Morphocompletion for #1955 ⟨a, b | aabaabba=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaabba ⇒ ab
2. abbaabba ⇒ aabaabbb
3. ababaabba ⇒ abb
4. abbbaabba ⇒ ababaabbb
5. abbabaabba ⇒ abbb
6. abbbbaabba ⇒ abbabaabbb
7. abbbabaabba ⇒ abbbb
8. abbbbbaabba ⇒ abbbabaabbb
9. aabaaabaabbb ⇒ ababba
10. abbaaabaabbb ⇒ aabaabbbabba
11. abbbbabaabba ⇒ abbbbb
12. abbbbbbaabba ⇒ abbbbabaabbb
13. ababaaabaabbb ⇒ abbabba
14. abbbbbabaabba ⇒ abbbbbb
15. abbabaaabaabbb ⇒ abbbabba
16. abbbbbbabaabba ⇒ abbbbbbb
17. abbbabaaabaabbb ⇒ abbbbabba
18. abbbbbbbabaabba ⇒ abbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] abb, [3/1] bba, [3/2] bbb, [3/3] aab, [3/4] baa, [3/5] aba, [3/6] bab
Length 4:[4/0] abba, [4/1] abbb, [4/2] baab, [4/3] aabb, [4/4] abaa, [4/5] bbbb, [4/6] bbba
Length 5:[5/0] aabba, [5/1] baabb, [5/2] abbbb, [5/3] abaab, [5/4] babaa, [5/5] aabbb, [5/6] bbbbb
Length 6:[6/0] baabba, [6/1] abaabb, [6/2] baabbb, [6/3] abbbbb, [6/4] bbabaa, [6/5] babaab, [6/6] aabaab
Length 7:[7/0] abaabba, [7/1] bbaabba, [7/2] abaabbb, [7/3] babaabb, [7/4] aabaabb, [7/5] bbbabaa, [7/6] bbabaab

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aabaabba=ab.