| Back: | ⟨a, b | aabbaaba=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabbaaba ⇒ ab |
| 2. | ababbaaba ⇒ abb |
| 3. | aabbaabb ⇒ abbbaaba |
| 4. | abbbaabaaaba ⇒ aabbab |
| 5. | abbabbaaba ⇒ abbb |
| 6. | ababbaabb ⇒ abbbbaaba |
| 7. | abbbbaabaaaba ⇒ ababbab |
| 8. | abbbabbaaba ⇒ abbbb |
| 9. | abbabbaabb ⇒ abbbbbaaba |
| 10. | aabbabbbaaba ⇒ abbbaabaaabb |
| 11. | abbbbbaabaaaba ⇒ abbabbab |
| 12. | abbbbabbaaba ⇒ abbbbb |
| 13. | abbbabbaabb ⇒ abbbbbbaaba |
| 14. | abbbbbabbaaba ⇒ abbbbbb |
| 15. | abbbbbbabbaaba ⇒ abbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 55 | lf:43,lp:12,rf:26,rp:14,rs:4,re:1,lprp:11,lprs:3 |
|---|---|---|---|
| [2/1] | ba | 50 | lf:39,ls:11,rf:15,rs:4 |
| [2/2] | bb | 49 | lf:45,ls:4,rf:42,rs:7 |
| [2/3] | aa | 27 | lf:24,lp:3,rf:8,rp:1 |
| [3/0] | abb | 41 | lf:27,lp:10,ls:4,rf:16,rp:12,rs:2,re:1,lprp:8,lsrp:4 |
| [3/1] | aba | 29 | lf:16,lp:2,ls:11,rf:6,rp:1,rs:4,lsrp:1,lprs:1 |
| [3/2] | aab | 24 | lf:21,lp:3,rf:7,rp:1 |
| [3/3] | bba | 23 | lf:23,rf:9 |
| [3/4] | bbb | 18 | lf:18,rf:26,rs:5,a:2 |
| [3/5] | baa | 18 | lf:18,rf:6 |
| [3/6] | bab | 10 | lf:10,rf:5,rs:3,a:1 |
| [4/0] | aaba | 25 | lf:14,ls:11,rf:5,rs:4 |
| [4/1] | abbb | 17 | lf:9,lp:8,rf:10,rp:10,rs:1,re:1,lprp:5,a:2 |
| [4/2] | abba | 16 | lf:14,lp:2,rf:4,rp:1 |
| [4/3] | baab | 15 | lf:15,rf:5 |
| [4/4] | bbaa | 15 | lf:15,rf:5 |
| [4/5] | aabb | 14 | lf:7,lp:3,ls:4,rf:2,rp:1,rs:1,lprs:1 |
| [4/6] | babb | 10 | lf:10,rf:2,a:1 |
| [5/0] | baaba | 19 | lf:11,ls:8,rf:5,rs:4 |
| [5/1] | bbaab | 15 | lf:15,rf:5 |
| [5/2] | abbaa | 11 | lf:11 |
| [5/3] | abbbb | 10 | lf:5,lp:5,rf:7,rp:7,rs:1,re:1,lprp:3,a:4 |
| [5/4] | babba | 9 | lf:9,rf:2,a:1 |
| [5/5] | bbabb | 8 | lf:8,rf:1,a:3 |
| [5/6] | baabb | 8 | lf:4,ls:4,a:2 |
| [6/0] | bbaaba | 19 | lf:11,ls:8,rf:5,rs:4 |
| [6/1] | abbaab | 11 | lf:11 |
| [6/2] | babbaa | 9 | lf:9,a:1 |
| [6/3] | bbaabb | 8 | lf:4,ls:4,a:2 |
| [6/4] | bbabba | 7 | lf:7,rf:1,a:3 |
| [6/5] | abbbbb | 6 | lf:3,lp:3,rf:5,rp:5,rs:1,re:1,lprp:2,a:6 |
| [6/6] | baaaba | 6 | lf:3,ls:3,a:9 |
| [7/0] | abbaaba | 14 | lf:7,ls:7 |
| [7/1] | babbaab | 9 | lf:9,a:1 |
| [7/2] | abbaabb | 8 | lf:4,ls:4,a:2 |
| [7/3] | bbabbaa | 7 | lf:7,a:3 |
| [7/4] | abaaaba | 6 | lf:3,ls:3,a:9 |
| [7/5] | bbbabba | 5 | lf:5,a:5 |
| [7/6] | bbbaaba | 5 | lf:4,ls:1,rf:5,rs:4,a:2 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aabbaaba=ab⟩.