Morphocompletion for #1978 ⟨a, b | aababbba=ab⟩

Back:⟨a, b | aababbba=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababbba ⇒ ab
2. abbabbba ⇒ aababbbb
3. abababbba ⇒ abb
4. abbbabbba ⇒ abababbbb
5. abbababbba ⇒ abbb
6. abbbbabbba ⇒ abbababbbb
7. abbbababbba ⇒ abbbb
8. abbbbbabbba ⇒ abbbababbbb
9. aababababbbb ⇒ abbbba
10. abbabababbbb ⇒ aababbbbbbba
11. abbbbababbba ⇒ abbbbb
12. abbbbbbabbba ⇒ abbbbababbbb
13. abababababbbb ⇒ abbbbba
14. abbbbbababbba ⇒ abbbbbb
15. abbababababbbb ⇒ abbbbbba
16. abbbbbbababbba ⇒ abbbbbbb
17. abbbababababbbb ⇒ abbbbbbba
18. abbbbbbbababbba ⇒ abbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] bbb, [3/1] abb, [3/2] bba, [3/3] bab, [3/4] aba, [3/5] aab
Length 4:[4/0] abbb, [4/1] bbba, [4/2] bbbb, [4/3] abab, [4/4] baba, [4/5] babb, [4/6] bbab
Length 5:[5/0] abbba, [5/1] abbbb, [5/2] babab, [5/3] babbb, [5/4] ababb, [5/5] ababa, [5/6] bbbab
Length 6:[6/0] babbba, [6/1] ababbb, [6/2] ababab, [6/3] bababb, [6/4] babbbb, [6/5] abbbbb, [6/6] bbabab
Length 7:[7/0] ababbba, [7/1] bababbb, [7/2] bbabbba, [7/3] ababbbb, [7/4] bababab, [7/5] abababb, [7/6] bbbabab

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aababbba=ab⟩.