| Back: | ⟨a, b | ababbaaab=a⟩ |
|---|
Solved by morph:3/2. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaaabb ⇒ aabbaa |
| 2. | abaaabb ⇒ ababbaa |
| 3. | aabbaaab ⇒ ababbaaa |
| 4. | aaababbaaa ⇒ aabbaaaaab |
| 5. | aaaabaabb ⇒ aabbaabaa |
| 6. | ababbaaab ⇒ a |
| 7. | abaababbaaa ⇒ ababbaaaaab |
| 8. | abaaabaabb ⇒ ababbaabaa |
| 9. | aaaababaabb ⇒ aaaababbbaa |
| 10. | aaaabaabaabb ⇒ aabbaabaabaa |
| 11. | abaaababaabb ⇒ abaaababbbaa |
| 12. | aabbaababbaaa ⇒ aaaab |
| 13. | ababbaabbaaaaab ⇒ aabbaaa |
| 14. | ababbaababbaaa ⇒ abaaab |
| 15. | aabbaababbaabbaa ⇒ aaaababb |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb |
|---|---|
| Length 3: | [3/0] aab, [3/1] aaa, [3/2] abb, [3/3] aba, [3/4] baa, [3/5] bba, [3/6] bab |
| Length 4: | [4/0] aabb, [4/1] aaab, [4/2] bbaa, [4/3] abaa, [4/4] baaa, [4/5] abab, [4/6] abba |
| Length 5: | [5/0] abbaa, [5/1] baabb, [5/2] ababb, [5/3] bbaaa, [5/4] aaaab, [5/5] babba, [5/6] aabba |
| Length 6: | [6/0] ababba, [6/1] abbaaa, [6/2] abaabb, [6/3] aabbaa, [6/4] babbaa, [6/5] abaaab, [6/6] aaaaba |
| Length 7: | [7/0] ababbaa, [7/1] babbaaa, [7/2] aabaabb, [7/3] aababba, [7/4] baababb, [7/5] babaabb, [7/6] aabbaab |
Considering [length 3 / frequency 2] abb=c.
Rewriting system is complete. See ⟨a, b | ababbaaab=a⟩.