Morphocompletion for #1986 ⟨a, b | aabbaaba=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbaaba ⇒ ab
2. ababbaaba ⇒ abb
3. aabbaabb ⇒ abbbaaba
4. abbbaabaaaba ⇒ aabbab
5. abbabbaaba ⇒ abbb
6. ababbaabb ⇒ abbbbaaba
7. abbbbaabaaaba ⇒ ababbab
8. abbbabbaaba ⇒ abbbb
9. abbabbaabb ⇒ abbbbbaaba
10. aabbabbbaaba ⇒ abbbaabaaabb
11. abbbbbaabaaaba ⇒ abbabbab
12. abbbbabbaaba ⇒ abbbbb
13. abbbabbaabb ⇒ abbbbbbaaba
14. abbbbbabbaaba ⇒ abbbbbb
15. abbbbbbabbaaba ⇒ abbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] abb, [3/1] aba, [3/2] aab, [3/3] bba, [3/4] bbb, [3/5] baa, [3/6] bab
Length 4:[4/0] aaba, [4/1] abbb, [4/2] abba, [4/3] baab, [4/4] bbaa, [4/5] aabb, [4/6] babb
Length 5:[5/0] baaba, [5/1] bbaab, [5/2] abbaa, [5/3] abbbb, [5/4] babba, [5/5] bbabb, [5/6] baabb
Length 6:[6/0] bbaaba, [6/1] abbaab, [6/2] babbaa, [6/3] bbaabb, [6/4] bbabba, [6/5] abbbbb, [6/6] baaaba
Length 7:[7/0] abbaaba, [7/1] babbaab, [7/2] abbaabb, [7/3] bbabbaa, [7/4] abaaaba, [7/5] bbbabba, [7/6] bbbaaba

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aabbaaba=ab.