| Back: | ⟨a, b | abbababba=b⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abbabb ⇒ bbabba |
| 2. | abbababba ⇒ b |
| 3. | abbbbabba ⇒ bbabbaabb |
| 4. | abbababbb ⇒ bbbababba |
| 5. | abbabaabbb ⇒ bbbaababba |
| 6. | abbabaaabbb ⇒ bbbaaababba |
| 7. | bbabbaababba ⇒ abbb |
| 8. | bbabbaaababba ⇒ aabbb |
| 9. | bbabbaaaababba ⇒ aaabbb |
| 10. | bbabbaaaaababba ⇒ aaaabbb |
| 11. | bbabbaabbbabba ⇒ abbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 43 | lf:34,lp:5,ls:4,rf:26,rp:5,rs:6,lsrp:4,lprs:5 |
|---|---|---|---|
| [2/1] | ba | 39 | lf:32,ls:7,rf:13,rs:4 |
| [2/2] | ab | 37 | lf:31,lp:6,rf:14,rp:2 |
| [2/3] | aa | 14 | lf:14,rf:10,rp:3,a:3 |
| [3/0] | bba | 36 | lf:24,lp:5,ls:7,rf:10,rp:2,rs:4,lsrp:1 |
| [3/1] | abb | 30 | lf:23,lp:6,ls:1,rf:11,rp:2,rs:1,lprs:1 |
| [3/2] | bab | 18 | lf:18,rf:6 |
| [3/3] | bbb | 9 | lf:6,ls:3,rf:10,rp:3,rs:5,lsrp:3,a:2 |
| [3/4] | aba | 8 | lf:8,rf:3 |
| [3/5] | aab | 7 | lf:7,rf:6,rp:1,a:3 |
| [3/6] | baa | 7 | lf:7,rf:3,a:3 |
| [4/0] | abba | 29 | lf:17,lp:5,ls:7,rf:5,rs:4,lprs:4 |
| [4/1] | bbab | 17 | lf:12,lp:5,rf:3,rp:2 |
| [4/2] | babb | 15 | lf:14,ls:1,rf:5 |
| [4/3] | abbb | 9 | lf:5,lp:1,ls:3,rf:5,rp:2,rs:4,re:1,a:2 |
| [4/4] | abab | 6 | lf:6,rf:3 |
| [4/5] | bbaa | 5 | lf:5,rf:3,a:3 |
| [4/6] | baba | 4 | lf:4,rf:1 |
| [5/0] | babba | 19 | lf:12,ls:7,rf:5,rs:4 |
| [5/1] | bbabb | 14 | lf:8,lp:5,ls:1,rf:2,rp:2,lsrp:10,a:1 |
| [5/2] | abbab | 10 | lf:5,lp:5 |
| [5/3] | ababb | 6 | lf:6,rf:3 |
| [5/4] | aabbb | 5 | lf:3,ls:2,rf:3,rp:1,rs:3,re:1,a:5 |
| [5/5] | abbaa | 5 | lf:5,rf:1,a:3 |
| [5/6] | bbaba | 4 | lf:4,rf:1 |
| [6/0] | bbabba | 14 | lf:7,lp:5,ls:2,rf:2,rp:2,rs:1,re:1,lsrp:1,a:1 |
| [6/1] | ababba | 10 | lf:5,ls:5,rf:3,rs:3 |
| [6/2] | abbaba | 8 | lf:4,lp:4 |
| [6/3] | babbaa | 5 | lf:5,rf:1,a:3 |
| [6/4] | aababb | 4 | lf:4,rf:2,a:3 |
| [6/5] | baabbb | 3 | lf:2,ls:1,a:6 |
| [6/6] | aaabab | 3 | lf:3,rf:1,a:5 |
| [7/0] | bbabbaa | 10 | lf:5,lp:5,rf:1,rp:1,a:3 |
| [7/1] | aababba | 8 | lf:4,ls:4,rf:2,rs:2,a:3 |
| [7/2] | bbbabba | 4 | lf:2,ls:2,a:4 |
| [7/3] | abbabab | 4 | lf:2,lp:2 |
| [7/4] | abbabaa | 4 | lf:2,lp:2,a:13 |
| [7/5] | aaababb | 3 | lf:3,rf:1,a:5 |
| [7/6] | babbaaa | 3 | lf:3,a:5 |
Considering [length 4 / frequency 0] abba=c.
Rewriting system is complete. See ⟨a, b | abbababba=b⟩.