. aabbbbab ⇒ abbbbbaa
3. ababbbbaa ⇒ abb
4. ababbbbab ⇒ abbbbbbaa
5. abbabbbbaa ⇒ abbb
6. abbabbbbab ⇒ abbbbbbbaa
7. abbbabbbbaa ⇒ abbbb
8. abbbabbbbab ⇒ abbbbbbbbaa
9. abbbbabbbbaa ⇒ abbbbb
10. abbbbabbbbab ⇒ abbbbbbbbbaa
11. abbbbbaabbbaa ⇒ aabbbbb
12. abbbbbabbbbaa ⇒ abbbbbb
13. abbbbbaabbbab ⇒ aabbbbbbbbbaa
14. abbbbbabbbbab ⇒ abbbbbbbbbbaa
15. abbbbbbaabbbaa ⇒ ababbbbb
16. abbbbbbabbbbaa ⇒ abbbbbbb
17. abbbbbbbaabbbaa ⇒ abbabbbbb
18. abbbbbbbabbbbaa ⇒ abbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] bbb, [3/1] abb, [3/2] bba, [3/3] bab, [3/4] baa, [3/5] aab, [3/6] aba
Length 4:[4/0] abbb, [4/1] bbbb, [4/2] bbba, [4/3] bbaa, [4/4] bbab, [4/5] babb, [4/6] aabb
Length 5:[5/0] abbbb, [5/1] bbbaa, [5/2] bbbba, [5/3] bbbab, [5/4] bbbbb, [5/5] babbb, [5/6] bbabb
Length 6:[6/0] bbbbaa, [6/1] bbbbab, [6/2] abbbba, [6/3] abbbbb, [6/4] babbbb, [6/5] bbabbb, [6/6] bbbabb
Length 7:[7/0] abbbbab, [7/1] abbbbaa, [7/2] babbbba, [7/3] bbabbbb, [7/4] abbbbbb, [7/5] bbbabbb, [7/6] abbbbba

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbbbaa=ab⟩.