| Back: | ⟨a, b | aababbba=ab⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababbba ⇒ ab |
| 2. | abbabbba ⇒ aababbbb |
| 3. | abababbba ⇒ abb |
| 4. | abbbabbba ⇒ abababbbb |
| 5. | abbababbba ⇒ abbb |
| 6. | abbbbabbba ⇒ abbababbbb |
| 7. | abbbababbba ⇒ abbbb |
| 8. | abbbbbabbba ⇒ abbbababbbb |
| 9. | aababababbbb ⇒ abbbba |
| 10. | abbabababbbb ⇒ aababbbbbbba |
| 11. | abbbbababbba ⇒ abbbbb |
| 12. | abbbbbbabbba ⇒ abbbbababbbb |
| 13. | abababababbbb ⇒ abbbbba |
| 14. | abbbbbababbba ⇒ abbbbbb |
| 15. | abbababababbbb ⇒ abbbbbba |
| 16. | abbbbbbababbba ⇒ abbbbbbb |
| 17. | abbbababababbbb ⇒ abbbbbbba |
| 18. | abbbbbbbababbba ⇒ abbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 86 | lf:81,ls:5,rf:73,rs:12 |
|---|---|---|---|
| [2/1] | ab | 72 | lf:56,lp:16,rf:28,rp:16,rs:1,re:1,lprp:14 |
| [2/2] | ba | 64 | lf:51,ls:13,rf:15,rs:5 |
| [2/3] | aa | 4 | lf:2,lp:2,rf:2,rp:2 |
| [3/0] | bbb | 54 | lf:49,ls:5,rf:53,rs:11 |
| [3/1] | abb | 46 | lf:32,lp:14,rf:20,rp:14,rs:1,re:1,lprp:11 |
| [3/2] | bba | 40 | lf:27,ls:13,rf:8,rs:5 |
| [3/3] | bab | 38 | lf:38,rf:10 |
| [3/4] | aba | 26 | lf:24,lp:2,rf:7,rp:1 |
| [3/5] | aab | 4 | lf:2,lp:2,rf:2,rp:2 |
| [4/0] | abbb | 38 | lf:28,lp:10,rf:18,rp:12,rs:1,re:1,lprp:8 |
| [4/1] | bbba | 36 | lf:23,ls:13,rf:7,rs:5 |
| [4/2] | bbbb | 26 | lf:21,ls:5,rf:35,rs:10,a:3 |
| [4/3] | abab | 26 | lf:24,lp:2,rf:7,rp:1 |
| [4/4] | baba | 20 | lf:20,rf:4,a:1 |
| [4/5] | babb | 18 | lf:18,rf:6 |
| [4/6] | bbab | 14 | lf:14,rf:3,a:2 |
| [5/0] | abbba | 32 | lf:16,lp:3,ls:13,rf:1,rp:1,lsrp:1 |
| [5/1] | abbbb | 24 | lf:12,lp:7,ls:5,rf:16,rp:10,rs:6,re:1,lprp:5,lsrp:4,lprs:3,a:3 |
| [5/2] | babab | 20 | lf:20,rf:4,a:1 |
| [5/3] | babbb | 18 | lf:18,rf:6 |
| [5/4] | ababb | 13 | lf:13,rf:6 |
| [5/5] | ababa | 13 | lf:11,lp:2,rf:1,rp:1,a:1 |
| [5/6] | bbbab | 10 | lf:10,rf:2,a:3 |
| [6/0] | babbba | 26 | lf:13,ls:13 |
| [6/1] | ababbb | 13 | lf:13,rf:6 |
| [6/2] | ababab | 13 | lf:11,lp:2,rf:1,rp:1,a:1 |
| [6/3] | bababb | 12 | lf:12,rf:4,a:1 |
| [6/4] | babbbb | 10 | lf:5,ls:5,rf:6,rs:5,a:6 |
| [6/5] | abbbbb | 10 | lf:5,lp:5,rf:8,rp:7,rs:1,re:1,lprp:3,a:4 |
| [6/6] | bbabab | 9 | lf:9,rf:3,a:2 |
| [7/0] | ababbba | 16 | lf:8,ls:8 |
| [7/1] | bababbb | 12 | lf:12,rf:4,a:1 |
| [7/2] | bbabbba | 10 | lf:5,ls:5,a:6 |
| [7/3] | ababbbb | 10 | lf:5,ls:5,rf:6,rs:5,a:6 |
| [7/4] | bababab | 8 | lf:8,a:13 |
| [7/5] | abababb | 7 | lf:6,lp:1,rf:1,rp:1,a:1 |
| [7/6] | bbbabab | 6 | lf:6,rf:2,a:3 |
Considering [length 4 / frequency 0] abbb=c.
Rewriting system is complete. See ⟨a, b | aababbba=ab⟩.