Morphocompletion for #1844 ⟨a, b | aaaaabba=ba⟩

Solved by morph:7/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaaabba ⇒ ba
2. aaaaabbba ⇒ bba
3. aaaaabbbba ⇒ bbba
4. aaaaabbbbba ⇒ bbbba
5. aaaaabbbbbba ⇒ bbbbba
6. aaaaabbbbbbba ⇒ bbbbbba
7. aaaaabbbbbbbba ⇒ bbbbbbba
8. aaaaabbbbbbbbba ⇒ bbbbbbbba
9. aaaaabbbbbbbbbba ⇒ bbbbbbbbba
10. aaaaabbbbbbbbbbba ⇒ bbbbbbbbbba
11. aaaaabbbbbbbbbbbba ⇒ bbbbbbbbbbba
12. aaaaabbbbbbbbbbbbba ⇒ bbbbbbbbbbbba
13. aaaaabbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbba
14. aaaaabbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbba
15. aaaaabbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbba
16. aaaaabbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbba
17. aaaaabbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbba
18. aaaaabbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbba
19. aaaaabbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbba
20. aaaaabbbbbbbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb210lf:210,rf:190,rp:19
[2/1]aa100lf:80,lp:20
[2/2]ba40lf:20,ls:20,rf:20,rp:1,rs:20,re:1,lsrp:1,lsrs:20
[2/3]ab20lf:20
[3/0]bbb190lf:190,rf:171,rp:18,a:1
[3/1]aaa80lf:60,lp:20
[3/2]bba40lf:20,ls:20,rf:19,rp:1,rs:19,re:1,lsrp:1,lsrs:19
[3/3]abb20lf:20
[3/4]aab20lf:20
[4/0]bbbb171lf:171,rf:153,rp:17,a:2
[4/1]aaaa60lf:40,lp:20
[4/2]bbba38lf:19,ls:19,rf:18,rp:1,rs:18,re:1,lsrp:1,lsrs:18,a:1
[4/3]aabb20lf:20
[4/4]aaab20lf:20
[4/5]abbb19lf:19,a:1
[4/6]abba2lf:1,ls:1
[5/0]bbbbb153lf:153,rf:136,rp:16,a:3
[5/1]aaaaa40lf:20,lp:20
[5/2]bbbba36lf:18,ls:18,rf:17,rp:1,rs:17,re:1,lsrp:1,lsrs:17,a:2
[5/3]aaabb20lf:20
[5/4]aaaab20lf:20
[5/5]aabbb19lf:19,a:1
[5/6]abbbb18lf:18,a:2
[6/0]bbbbbb136lf:136,rf:120,rp:15,a:4
[6/1]aaaaab40lf:20,lp:20
[6/2]bbbbba34lf:17,ls:17,rf:16,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:3
[6/3]aaaabb20lf:20
[6/4]aaabbb19lf:19,a:1
[6/5]aabbbb18lf:18,a:2
[6/6]abbbbb17lf:17,a:3
[7/0]bbbbbbb120lf:120,rf:105,rp:14,a:5
[7/1]aaaaabb40lf:20,lp:20
[7/2]bbbbbba32lf:16,ls:16,rf:15,rp:1,rs:15,re:1,lsrp:1,lsrs:15,a:4
[7/3]aaaabbb19lf:19,a:1
[7/4]aaabbbb18lf:18,a:2
[7/5]aabbbbb17lf:17,a:3
[7/6]abbbbbb16lf:16,a:4

Considering [length 7 / frequency 1] aaaaabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaaabba=ba⟩.