Morphocompletion for #1940 ⟨a, b | aabaaaba=ab⟩

Back:⟨a, b | aabaaaba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaab ⇒ abaaba
2. aabaaaba ⇒ ab
3. ababaab ⇒ abbaaba
4. ababaaaba ⇒ abb
5. abaabaaaaba ⇒ aabab
6. aababab ⇒ abababa
7. aabaaabb ⇒ abbaaaba
8. abbabaab ⇒ abbbaaba
9. abbabaaaba ⇒ abbb
10. abababab ⇒ abbababa
11. aababbab ⇒ ababbaba
12. abbbabaaaba ⇒ abbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] bab, [3/3] baa, [3/4] abb, [3/5] aaa, [3/6] bba
Length 4:[4/0] aaba, [4/1] abab, [4/2] abaa, [4/3] baba, [4/4] baab, [4/5] aaab, [4/6] baaa
Length 5:[5/0] aaaba, [5/1] abaab, [5/2] ababa, [5/3] aabaa, [5/4] abbab, [5/5] abaaa, [5/6] babab
Length 6:[6/0] baaaba, [6/1] ababab, [6/2] abaaab, [6/3] aabaaa, [6/4] abbaba, [6/5] babaab, [6/6] ababaa
Length 7:[7/0] abaaaba, [7/1] abbabaa, [7/2] aabaaab, [7/3] babaaab, [7/4] ababbab, [7/5] abbbaba, [7/6] bababab

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabaaaba=ab⟩.