Morphocompletion for #1868 ⟨a, b | aaaabbaa=ba⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaabbaa ⇒ ba
2. aaaabbba ⇒ baaabbaa
3. aaaabbaba ⇒ bba
4. aaaabbbba ⇒ baaabbaba
5. aaaabbabba ⇒ bbba
6. aaaabbbbba ⇒ baaabbabba
7. aaaabbabbba ⇒ bbbba
8. aaaabbbbbba ⇒ baaabbabbba
9. aaaabbabbbba ⇒ bbbbba
10. aaaabbbbbbba ⇒ baaabbabbbba
11. aaaabbabbbbba ⇒ bbbbbba
12. aaaabbbbbbbba ⇒ baaabbabbbbba
13. aaaabbabbbbbba ⇒ bbbbbbba
14. aaaabbbbbbbbba ⇒ baaabbabbbbbba
15. aaaabbabbbbbbba ⇒ bbbbbbbba
16. aaaabbbbbbbbbba ⇒ baaabbabbbbbbba
17. aaaabbabbbbbbbba ⇒ bbbbbbbbba
18. aaaabbbbbbbbbbba ⇒ baaabbabbbbbbbba
19. aaaabbabbbbbbbbba ⇒ bbbbbbbbbba
20. aaaabbabbbbbbbbbba ⇒ bbbbbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb110lf:110,rf:92,rp:10
[2/1]aa82lf:61,lp:20,ls:1,rf:19,rs:1,lprs:1
[2/2]ba49lf:30,ls:19,rf:37,rp:10,rs:19,re:1,lsrp:9,lsrs:18
[2/3]ab30lf:30,rf:17
[3/0]bbb81lf:81,rf:66,rp:9,a:1
[3/1]aaa60lf:40,lp:20,rf:9
[3/2]bba47lf:29,ls:18,rf:26,rp:1,rs:17,re:1,lsrs:16
[3/3]abb29lf:29,rf:16
[3/4]aab20lf:20,rf:9
[3/5]bab10lf:10,rf:8,a:2
[3/6]aba2lf:1,ls:1,rf:1,rs:1,a:2
[4/0]bbbb64lf:64,rf:51,rp:8,a:3
[4/1]aaaa40lf:20,lp:20
[4/2]bbba34lf:17,ls:17,rf:15,rp:1,rs:15,re:1,lsrs:14,a:1
[4/3]aabb20lf:20,rf:9
[4/4]aaab20lf:20,rf:9
[4/5]abbb17lf:17,rf:6,a:1
[4/6]abba13lf:12,ls:1,rf:10,rs:1
[5/0]bbbbb49lf:49,rf:38,rp:7,a:6
[5/1]aaaab40lf:20,lp:20
[5/2]bbbba30lf:15,ls:15,rf:13,rp:1,rs:13,re:1,lsrs:12,a:3
[5/3]aaabb20lf:20,rf:9
[5/4]abbbb15lf:15,rf:5,a:3
[5/5]aabba11lf:11,rf:9
[5/6]abbab10lf:10,rf:8,a:2
[6/0]aaaabb40lf:20,lp:20
[6/1]bbbbbb36lf:36,rf:27,rp:6,a:8
[6/2]bbbbba26lf:13,ls:13,rf:11,rp:1,rs:11,re:1,lsrs:10,a:6
[6/3]abbbbb13lf:13,rf:4,a:6
[6/4]aaabba11lf:11,rf:9
[6/5]aabbab10lf:10,rf:8,a:2
[6/6]abbabb9lf:9,rf:7,a:4
[7/0]bbbbbbb25lf:25,rf:18,rp:5,a:10
[7/1]bbbbbba22lf:11,ls:11,rf:9,rp:1,rs:9,re:1,lsrs:8,a:8
[7/2]aaaabba22lf:11,lp:11
[7/3]aaaabbb18lf:9,lp:9,a:1
[7/4]abbbbbb11lf:11,rf:3,a:9
[7/5]aaabbab10lf:10,rf:8,a:2
[7/6]aabbabb9lf:9,rf:7,a:4

Considering [length 6 / frequency 0] aaaabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaabbaa=ba⟩.