Morphocompletion for #1875 ⟨a, b | aaaabbba=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbba ⇒ ab
2. abaabbba ⇒ aaaabbbb
3. abaaabbba ⇒ abb
4. abbaabbba ⇒ abaaabbbb
5. abbaaabbba ⇒ abbb
6. aaaabbaaabbbb ⇒ ababbba
7. abbbaabbba ⇒ abbaaabbbb
8. abbbaaabbba ⇒ abbbb
9. abaaabbaaabbbb ⇒ abbabbba
10. aaaabbbbabbba ⇒ abaabbaaabbbb
11. abbbbaabbba ⇒ abbbaaabbbb
12. abbbbaaabbba ⇒ abbbbb
13. abbaaabbaaabbbb ⇒ abbbabbba
14. abbbbbaabbba ⇒ abbbbaaabbbb
15. abbbbbaaabbba ⇒ abbbbbb
16. abbbaaabbaaabbbb ⇒ abbbbabbba
17. abbbbbbaaabbba ⇒ abbbbbbb
18. abbbbbbbaaabbba ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb85lf:81,ls:4,rf:67,rs:13
[2/1]ab53lf:38,lp:15,rf:28,rp:17,rs:1,re:1,lprp:14
[2/2]ba48lf:34,ls:14,rf:14,rs:4
[2/3]aa45lf:42,lp:3,rf:14,rp:1
[3/0]bbb50lf:46,ls:4,rf:43,rs:12
[3/1]abb47lf:35,lp:12,rf:24,rp:13,rs:1,re:1,lprp:11
[3/2]bba45lf:31,ls:14,rf:11,rs:4
[3/3]aaa23lf:20,lp:3,rf:7,rp:1
[3/4]aab22lf:22,rf:7
[3/5]baa19lf:19,rf:6,a:1
[3/6]aba6lf:3,lp:3,rf:3,rp:3,a:1
[4/0]bbba38lf:24,ls:14,rf:8,rs:4
[4/1]abbb37lf:28,lp:9,rf:20,rp:10,rs:1,re:1,lprp:8
[4/2]bbbb22lf:18,ls:4,rf:23,rs:11,a:3
[4/3]aabb22lf:22,rf:7
[4/4]aaab17lf:17,rf:6
[4/5]bbaa16lf:16,rf:4,a:2
[4/6]baaa14lf:14,rf:5,a:1
[5/0]abbba34lf:17,lp:3,ls:14,rf:6,rp:2,rs:4,lsrp:1,lprs:1
[5/1]abbbb21lf:11,lp:6,ls:4,rf:13,rp:7,rs:7,re:1,lprp:5,lsrp:1,lprs:2,a:3
[5/2]aabbb18lf:18,rf:6
[5/3]aaabb17lf:17,rf:6
[5/4]baaab14lf:14,rf:5,a:1
[5/5]bbaaa12lf:12,rf:4,a:2
[5/6]abbaa10lf:7,lp:3,rf:2,rp:1,a:2
[6/0]aabbba26lf:13,ls:13
[6/1]baaabb14lf:14,rf:5,a:1
[6/2]aaabbb13lf:13,rf:6
[6/3]bbaaab12lf:12,rf:4,a:2
[6/4]aabbbb9lf:5,ls:4,rf:6,rs:6,a:6
[6/5]abbbbb8lf:4,lp:4,rf:4,rp:4,rs:1,re:1,lprp:3,a:4
[6/6]abbaaa8lf:6,lp:2,rf:2,rp:1,a:2
[7/0]aaabbba16lf:8,ls:8
[7/1]bbaaabb12lf:12,rf:4,a:2
[7/2]baaabbb11lf:11,rf:5,a:1
[7/3]baabbba10lf:5,ls:5,a:6
[7/4]aaabbbb9lf:5,ls:4,rf:6,rs:6,a:6
[7/5]abbaaab8lf:6,lp:2,rf:2,rp:1,a:2
[7/6]bbbaaab6lf:6,rf:2,a:3

Considering [length 4 / frequency 0] bbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaabbba=ab⟩.