Morphocompletion for #1868 ⟨a, b | aaaabbaa=ba⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#	Rule
1.	aaaabbaa ⇒ ba
2.	aaaabbba ⇒ baaabbaa
3.	aaaabbaba ⇒ bba
4.	aaaabbbba ⇒ baaabbaba
5.	aaaabbabba ⇒ bbba
6.	aaaabbbbba ⇒ baaabbabba
7.	aaaabbabbba ⇒ bbbba
8.	aaaabbbbbba ⇒ baaabbabbba
9.	aaaabbabbbba ⇒ bbbbba
10.	aaaabbbbbbba ⇒ baaabbabbbba
11.	aaaabbabbbbba ⇒ bbbbbba
12.	aaaabbbbbbbba ⇒ baaabbabbbbba
13.	aaaabbabbbbbba ⇒ bbbbbbba
14.	aaaabbbbbbbbba ⇒ baaabbabbbbbba
15.	aaaabbabbbbbbba ⇒ bbbbbbbba
16.	aaaabbbbbbbbbba ⇒ baaabbabbbbbbba
17.	aaaabbabbbbbbbba ⇒ bbbbbbbbba
18.	aaaabbbbbbbbbbba ⇒ baaabbabbbbbbbba
19.	aaaabbabbbbbbbbba ⇒ bbbbbbbbbba
20.	aaaabbabbbbbbbbbba ⇒ bbbbbbbbbbba
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] bb, [2/1] aa, [2/2] ba, [2/3] ab
Length 3:	[3/0] bbb, [3/1] aaa, [3/2] bba, [3/3] abb, [3/4] aab, [3/5] bab, [3/6] aba
Length 4:	[4/0] bbbb, [4/1] aaaa, [4/2] bbba, [4/3] aabb, [4/4] aaab, [4/5] abbb, [4/6] abba
Length 5:	[5/0] bbbbb, [5/1] aaaab, [5/2] bbbba, [5/3] aaabb, [5/4] abbbb, [5/5] aabba, [5/6] abbab
Length 6:	[6/0] aaaabb, [6/1] bbbbbb, [6/2] bbbbba, [6/3] abbbbb, [6/4] aaabba, [6/5] aabbab, [6/6] abbabb
Length 7:	[7/0] bbbbbbb, [7/1] bbbbbba, [7/2] aaaabba, [7/3] aaaabbb, [7/4] abbbbbb, [7/5] aaabbab, [7/6] aabbabb

Considering [length 6 / frequency 0] aaaabb=c.

Auxiliary generators:
1. c = aaaabb
Reduction order:
- Left-to-right recursive path with deg(a) = 0; deg(c) = deg(b) = 1, c < b

Rewriting system is complete. See ⟨a, b | aaaabbaa=ba⟩.