Morphocompletion for #1867 ⟨a, b | aaaabbaa=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaabbaa ⇒ ab
2. abaaabbaa ⇒ abb
3. aaaabbb ⇒ ababbaa
4. aaaabbab ⇒ abaabbaa
5. abbaaabbaa ⇒ abbb
6. abaaabbb ⇒ abbabbaa
7. abaaabbab ⇒ abbaabbaa
8. abbbaaabbaa ⇒ abbbb
9. abbaaabbb ⇒ abbbabbaa
10. abbaaabbab ⇒ abbbaabbaa
11. abbbbaaabbaa ⇒ abbbbb
12. abbbaaabbb ⇒ abbbbabbaa
13. abbbaaabbab ⇒ abbbbaabbaa
14. abbbbbaaabbaa ⇒ abbbbbb
15. abbbbaaabbb ⇒ abbbbbabbaa
16. abbbbaaabbab ⇒ abbbbbaabbaa
17. abbbbbbaaabbaa ⇒ abbbbbbb
18. abbbbbaaabbb ⇒ abbbbbbabbaa
19. abbbbbaaabbab ⇒ abbbbbbaabbaa
20. abbbbbbbaaabbaa ⇒ abbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] abb, [3/1] bbb, [3/2] baa, [3/3] bba, [3/4] aaa, [3/5] aab, [3/6] bab
Length 4:[4/0] abbb, [4/1] bbaa, [4/2] aabb, [4/3] abba, [4/4] aaab, [4/5] baaa, [4/6] bbbb
Length 5:[5/0] abbaa, [5/1] aaabb, [5/2] baaab, [5/3] abbbb, [5/4] aabba, [5/5] bbaaa, [5/6] aabbb
Length 6:[6/0] baaabb, [6/1] aabbaa, [6/2] bbaaab, [6/3] aaabba, [6/4] aaabbb, [6/5] aabbab, [6/6] bbbaaa
Length 7:[7/0] aaabbaa, [7/1] bbaaabb, [7/2] aaabbab, [7/3] baaabba, [7/4] bbbaaab, [7/5] baaabbb, [7/6] bbbbaaa

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aaaabbaa=ab.