| Back: | ⟨a, b | aaaabbaa=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | aaaabbaa ⇒ ab |
| 2. | abaaabbaa ⇒ abb |
| 3. | aaaabbb ⇒ ababbaa |
| 4. | aaaabbab ⇒ abaabbaa |
| 5. | abbaaabbaa ⇒ abbb |
| 6. | abaaabbb ⇒ abbabbaa |
| 7. | abaaabbab ⇒ abbaabbaa |
| 8. | abbbaaabbaa ⇒ abbbb |
| 9. | abbaaabbb ⇒ abbbabbaa |
| 10. | abbaaabbab ⇒ abbbaabbaa |
| 11. | abbbbaaabbaa ⇒ abbbbb |
| 12. | abbbaaabbb ⇒ abbbbabbaa |
| 13. | abbbaaabbab ⇒ abbbbaabbaa |
| 14. | abbbbbaaabbaa ⇒ abbbbbb |
| 15. | abbbbaaabbb ⇒ abbbbbabbaa |
| 16. | abbbbaaabbab ⇒ abbbbbaabbaa |
| 17. | abbbbbbaaabbaa ⇒ abbbbbbb |
| 18. | abbbbbaaabbb ⇒ abbbbbbabbaa |
| 19. | abbbbbaaabbab ⇒ abbbbbbaabbaa |
| 20. | abbbbbbbaaabbaa ⇒ abbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 73 | lf:67,ls:6,rf:70,rs:7 |
|---|---|---|---|
| [2/1] | ab | 66 | lf:43,lp:17,ls:6,rf:32,rp:20,rs:1,re:1,lprp:17,lsrp:6 |
| [2/2] | aa | 62 | lf:51,lp:3,ls:8,rf:18,rs:12,lprs:2 |
| [2/3] | ba | 31 | lf:31,rf:24 |
| [3/0] | abb | 48 | lf:34,lp:14,rf:29,rp:17,rs:1,re:1,lprp:14 |
| [3/1] | bbb | 39 | lf:33,ls:6,rf:41,rs:6,a:3 |
| [3/2] | baa | 33 | lf:25,ls:8,rf:18,rs:12 |
| [3/3] | bba | 28 | lf:28,rf:22 |
| [3/4] | aaa | 26 | lf:23,lp:3 |
| [3/5] | aab | 20 | lf:20,rf:6 |
| [3/6] | bab | 12 | lf:6,ls:6,rf:6,a:1 |
| [4/0] | abbb | 34 | lf:17,lp:11,ls:6,rf:14,rp:14,rs:1,re:1,lprp:11,lsrp:4,a:3 |
| [4/1] | bbaa | 30 | lf:22,ls:8,rf:17,rs:12 |
| [4/2] | aabb | 20 | lf:20,rf:6 |
| [4/3] | abba | 20 | lf:17,lp:3,rf:14,rp:2 |
| [4/4] | aaab | 20 | lf:20 |
| [4/5] | baaa | 17 | lf:17,a:2 |
| [4/6] | bbbb | 16 | lf:16,rf:27,rs:5,a:5 |
| [5/0] | abbaa | 22 | lf:11,lp:3,ls:8,rf:13,rp:1,rs:12,lprs:2 |
| [5/1] | aaabb | 20 | lf:20 |
| [5/2] | baaab | 17 | lf:17,a:2 |
| [5/3] | abbbb | 16 | lf:8,lp:8,rf:11,rp:11,rs:1,re:1,lprp:8,a:5 |
| [5/4] | aabba | 14 | lf:14,rf:6 |
| [5/5] | bbaaa | 14 | lf:14,a:3 |
| [5/6] | aabbb | 12 | lf:6,ls:6,a:6 |
| [6/0] | baaabb | 17 | lf:17,a:2 |
| [6/1] | aabbaa | 16 | lf:8,ls:8,rf:6,rs:6 |
| [6/2] | bbaaab | 14 | lf:14,a:3 |
| [6/3] | aaabba | 14 | lf:14 |
| [6/4] | aaabbb | 12 | lf:6,ls:6,a:6 |
| [6/5] | aabbab | 12 | lf:6,ls:6,a:1 |
| [6/6] | bbbaaa | 11 | lf:11,a:5 |
| [7/0] | aaabbaa | 16 | lf:8,ls:8 |
| [7/1] | bbaaabb | 14 | lf:14,a:3 |
| [7/2] | aaabbab | 12 | lf:6,ls:6,a:1 |
| [7/3] | baaabba | 12 | lf:12,a:2 |
| [7/4] | bbbaaab | 11 | lf:11,a:5 |
| [7/5] | baaabbb | 10 | lf:5,ls:5,a:7 |
| [7/6] | bbbbaaa | 8 | lf:8,a:8 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aaaabbaa=ab⟩.