| Back: | ⟨a, b | aabaabba=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabaabba ⇒ ab |
| 2. | abbaabba ⇒ aabaabbb |
| 3. | ababaabba ⇒ abb |
| 4. | abbbaabba ⇒ ababaabbb |
| 5. | abbabaabba ⇒ abbb |
| 6. | abbbbaabba ⇒ abbabaabbb |
| 7. | abbbabaabba ⇒ abbbb |
| 8. | abbbbbaabba ⇒ abbbabaabbb |
| 9. | aabaaabaabbb ⇒ ababba |
| 10. | abbaaabaabbb ⇒ aabaabbbabba |
| 11. | abbbbabaabba ⇒ abbbbb |
| 12. | abbbbbbaabba ⇒ abbbbabaabbb |
| 13. | ababaaabaabbb ⇒ abbabba |
| 14. | abbbbbabaabba ⇒ abbbbbb |
| 15. | abbabaaabaabbb ⇒ abbbabba |
| 16. | abbbbbbabaabba ⇒ abbbbbbb |
| 17. | abbbabaaabaabbb ⇒ abbbbabba |
| 18. | abbbbbbbabaabba ⇒ abbbbbbbb |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa |
|---|---|
| Length 3: | [3/0] abb, [3/1] bba, [3/2] bbb, [3/3] aab, [3/4] baa, [3/5] aba, [3/6] bab |
| Length 4: | [4/0] abba, [4/1] abbb, [4/2] baab, [4/3] aabb, [4/4] abaa, [4/5] bbbb, [4/6] bbba |
| Length 5: | [5/0] aabba, [5/1] baabb, [5/2] abbbb, [5/3] abaab, [5/4] babaa, [5/5] aabbb, [5/6] bbbbb |
| Length 6: | [6/0] baabba, [6/1] abaabb, [6/2] baabbb, [6/3] abbbbb, [6/4] bbabaa, [6/5] babaab, [6/6] aabaab |
| Length 7: | [7/0] abaabba, [7/1] bbaabba, [7/2] abaabbb, [7/3] babaabb, [7/4] aabaabb, [7/5] bbbabaa, [7/6] bbabaab |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aabaabba=ab⟩.