Morphocompletion for #2002 ⟨a, b | aabbbaab=ba⟩

Back:⟨a, b | aabbbaab=ba⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aabbbaab ⇒ ba
2. aabbbba ⇒ babbaab
3. babbaababbbaab ⇒ aabbbbba
4. aabbbaaaabbbbba ⇒ baabbaababbbaab
5. babbaababbbba ⇒ aabbbbbabbaab
6. aabbaabbbaaaabbbbbba ⇒ babaababbbaababbbaab
7. baabbaababbbaababbbaab ⇒ aabbbaaaabbbbbba
8. aabbbaaaabbbaaaabbbbbba ⇒ baaabbaababbbaababbbaab
9. babbaababbbaaaabbbbba ⇒ aabbbbbaabbaababbbaab
10. baabbaababbbaababbbba ⇒ aabbbaaaabbbbbbabbaab
11. babaababbbaababbbaababbbaab ⇒ aabbaabbbaaaabbbbbbba
12. babbaababbaabbbaaaabbbbbba ⇒ aabbbbbabaababbbaababbbaab
13. babaababbbaababbbaababbbba ⇒ aabbaabbbaaaabbbbbbbabbaab
14. baaabbaababbbaababbbaababbbaab ⇒ aabbbaaaabbbaaaabbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] bb, [2/2] ab, [2/3] aa
Length 3:[3/0] aab, [3/1] bba, [3/2] bbb, [3/3] abb, [3/4] baa, [3/5] bab, [3/6] aba
Length 4:[4/0] bbba, [4/1] baab, [4/2] abbb, [4/3] bbaa, [4/4] babb, [4/5] aabb, [4/6] bbbb
Length 5:[5/0] bbaab, [5/1] bbbaa, [5/2] abbba, [5/3] bbbba, [5/4] ababb, [5/5] baaba, [5/6] aabab
Length 6:[6/0] abbbaa, [6/1] bbbaab, [6/2] baabab, [6/3] aababb, [6/4] ababbb, [6/5] bbaaba, [6/6] babbba
Length 7:[7/0] abbbaab, [7/1] baababb, [7/2] aababbb, [7/3] bbaabab, [7/4] babbbaa, [7/5] ababbba, [7/6] babbaab

Considering [length 5 / frequency 0] bbaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbbaab=ba⟩.