Morphocompletion for #1804 ⟨a, b | abbaabaab=b⟩

Solved by morph:2/0,4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbb ⇒ baabab
2. aaabbab ⇒ baabaab
3. abbaabb ⇒ bbaabab
4. abbaabab ⇒ bbaabaab
5. abbaabaab ⇒ b
6. abbbaabab ⇒ baaababbb
7. bbaababaabab ⇒ abbb
8. bbaababaabaab ⇒ abbab
9. bbaabaabaabab ⇒ aabbb
10. bbaabaabaabaab ⇒ aabbab
11. abbbbaabaab ⇒ bbaababaabb
12. bbaabaaaababbb ⇒ ababbb
13. baababaababaabab ⇒ aaababbb
...

Collecting factors up to length 7 / frequency 4:

[2/0]ab57lf:42,lp:5,ls:10,rf:23,rp:3,rs:6,lsrp:2,lprs:2,lsrs:4
[2/1]ba36lf:35,lp:1,rf:17,rp:3
[2/2]aa32lf:30,lp:2,rf:14,rp:3
[2/3]bb27lf:19,lp:5,ls:3,rf:16,rp:3,rs:6,lsrp:1,lprs:3,lsrs:1
[3/0]aab30lf:26,ls:4,rf:12,rp:2,rs:2,lsrp:1
[3/1]baa25lf:24,lp:1,rf:9,rp:3
[3/2]aba23lf:23,rf:9,rp:1
[3/3]bab17lf:11,ls:6,rf:8,rs:4,a:1
[4/0]baab28lf:23,lp:1,ls:4,rf:8,rp:2,rs:2
[4/1]aaba19lf:19,rf:7
[4/2]abab15lf:10,ls:5,rf:6,rp:1,rs:2,a:1
[4/3]bbaa15lf:10,lp:5,rf:3,rp:3
[5/0]baaba19lf:18,lp:1,rf:5,rp:2
[5/1]abaab16lf:12,ls:4,rf:3,rs:2
[5/2]bbaab15lf:10,lp:5,rf:3,rp:3
[5/3]aabab15lf:10,ls:5,rf:5,rs:2,a:1
[6/0]baabab15lf:9,lp:1,ls:5,rf:3,rp:1,rs:2,re:1,a:1
[6/1]bbaaba14lf:9,lp:5,rf:3,rp:3
[6/2]aabaab12lf:8,ls:4,rf:2,rs:2
[6/3]baabaa9lf:9,rf:2,rp:1

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. cbacac ⇒ b
3. acbc ⇒ cbaccacac
4. acbacc ⇒ b
5. accbc ⇒ cbaccaccaccacac
6. accbacc ⇒ cbaccaccacac
7. bbacac ⇒ cbacc
8. bbaccacac ⇒ cbc
9. bbaccaccacac ⇒ ccbacc
10. bbaccaccaccacac ⇒ ccbc
11. cbb ⇒ bbaccacc
12. cbcbaccacac ⇒ bbaccc
13. cbacb ⇒ bbacc
14. cbaccbaccacac ⇒ bbc
15. bbb ⇒ cbaccbaccacc
16. bbacb ⇒ cbaccbacc
17. bbaccb ⇒ cbcbaccacc
18. bbaccacb ⇒ cbcbacc
19. cbcbaccacb ⇒ bbacccbacc
20. cbcbaccaccacacacb ⇒ bbcbacc
...

Collecting factors up to length 6 / frequency 7:

[2/0]ac52lf:41,lp:4,ls:7,rf:29,rs:3,lprs:3,a:2
[2/1]cb34lf:21,lp:7,ls:6,rf:17,rp:9,lsrp:3,a:2
[2/2]ca21lf:21,rf:12,a:2
[2/3]bb20lf:10,lp:8,ls:2,rf:6,rp:6,lsrp:1,a:3
[2/4]cc20lf:18,ls:2,rf:27,rp:2,rs:11,a:3
[2/5]ba16lf:16,rf:17,a:2
[2/6]bc7lf:5,ls:2,rf:6,rs:3,a:7
[3/0]cac28lf:21,ls:7,rf:12,rs:3,a:2
[3/1]acc22lf:18,lp:2,ls:2,rf:23,rs:10,a:3
[3/2]bac16lf:16,rf:17,a:2
[3/3]bba14lf:7,lp:7,rf:4,rp:4,a:3
[3/4]acb14lf:7,lp:2,ls:5,a:4
[3/5]cba12lf:9,lp:3,rf:13,rp:6,a:2
[3/6]cca12lf:12,rf:9,a:7
[4/0]acac16lf:9,ls:7,rf:3,rs:3,a:2
[4/1]bbac14lf:7,lp:7,rf:4,rp:4,a:3
[4/2]bacc14lf:12,ls:2,rf:17,rs:7,a:3
[4/3]cbac12lf:9,lp:3,rf:13,rp:6,a:2
[4/4]ccac12lf:12,rf:9,a:7
[4/5]acca12lf:12,rf:9,a:7
[4/6]accb7lf:4,lp:2,ls:1,rf:2,a:6
[5/0]cacac12lf:7,ls:5,rf:3,rs:3,a:7
[5/1]accac12lf:12,rf:9,a:7
[5/2]bbacc10lf:5,lp:5,rf:4,rp:4,rs:1,re:1,a:5
[5/3]cbacc10lf:7,lp:1,ls:2,rf:13,rp:6,rs:6,re:1,lsrp:1,a:3
[5/4]bacca8lf:8,rf:6,a:7
[5/5]cbcba6lf:3,lp:3,rf:2,rp:2,a:9
[5/6]ccaca6lf:6,rf:3,a:7

Considering [length 4 / frequency 1] bbac=d.

Step 3

Rewriting system is complete. See ⟨a, b | abbaabaab=b⟩.