Morphocompletion for #1807 ⟨a, b | abbabaaab=a

Solved by morph:2/1,2/0,5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbb ⇒ abbabaa
2. aabaaab ⇒ ababaaa
3. ababaaab ⇒ abbabaaa
4. abbabaaab ⇒ a
5. aaaababbbab ⇒ abbabaababa
6. aaaabbaaabbb ⇒ abbabaababaa
7. abbabaababaaa ⇒ aaaab
8. abbabaabbabaaa ⇒ aaaabb
9. ababaaaaaab ⇒ aabaababaaa
10. abbabaaaaaab ⇒ ababaababaaa
11. aaaababbbbabaaa ⇒ aaaabab
12. abbabaabababbabaa ⇒ aaaababbb
...

Collecting factors up to length 7, frequency 3:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba
Length 3:[3/0] aaa, [3/1] aba, [3/2] aab
Length 4:[4/0] aaab, [4/1] aaaa, [4/2] abaa
Length 5:[5/0] aaaab, [5/1] babaa, [5/2] abbab
Length 6:[6/0] abbaba, [6/1] babaaa, [6/2] bbabaa

Considering [length 2 / frequency 1] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. cbcaac ⇒ a
3. ccaacb ⇒ a
4. ccaaccbb ⇒ cbccbcaa
5. ccaacccbbc ⇒ cbccbcacca
6. cbcaaa ⇒ ccaac
7. cbccbcacccbcaa ⇒ ccaacccbb
8. acaac ⇒ ccaaa
9. cbccbcaccaac ⇒ ccaaccb
10. aaacb ⇒ cbcaccaac
11. ccaacacbb ⇒ cbcacbcaa
12. aaaccbb ⇒ cbcacccbcaa
13. cbcaccaaa ⇒ aaac
14. ccaaccaac ⇒ acaaa
15. cbcacbcaccaac ⇒ ccaacacb
16. cbcacccbcaccaac ⇒ aaaccb
17. ccaaaaac ⇒ acaccaaa
18. cbcaccacbcaccaac ⇒ aaacacb
19. cbcaccaaccaaa ⇒ aaaccaac
20. acaaaaac ⇒ ccaaccaccaaa
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] ac, [2/1] aa, [2/2] cb, [2/3] ca, [2/4] cc
Length 3:[3/0] aac, [3/1] cbc, [3/2] cca, [3/3] caa, [3/4] aaa
Length 4:[4/0] caac, [4/1] ccaa, [4/2] cbca, [4/3] bcac, [4/4] acca
Length 5:[5/0] ccaac, [5/1] cbcac, [5/2] bcacc, [5/3] accaa, [5/4] cacca

Considering [length 2 / frequency 0] ac=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. cbcad ⇒ a
3. dadb ⇒ ccad
4. dcadb ⇒ dbcad
5. dbcadb ⇒ d
6. ccadb ⇒ a
7. daddb ⇒ ccdbcdcad
8. dbcaddb ⇒ cbcdcad
9. ac ⇒ d
10. dadc ⇒ ccdbcadd
11. dcadc ⇒ dbcdbcadd
12. dbcadc ⇒ ad
13. ccadc ⇒ cbcdbcadd
14. aa ⇒ dbcad
15. dbcdbcada ⇒ dcad
16. ccdbcada ⇒ dad
17. cbcdbcada ⇒ ccad
18. cbcdcdbcada ⇒ dbcadd
19. adad ⇒ dcdbcada
20. adbcad ⇒ dbcada
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] db, [2/1] ad, [2/2] da, [2/3] ca, [2/4] dc
Length 3:[3/0] cad, [3/1] dbc, [3/2] ada, [3/3] adb, [3/4] bca
Length 4:[4/0] bcad, [4/1] dbca, [4/2] cada, [4/3] cadc, [4/4] cadb
Length 5:[5/0] dbcad, [5/1] bcada, [5/2] cdbca, [5/3] adbca, [5/4] bcadc

Considering [length 5 / frequency 1] bcada=e.

Step 4

Rewriting system is complete. See a, b | abbabaaab=a.