Morphocompletion for #2009 ⟨a, b | aabbbbaa=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbbbaa ⇒ ab
2. aabbbbab ⇒ abbbbbaa
3. ababbbbaa ⇒ abb
4. ababbbbab ⇒ abbbbbbaa
5. abbabbbbaa ⇒ abbb
6. abbabbbbab ⇒ abbbbbbbaa
7. abbbabbbbaa ⇒ abbbb
8. abbbabbbbab ⇒ abbbbbbbbaa
9. abbbbabbbbaa ⇒ abbbbb
10. abbbbabbbbab ⇒ abbbbbbbbbaa
11. abbbbbaabbbaa ⇒ aabbbbb
12. abbbbbabbbbaa ⇒ abbbbbb
13. abbbbbaabbbab ⇒ aabbbbbbbbbaa
14. abbbbbabbbbab ⇒ abbbbbbbbbbaa
15. abbbbbbaabbbaa ⇒ ababbbbb
16. abbbbbbabbbbaa ⇒ abbbbbbb
17. abbbbbbbaabbbaa ⇒ abbabbbbb
18. abbbbbbbabbbbaa ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb100lf:100,rf:88,rs:10
[2/1]ab64lf:41,lp:16,ls:7,rf:20,rp:16,rs:1,re:1,lprp:14,lsrp:6
[2/2]ba34lf:34,rf:9
[2/3]aa30lf:17,lp:2,ls:11,rf:9,rp:2,rs:7,lsrp:1,lprs:1
[3/0]bbb68lf:68,rf:70,rs:9
[3/1]abb46lf:32,lp:14,rf:18,rp:14,rs:1,re:1,lprp:11
[3/2]bba32lf:32,rf:8
[3/3]bab26lf:19,ls:7,rf:2,a:1
[3/4]baa26lf:15,ls:11,rf:7,rs:7
[3/5]aab8lf:6,lp:2,rf:2,rp:2
[3/6]aba4lf:2,lp:2,rf:1,rp:1,a:2
[4/0]abbb42lf:30,lp:12,rf:16,rp:12,rs:1,re:1,lprp:8
[4/1]bbbb38lf:38,rf:54,rs:8
[4/2]bbba30lf:30,rf:7
[4/3]bbaa26lf:15,ls:11,rf:7,rs:7
[4/4]bbab24lf:17,ls:7,rf:1,a:1
[4/5]babb12lf:12,rf:2,a:2
[4/6]aabb8lf:6,lp:2,rf:2,rp:2
[5/0]abbbb34lf:24,lp:10,rf:15,rp:11,rs:1,re:1,lprp:6
[5/1]bbbaa26lf:15,ls:11,rf:7,rs:7
[5/2]bbbba24lf:24,rf:7
[5/3]bbbab22lf:15,ls:7,a:1
[5/4]bbbbb14lf:14,rf:39,rs:7,a:1
[5/5]babbb12lf:12,rf:2,a:2
[5/6]bbabb10lf:10,rf:1,a:3
[6/0]bbbbaa20lf:12,ls:8,rf:7,rs:7
[6/1]bbbbab18lf:12,ls:6,a:1
[6/2]abbbba18lf:16,lp:2
[6/3]abbbbb16lf:8,lp:8,rf:14,rp:10,rs:4,re:1,lprp:4,lprs:3,a:1
[6/4]babbbb12lf:12,rf:2,a:2
[6/5]bbabbb10lf:10,rf:1,a:3
[6/6]bbbabb8lf:8,a:5
[7/0]abbbbab16lf:8,lp:2,ls:6,a:1
[7/1]abbbbaa16lf:8,ls:8
[7/2]babbbba12lf:12,a:2
[7/3]bbabbbb10lf:10,rf:1,a:3
[7/4]abbbbbb8lf:4,lp:4,rf:9,rp:8,rs:1,re:1,lprp:2,a:4
[7/5]bbbabbb8lf:8,a:5
[7/6]abbbbba8lf:4,lp:4,rf:1,rp:1,a:1

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbbbaa=ab⟩.