Morphocompletion for #1793 ⟨a, b | ababbbaab=a⟩

Solved by morph:6/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbba ⇒ abaabb
2. abaabba ⇒ aaabbab
3. ababbba ⇒ abbaabb
4. abbaabba ⇒ aaabbabb
5. aaabbabbb ⇒ a
6. aaababbabbba ⇒ aaab
7. aaabbbbaabba ⇒ aaab
8. aaabbabbabbba ⇒ aaabb
9. aaababbbbaabba ⇒ aaabab
10. abaabbbbaabba ⇒ abaab
11. abbaabbbbaabba ⇒ abbaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb35lf:34,ls:1,rf:8,rs:4,a:3
[2/1]ba35lf:25,ls:10,rf:7,a:3
[2/2]ab31lf:26,lp:5,rf:17,rp:4,rs:6,lprp:3,lprs:3,a:3
[2/3]aa25lf:19,lp:6,rf:16,rp:6,lprp:4,a:3
[3/0]bba30lf:20,ls:10,rf:4,a:3
[3/1]abb23lf:21,lp:2,rf:8,rp:2,rs:4,lprp:1,lprs:1,a:3
[3/2]aab15lf:14,lp:1,rf:10,rs:4,a:3
[3/3]bbb14lf:13,ls:1,a:3
[3/4]aaa10lf:5,lp:5,rf:6,rp:6,lprp:4,a:4
[3/5]baa8lf:8,rf:4,a:3
[3/6]aba8lf:5,lp:3,rf:3,rp:2,lprp:1,a:3
[4/0]abba20lf:12,lp:2,ls:6,rf:4,rp:2,lprp:1,lsrp:1,a:3
[4/1]aabb13lf:12,lp:1,rf:5,rs:3,lprs:1,a:3
[4/2]bbba12lf:8,ls:4,a:3
[4/3]abbb10lf:9,ls:1,a:3
[4/4]aaab10lf:5,lp:5,rf:6,rp:6,rs:2,re:2,lprp:4,lprs:2,a:4
[4/5]baab8lf:8,rf:4,rs:2,a:3
[4/6]babb7lf:7,rf:1,rs:1,a:3
[5/0]aabba14lf:8,ls:6,rf:2,a:4
[5/1]abbba8lf:4,ls:4,a:3
[5/2]baabb8lf:8,rf:2,rs:2,a:3
[5/3]babbb6lf:5,ls:1,a:3
[5/4]bbaab6lf:6,rf:2,rs:1,a:3
[5/5]aaabb6lf:3,lp:3,rf:3,rp:3,rs:1,re:1,lprp:1,lprs:1,a:4
[5/6]aabbb5lf:4,lp:1,a:5
[6/0]baabba12lf:6,ls:6,a:4
[6/1]babbba6lf:3,ls:3,a:3
[6/2]bbaabb6lf:6,rf:1,rs:1,a:3
[6/3]bbabbb4lf:3,ls:1,a:11
[6/4]bbbbaa4lf:4,a:20
[6/5]abbbba4lf:4,a:20
[6/6]bbbaab4lf:4,a:20
[7/0]bbaabba10lf:5,ls:5,a:4
[7/1]bbabbba4lf:2,ls:2,a:17
[7/2]bbbbaab4lf:4,a:20
[7/3]bbbaabb4lf:4,a:20
[7/4]abbabbb4lf:3,ls:1,a:11
[7/5]abbbbaa4lf:4,a:20
[7/6]abbaabb4lf:2,lp:2,rf:1,rp:1,rs:1,re:1,a:3

Considering [length 6 / frequency 1] babbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababbbaab=a⟩.