| Back: | ⟨a, b | abbaabaab=b⟩ |
|---|
Solved by morph:2/0,4/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaabbb ⇒ baabab |
| 2. | aaabbab ⇒ baabaab |
| 3. | abbaabb ⇒ bbaabab |
| 4. | abbaabab ⇒ bbaabaab |
| 5. | abbaabaab ⇒ b |
| 6. | abbbaabab ⇒ baaababbb |
| 7. | bbaababaabab ⇒ abbb |
| 8. | bbaababaabaab ⇒ abbab |
| 9. | bbaabaabaabab ⇒ aabbb |
| 10. | bbaabaabaabaab ⇒ aabbab |
| 11. | abbbbaabaab ⇒ bbaababaabb |
| 12. | bbaabaaaababbb ⇒ ababbb |
| 13. | baababaababaabab ⇒ aaababbb |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb |
|---|---|
| Length 3: | [3/0] aab, [3/1] baa, [3/2] aba, [3/3] bab |
| Length 4: | [4/0] baab, [4/1] aaba, [4/2] abab, [4/3] bbaa |
| Length 5: | [5/0] baaba, [5/1] abaab, [5/2] bbaab, [5/3] aabab |
| Length 6: | [6/0] baabab, [6/1] bbaaba, [6/2] aabaab, [6/3] baabaa |
Considering [length 2 / frequency 0] ab=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | ab ⇒ c |
| 2. | cbacac ⇒ b |
| 3. | acbc ⇒ cbaccacac |
| 4. | acbacc ⇒ b |
| 5. | accbc ⇒ cbaccaccaccacac |
| 6. | accbacc ⇒ cbaccaccacac |
| 7. | bbacac ⇒ cbacc |
| 8. | bbaccacac ⇒ cbc |
| 9. | bbaccaccacac ⇒ ccbacc |
| 10. | bbaccaccaccacac ⇒ ccbc |
| 11. | cbb ⇒ bbaccacc |
| 12. | cbcbaccacac ⇒ bbaccc |
| 13. | cbacb ⇒ bbacc |
| 14. | cbaccbaccacac ⇒ bbc |
| 15. | bbb ⇒ cbaccbaccacc |
| 16. | bbacb ⇒ cbaccbacc |
| 17. | bbaccb ⇒ cbcbaccacc |
| 18. | bbaccacb ⇒ cbcbacc |
| 19. | cbcbaccacb ⇒ bbacccbacc |
| 20. | cbcbaccaccacacacb ⇒ bbcbacc |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] ac, [2/1] cb, [2/2] ca, [2/3] bb, [2/4] cc, [2/5] ba, [2/6] bc |
|---|---|
| Length 3: | [3/0] cac, [3/1] acc, [3/2] bac, [3/3] bba, [3/4] acb, [3/5] cba, [3/6] cca |
| Length 4: | [4/0] acac, [4/1] bbac, [4/2] bacc, [4/3] cbac, [4/4] ccac, [4/5] acca, [4/6] accb |
| Length 5: | [5/0] cacac, [5/1] accac, [5/2] bbacc, [5/3] cbacc, [5/4] bacca, [5/5] cbcba, [5/6] ccaca |
Considering [length 4 / frequency 1] bbac=d.
Rewriting system is complete. See ⟨a, b | abbaabaab=b⟩.