Morphocompletion for #1987 ⟨a, b | aabbaaba=ba⟩

Back:⟨a, b | aabbaaba=ba⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbba ⇒ ba
2. bbaaba ⇒ aabbba
3. aaaabbbba ⇒ bba
4. aaaabaabbba ⇒ baaba
5. bbaabba ⇒ aabbbba
6. aaaabbbbba ⇒ bbba
7. aaaabaabbbba ⇒ baabba
8. bbaabbba ⇒ aabbbbba
9. aaaabbbbbba ⇒ bbbba
10. aaaabaabbbbba ⇒ baabbba
11. bbaabbbba ⇒ aabbbbbba
12. aaaabbbbbbba ⇒ bbbbba
13. bbaabbbbba ⇒ aabbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] aa, [2/2] ba, [2/3] ab
Length 3:[3/0] bba, [3/1] bbb, [3/2] aaa, [3/3] aab, [3/4] abb, [3/5] baa, [3/6] aba
Length 4:[4/0] bbba, [4/1] bbbb, [4/2] aaaa, [4/3] aabb, [4/4] abbb, [4/5] bbaa, [4/6] baab
Length 5:[5/0] bbbba, [5/1] aaaab, [5/2] aabbb, [5/3] bbaab, [5/4] bbbbb, [5/5] abbbb, [5/6] baabb
Length 6:[6/0] bbbbba, [6/1] aaaabb, [6/2] bbaabb, [6/3] aabbbb, [6/4] abbbba, [6/5] baabbb, [6/6] aabbba
Length 7:[7/0] aaaabbb, [7/1] abbbbba, [7/2] bbaabbb, [7/3] aabbbba, [7/4] aaaabaa, [7/5] aabbbbb, [7/6] bbbbbba

Considering [length 3 / frequency 0] bba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbaaba=ba⟩.