Morphocompletion for #1932 ⟨a, b | aaabbbba=ab⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbba ⇒ ab
2. ababbbba ⇒ aaabbbbb
3. abaabbbba ⇒ abb
4. abbabbbba ⇒ abaabbbbb
5. abbaabbbba ⇒ abbb
6. abbbabbbba ⇒ abbaabbbbb
7. abbbaabbbba ⇒ abbbb
8. aaabbbaabbbbb ⇒ abbbbba
9. abbbbabbbba ⇒ abbbaabbbbb
10. abbbbaabbbba ⇒ abbbbb
11. abaabbbaabbbbb ⇒ abbbbbba
12. aaabbbbbbbbba ⇒ ababbbaabbbbb
13. abbbbbabbbba ⇒ abbbbaabbbbb
14. abbbbbaabbbba ⇒ abbbbbb
15. abbaabbbaabbbbb ⇒ abbbbbbba
16. abbbbbbabbbba ⇒ abbbbbaabbbbb
17. abbbbbbaabbbba ⇒ abbbbbbb
18. abbbaabbbaabbbbb ⇒ abbbbbbbba
19. abbbbbbbaabbbba ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb117lf:113,ls:4,rf:90,rs:14
[2/1]ab55lf:39,lp:16,rf:26,rp:18,rs:1,re:1,lprp:15
[2/2]ba50lf:35,ls:15,rf:11,rs:4
[2/3]aa23lf:20,lp:3,rf:8,rp:1
[3/0]bbb81lf:77,ls:4,rf:67,rs:13
[3/1]abb49lf:36,lp:13,rf:23,rp:15,rs:1,re:1,lprp:12
[3/2]bba47lf:32,ls:15,rf:9,rs:4
[3/3]aab17lf:17,rf:7
[3/4]baa14lf:14,rf:6,a:1
[3/5]bab6lf:6,rf:1,a:8
[3/6]aba6lf:3,lp:3,rf:2,rp:2,a:1
[4/0]bbbb48lf:44,ls:4,rf:46,rs:12
[4/1]bbba44lf:29,ls:15,rf:8,rs:4
[4/2]abbb43lf:33,lp:10,rf:21,rp:13,rs:1,re:1,lprp:9
[4/3]aabb17lf:17,rf:7
[4/4]baab14lf:14,rf:6,a:1
[4/5]bbaa12lf:12,rf:5,a:2
[4/6]babb6lf:6,rf:1,a:8
[5/0]bbbba37lf:22,ls:15,rf:6,rs:4
[5/1]abbbb33lf:26,lp:7,rf:18,rp:11,rs:1,re:1,lprp:6
[5/2]bbbbb22lf:18,ls:4,rf:28,rs:11,a:4
[5/3]aabbb17lf:17,rf:7
[5/4]baabb14lf:14,rf:6,a:1
[5/5]bbaab12lf:12,rf:5,a:2
[5/6]bbbaa10lf:10,rf:4,a:3
[6/0]abbbba32lf:16,lp:2,ls:14,rf:1,rp:1,lsrp:1
[6/1]abbbbb19lf:10,lp:5,ls:4,rf:16,rp:9,rs:8,re:1,lprp:4,lsrp:4,lprs:2,a:4
[6/2]baabbb14lf:14,rf:6,a:1
[6/3]aabbbb13lf:13,rf:7
[6/4]bbaabb12lf:12,rf:5,a:2
[6/5]bbbaab10lf:10,rf:4,a:3
[6/6]bbbbbb8lf:8,rf:12,rs:3,a:5
[7/0]aabbbba16lf:8,ls:8
[7/1]babbbba12lf:6,ls:6,a:8
[7/2]bbaabbb12lf:12,rf:5,a:2
[7/3]baabbbb11lf:11,rf:6,a:1
[7/4]bbbaabb10lf:10,rf:4,a:3
[7/5]aabbbbb9lf:5,ls:4,rf:7,rs:7,a:8
[7/6]abbbaab8lf:6,lp:2,rf:2,rp:1,a:3

Considering [length 5 / frequency 0] bbbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbbba=ab⟩.