Morphocompletion for #1810 ⟨a, b | abbababba=b

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbabb ⇒ bbabba
2. abbababba ⇒ b
3. abbbbabba ⇒ bbabbaabb
4. abbababbb ⇒ bbbababba
5. abbabaabbb ⇒ bbbaababba
6. abbabaaabbb ⇒ bbbaaababba
7. bbabbaababba ⇒ abbb
8. bbabbaaababba ⇒ aabbb
9. bbabbaaaababba ⇒ aaabbb
10. bbabbaaaaababba ⇒ aaaabbb
11. bbabbaabbbabba ⇒ abbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ba, [2/2] ab, [2/3] aa
Length 3:[3/0] bba, [3/1] abb, [3/2] bab, [3/3] bbb, [3/4] aba, [3/5] aab, [3/6] baa
Length 4:[4/0] abba, [4/1] bbab, [4/2] babb, [4/3] abbb, [4/4] abab, [4/5] bbaa, [4/6] baba
Length 5:[5/0] babba, [5/1] bbabb, [5/2] abbab, [5/3] ababb, [5/4] aabbb, [5/5] abbaa, [5/6] bbaba
Length 6:[6/0] bbabba, [6/1] ababba, [6/2] abbaba, [6/3] babbaa, [6/4] aababb, [6/5] baabbb, [6/6] aaabab
Length 7:[7/0] bbabbaa, [7/1] aababba, [7/2] bbbabba, [7/3] abbabab, [7/4] abbabaa, [7/5] aaababb, [7/6] babbaaa

Considering [length 4 / frequency 0] abba=c.

Step 2

Rewriting system is complete. See a, b | abbababba=b.