Morphocompletion for #1932 ⟨a, b | aaabbbba=ab

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbbba ⇒ ab
2. ababbbba ⇒ aaabbbbb
3. abaabbbba ⇒ abb
4. abbabbbba ⇒ abaabbbbb
5. abbaabbbba ⇒ abbb
6. abbbabbbba ⇒ abbaabbbbb
7. abbbaabbbba ⇒ abbbb
8. aaabbbaabbbbb ⇒ abbbbba
9. abbbbabbbba ⇒ abbbaabbbbb
10. abbbbaabbbba ⇒ abbbbb
11. abaabbbaabbbbb ⇒ abbbbbba
12. aaabbbbbbbbba ⇒ ababbbaabbbbb
13. abbbbbabbbba ⇒ abbbbaabbbbb
14. abbbbbaabbbba ⇒ abbbbbb
15. abbaabbbaabbbbb ⇒ abbbbbbba
16. abbbbbbabbbba ⇒ abbbbbaabbbbb
17. abbbbbbaabbbba ⇒ abbbbbbb
18. abbbaabbbaabbbbb ⇒ abbbbbbbba
19. abbbbbbbaabbbba ⇒ abbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] bbb, [3/1] abb, [3/2] bba, [3/3] aab, [3/4] baa, [3/5] bab, [3/6] aba
Length 4:[4/0] bbbb, [4/1] bbba, [4/2] abbb, [4/3] aabb, [4/4] baab, [4/5] bbaa, [4/6] babb
Length 5:[5/0] bbbba, [5/1] abbbb, [5/2] bbbbb, [5/3] aabbb, [5/4] baabb, [5/5] bbaab, [5/6] bbbaa
Length 6:[6/0] abbbba, [6/1] abbbbb, [6/2] baabbb, [6/3] aabbbb, [6/4] bbaabb, [6/5] bbbaab, [6/6] bbbbbb
Length 7:[7/0] aabbbba, [7/1] babbbba, [7/2] bbaabbb, [7/3] baabbbb, [7/4] bbbaabb, [7/5] aabbbbb, [7/6] abbbaab

Considering [length 5 / frequency 0] bbbba=c.

Step 2

Rewriting system is complete. See a, b | aaabbbba=ab.