Morphocompletion for #1843 ⟨a, b | aaaaabba=ab⟩

Back:⟨a, b | aaaaabba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaabba ⇒ ab
2. abaaabba ⇒ aaaaabbb
3. abaaaabba ⇒ abb
4. aaaaabaaaabbb ⇒ abaabba
5. abbaaabba ⇒ abaaaabbb
6. abbaaaabba ⇒ abbb
7. abaaaabaaaabbb ⇒ abbaabba
8. abbbaaabba ⇒ abbaaaabbb
9. abbbaaaabba ⇒ abbbb
10. abbaaaabaaaabbb ⇒ abbbaabba
11. abbbbaaabba ⇒ abbbaaaabbb
12. abbbbaaaabba ⇒ abbbbb
13. abbbbbaaabba ⇒ abbbbaaaabbb
14. abbbbbaaaabba ⇒ abbbbbb
15. abbbbbbaaaabba ⇒ abbbbbbb
16. abbbbbbbaaaabba ⇒ abbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] bb, [2/2] ab, [2/3] ba
Length 3:[3/0] abb, [3/1] bba, [3/2] aaa, [3/3] bbb, [3/4] aab, [3/5] baa, [3/6] aba
Length 4:[4/0] abba, [4/1] abbb, [4/2] aaab, [4/3] aaaa, [4/4] baaa, [4/5] aabb, [4/6] bbbb
Length 5:[5/0] aabba, [5/1] aaabb, [5/2] aaaab, [5/3] abbbb, [5/4] baaaa, [5/5] bbaaa, [5/6] abaaa
Length 6:[6/0] aaabba, [6/1] baaaab, [6/2] aaaabb, [6/3] abbbbb, [6/4] bbbaaa, [6/5] bbaaaa, [6/6] abaaaa
Length 7:[7/0] aaaabba, [7/1] baaabba, [7/2] baaaabb, [7/3] bbaaaab, [7/4] abaaaab, [7/5] bbbbaaa, [7/6] aaaabbb

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaaabba=ab⟩.