Morphocompletion for #1997 ⟨a, b | aabbabba=ab⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aabbb ⇒ abbba
2. ababbb ⇒ abbbba
3. abbabbb ⇒ abbbbba
4. abbbabbb ⇒ abbbbbba
5. aabbabba ⇒ ab
6. abbbbabbb ⇒ abbbbbbba
7. ababbabba ⇒ abb
8. abbbbbabbb ⇒ abbbbbbbba
9. abbabbabba ⇒ abbb
10. abbbbbbabbb ⇒ abbbbbbbbba
11. abbbabbabba ⇒ abbbb
12. abbbbbbbabbb ⇒ abbbbbbbbbba
13. abbbbabbabba ⇒ abbbbb
14. abbbbbbbbabbb ⇒ abbbbbbbbbbba
15. abbbbbabbabba ⇒ abbbbbb
16. abbbbbbbbbabbb ⇒ abbbbbbbbbbbba
17. abbbbbbabbabba ⇒ abbbbbbb
18. abbbbbbbabbabba ⇒ abbbbbbbb
19. abbbbbbbbabbabba ⇒ abbbbbbbbb
20. abbbbbbbbbabbabba ⇒ abbbbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb122lf:112,ls:10,rf:110,rs:9
[2/1]ab66lf:48,lp:18,rf:20,rp:20,rs:1,re:1,lprp:18
[2/2]ba48lf:38,ls:10,rf:10,rs:10
[2/3]aa4lf:2,lp:2
[3/0]bbb76lf:66,ls:10,rf:91,rs:8,a:2
[3/1]abb62lf:46,lp:16,rf:19,rp:19,rs:1,re:1,lprp:16
[3/2]bba46lf:36,ls:10,rf:10,rs:10
[3/3]bab28lf:28
[3/4]aab4lf:2,lp:2
[3/5]aba4lf:2,lp:2,a:1
[4/0]abbb48lf:24,lp:14,ls:10,rf:18,rp:18,rs:1,re:1,lprp:14,lsrp:19,a:2
[4/1]bbbb42lf:42,rf:73,rs:7,a:3
[4/2]abba34lf:22,lp:2,ls:10
[4/3]babb28lf:28
[4/4]bbab26lf:26
[4/5]bbba14lf:14,rf:10,rs:10,a:3
[4/6]aabb4lf:2,lp:2
[5/0]bbbbb30lf:30,rf:57,rs:6,a:7
[5/1]babba29lf:19,ls:10
[5/2]bbabb26lf:26
[5/3]abbbb24lf:12,lp:12,rf:16,rp:16,rs:1,re:1,lprp:12,a:3
[5/4]babbb18lf:9,ls:9,a:6
[5/5]abbab14lf:12,lp:2
[5/6]bbbab14lf:14,a:3
[6/0]bbabba28lf:18,ls:10
[6/1]abbbbb20lf:10,lp:10,rf:14,rp:14,rs:1,re:1,lprp:10,a:7
[6/2]bbbbbb20lf:20,rf:43,rs:5,a:9
[6/3]bbabbb16lf:8,ls:8,a:8
[6/4]abbabb14lf:12,lp:2
[6/5]bbbabb14lf:14,a:3
[6/6]bbbbab12lf:12,a:7
[7/0]abbabba22lf:11,lp:1,ls:10
[7/1]abbbbbb16lf:8,lp:8,rf:12,rp:12,rs:1,re:1,lprp:8,a:9
[7/2]bbbabbb14lf:7,ls:7,a:9
[7/3]bbbbabb12lf:12,a:7
[7/4]bbbbbbb12lf:12,rf:31,rs:4,a:10
[7/5]bbbbbab10lf:10,a:11
[7/6]babbabb9lf:9,a:1

Considering [length 7 / frequency 0] abbabba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbabba=ab⟩.