Morphocompletion for #1924 ⟨a, b | aaabbbaa=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaabbbaa ⇒ ab
2. abaabbbaa ⇒ abb
3. aaabbbb ⇒ abbbbaa
4. aaabbbab ⇒ ababbbaa
5. abbaabbbaa ⇒ abbb
6. abaabbbb ⇒ abbbbbaa
7. abaabbbab ⇒ abbabbbaa
8. abbbaabbbaa ⇒ abbbb
9. abbaabbbb ⇒ abbbbbbaa
10. abbaabbbab ⇒ abbbabbbaa
11. abbbbaabbbaa ⇒ abbbbb
12. abbbaabbbb ⇒ abbbbbbbaa
13. abbbaabbbab ⇒ abbbbabbbaa
14. abbbbbaabbbaa ⇒ abbbbbb
15. abbbbaabbbb ⇒ abbbbbbbbaa
16. abbbbaabbbab ⇒ abbbbbabbbaa
17. abbbbbbaabbbaa ⇒ abbbbbbb
18. abbbbbaabbbb ⇒ abbbbbbbbbaa
19. abbbbbaabbbab ⇒ abbbbbbabbbaa
20. abbbbbbbaabbbaa ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb93lf:87,ls:6,rf:88,rs:7
[2/1]ab66lf:43,lp:17,ls:6,rf:26,rp:20,rs:1,re:1,lprp:17,lsrp:6
[2/2]aa42lf:31,lp:3,ls:8,rf:12,rs:12,lprs:2
[2/3]ba31lf:31,rf:18
[3/0]bbb59lf:53,ls:6,rf:64,rs:6
[3/1]abb48lf:34,lp:14,rf:24,rp:18,rs:1,re:1,lprp:14
[3/2]baa33lf:25,ls:8,rf:12,rs:12
[3/3]bba28lf:28,rf:17
[3/4]aab20lf:20
[3/5]bab12lf:6,ls:6,rf:6,a:1
[3/6]aba6lf:3,lp:3,rf:1,rp:1,a:1
[4/0]abbb42lf:31,lp:11,rf:22,rp:16,rs:1,re:1,lprp:11
[4/1]bbaa30lf:22,ls:8,rf:12,rs:12
[4/2]bbbb28lf:22,ls:6,rf:42,rs:5,a:5
[4/3]bbba25lf:25,rf:16
[4/4]aabb20lf:20
[4/5]baab17lf:17,a:2
[4/6]bbab12lf:6,ls:6,rf:5,a:1
[5/0]abbbb28lf:14,lp:8,ls:6,rf:14,rp:14,rs:1,re:1,lprp:8,lsrp:6,a:5
[5/1]bbbaa27lf:19,ls:8,rf:12,rs:12
[5/2]aabbb20lf:20
[5/3]abbba20lf:17,lp:3,rf:7,rp:1
[5/4]baabb17lf:17,a:2
[5/5]bbaab14lf:14,a:3
[5/6]bbbab12lf:6,ls:6,rf:4,a:1
[6/0]abbbaa22lf:11,lp:3,ls:8,rf:6,rs:6,lprs:1
[6/1]baabbb17lf:17,a:2
[6/2]bbaabb14lf:14,a:3
[6/3]aabbba14lf:14
[6/4]aabbbb12lf:6,ls:6,a:10
[6/5]abbbab12lf:6,ls:6,rf:1,rp:1,lsrp:1,a:1
[6/6]bbbaab11lf:11,a:5
[7/0]aabbbaa16lf:8,ls:8
[7/1]bbaabbb14lf:14,a:3
[7/2]aabbbab12lf:6,ls:6,a:1
[7/3]baabbba12lf:12,a:2
[7/4]bbbaabb11lf:11,a:5
[7/5]baabbbb10lf:5,ls:5,a:11
[7/6]bbbbaab8lf:8,a:6

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbbaa=ab⟩.