Morphocompletion for #1924 ⟨a, b | aaabbbaa=ab

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaabbbaa ⇒ ab
2. abaabbbaa ⇒ abb
3. aaabbbb ⇒ abbbbaa
4. aaabbbab ⇒ ababbbaa
5. abbaabbbaa ⇒ abbb
6. abaabbbb ⇒ abbbbbaa
7. abaabbbab ⇒ abbabbbaa
8. abbbaabbbaa ⇒ abbbb
9. abbaabbbb ⇒ abbbbbbaa
10. abbaabbbab ⇒ abbbabbbaa
11. abbbbaabbbaa ⇒ abbbbb
12. abbbaabbbb ⇒ abbbbbbbaa
13. abbbaabbbab ⇒ abbbbabbbaa
14. abbbbbaabbbaa ⇒ abbbbbb
15. abbbbaabbbb ⇒ abbbbbbbbaa
16. abbbbaabbbab ⇒ abbbbbabbbaa
17. abbbbbbaabbbaa ⇒ abbbbbbb
18. abbbbbaabbbb ⇒ abbbbbbbbbaa
19. abbbbbaabbbab ⇒ abbbbbbabbbaa
20. abbbbbbbaabbbaa ⇒ abbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] bbb, [3/1] abb, [3/2] baa, [3/3] bba, [3/4] aab, [3/5] bab, [3/6] aba
Length 4:[4/0] abbb, [4/1] bbaa, [4/2] bbbb, [4/3] bbba, [4/4] aabb, [4/5] baab, [4/6] bbab
Length 5:[5/0] abbbb, [5/1] bbbaa, [5/2] aabbb, [5/3] abbba, [5/4] baabb, [5/5] bbaab, [5/6] bbbab
Length 6:[6/0] abbbaa, [6/1] baabbb, [6/2] bbaabb, [6/3] aabbba, [6/4] aabbbb, [6/5] abbbab, [6/6] bbbaab
Length 7:[7/0] aabbbaa, [7/1] bbaabbb, [7/2] aabbbab, [7/3] baabbba, [7/4] bbbaabb, [7/5] baabbbb, [7/6] bbbbaab

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See a, b | aaabbbaa=ab.