Morphocompletion for #1793 ⟨a, b | ababbbaab=a

Solved by morph:6/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbba ⇒ abaabb
2. abaabba ⇒ aaabbab
3. ababbba ⇒ abbaabb
4. abbaabba ⇒ aaabbabb
5. aaabbabbb ⇒ a
6. aaababbabbba ⇒ aaab
7. aaabbbbaabba ⇒ aaab
8. aaabbabbabbba ⇒ aaabb
9. aaababbbbaabba ⇒ aaabab
10. abaabbbbaabba ⇒ abaab
11. abbaabbbbaabba ⇒ abbaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ba, [2/2] ab, [2/3] aa
Length 3:[3/0] bba, [3/1] abb, [3/2] aab, [3/3] bbb, [3/4] aaa, [3/5] baa, [3/6] aba
Length 4:[4/0] abba, [4/1] aabb, [4/2] bbba, [4/3] abbb, [4/4] aaab, [4/5] baab, [4/6] babb
Length 5:[5/0] aabba, [5/1] abbba, [5/2] baabb, [5/3] babbb, [5/4] bbaab, [5/5] aaabb, [5/6] aabbb
Length 6:[6/0] baabba, [6/1] babbba, [6/2] bbaabb, [6/3] bbabbb, [6/4] bbbbaa, [6/5] abbbba, [6/6] bbbaab
Length 7:[7/0] bbaabba, [7/1] bbabbba, [7/2] bbbbaab, [7/3] bbbaabb, [7/4] abbabbb, [7/5] abbbbaa, [7/6] abbaabb

Considering [length 6 / frequency 1] babbba=c.

Step 2

Rewriting system is complete. See a, b | ababbbaab=a.