| Back: | ⟨a, b | aabbbaba=ab⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabbbaba ⇒ ab |
| 2. | ababbbaba ⇒ abb |
| 3. | aabbbabb ⇒ abbbbaba |
| 4. | abbabbbaba ⇒ abbb |
| 5. | ababbbabb ⇒ abbbbbaba |
| 6. | abbbbabababa ⇒ aabbbb |
| 7. | abbbabbbaba ⇒ abbbb |
| 8. | abbabbbabb ⇒ abbbbbbaba |
| 9. | abbbbbabababa ⇒ ababbbb |
| 10. | abbbbabbbaba ⇒ abbbbb |
| 11. | abbbabbbabb ⇒ abbbbbbbaba |
| 12. | aabbbbbbbaba ⇒ abbbbabababb |
| 13. | abbbbbbabababa ⇒ abbabbbb |
| 14. | abbbbbabbbaba ⇒ abbbbbb |
| 15. | abbbbabbbabb ⇒ abbbbbbbbaba |
| 16. | abbbbbbabbbaba ⇒ abbbbbbb |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa |
|---|---|
| Length 3: | [3/0] abb, [3/1] bbb, [3/2] bab, [3/3] aba, [3/4] bba, [3/5] aab |
| Length 4: | [4/0] abbb, [4/1] baba, [4/2] bbab, [4/3] bbba, [4/4] babb, [4/5] bbbb, [4/6] abab |
| Length 5: | [5/0] bbbab, [5/1] bbaba, [5/2] bbabb, [5/3] abbba, [5/4] abbbb, [5/5] babbb, [5/6] bbbbb |
| Length 6: | [6/0] bbbaba, [6/1] bbbabb, [6/2] abbbab, [6/3] babbba, [6/4] abbbbb, [6/5] bababa, [6/6] bbabbb |
| Length 7: | [7/0] abbbabb, [7/1] abbbaba, [7/2] babbbab, [7/3] bbabbba, [7/4] bbbabbb, [7/5] abbbbab, [7/6] abababa |
Considering [length 4 / frequency 0] abbb=c.
Rewriting system is complete. See ⟨a, b | aabbbaba=ab⟩.