Morphocompletion for #1843 ⟨a, b | aaaaabba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaabba ⇒ ab
2. abaaabba ⇒ aaaaabbb
3. abaaaabba ⇒ abb
4. aaaaabaaaabbb ⇒ abaabba
5. abbaaabba ⇒ abaaaabbb
6. abbaaaabba ⇒ abbb
7. abaaaabaaaabbb ⇒ abbaabba
8. abbbaaabba ⇒ abbaaaabbb
9. abbbaaaabba ⇒ abbbb
10. abbaaaabaaaabbb ⇒ abbbaabba
11. abbbbaaabba ⇒ abbbaaaabbb
12. abbbbaaaabba ⇒ abbbbb
13. abbbbbaaabba ⇒ abbbbaaaabbb
14. abbbbbaaaabba ⇒ abbbbbb
15. abbbbbbaaaabba ⇒ abbbbbbb
16. abbbbbbbaaaabba ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa56lf:54,lp:2,rf:19,rp:1
[2/1]bb54lf:51,ls:3,rf:50,rs:12
[2/2]ab47lf:33,lp:14,rf:23,rp:15,rs:1,re:1,lprp:13
[2/3]ba43lf:30,ls:13,rf:10,rs:3
[3/0]abb38lf:27,lp:11,rf:20,rp:12,rs:1,re:1,lprp:10
[3/1]bba37lf:24,ls:13,rf:8,rs:3
[3/2]aaa37lf:35,lp:2,rf:11,rp:1
[3/3]bbb27lf:24,ls:3,rf:30,rs:11,a:2
[3/4]aab19lf:19,rf:8
[3/5]baa17lf:17,rf:7,a:1
[3/6]aba9lf:6,lp:3,rf:2,rp:2,a:1
[4/0]abba32lf:16,lp:3,ls:13,rf:5,rp:2,rs:3,lsrp:1,lprs:1
[4/1]abbb22lf:11,lp:8,ls:3,rf:14,rp:9,rs:6,re:1,lprp:7,lsrp:1,lprs:3,a:2
[4/2]aaab19lf:19,rf:5
[4/3]aaaa18lf:16,lp:2,rf:6,rp:1
[4/4]baaa17lf:17,rf:4,a:1
[4/5]aabb16lf:16,rf:8
[4/6]bbbb13lf:13,rf:16,rs:5,a:3
[5/0]aabba26lf:13,ls:13,rf:3,rs:3
[5/1]aaabb16lf:16,rf:5
[5/2]aaaab14lf:14,rf:5
[5/3]abbbb12lf:6,lp:6,rf:6,rp:6,rs:1,re:1,lprp:5,a:3
[5/4]baaaa12lf:12,rf:4,a:1
[5/5]bbaaa11lf:11,rf:3,a:2
[5/6]abaaa9lf:6,lp:3,rf:1,rp:1,a:1
[6/0]aaabba26lf:13,ls:13
[6/1]baaaab12lf:12,rf:4,a:1
[6/2]aaaabb11lf:11,rf:5
[6/3]abbbbb8lf:4,lp:4,rf:4,rp:4,rs:1,re:1,lprp:3,a:6
[6/4]bbbaaa8lf:8,rf:2,a:3
[6/5]bbaaaa7lf:7,rf:3,a:2
[6/6]abaaaa7lf:5,lp:2,rf:1,rp:1,a:1
[7/0]aaaabba16lf:8,ls:8
[7/1]baaabba10lf:5,ls:5,a:4
[7/2]baaaabb10lf:10,rf:4,a:1
[7/3]bbaaaab7lf:7,rf:3,a:2
[7/4]abaaaab7lf:5,lp:2,rf:1,rp:1,a:1
[7/5]bbbbaaa6lf:6,rf:1,a:6
[7/6]aaaabbb6lf:3,ls:3,rf:5,rs:5,a:4

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaaabba=ab⟩.