| Back: | ⟨a, b | ababbaaab=a⟩ |
|---|
Solved by morph:3/2. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaaabb ⇒ aabbaa |
| 2. | abaaabb ⇒ ababbaa |
| 3. | aabbaaab ⇒ ababbaaa |
| 4. | aaababbaaa ⇒ aabbaaaaab |
| 5. | aaaabaabb ⇒ aabbaabaa |
| 6. | ababbaaab ⇒ a |
| 7. | abaababbaaa ⇒ ababbaaaaab |
| 8. | abaaabaabb ⇒ ababbaabaa |
| 9. | aaaababaabb ⇒ aaaababbbaa |
| 10. | aaaabaabaabb ⇒ aabbaabaabaa |
| 11. | abaaababaabb ⇒ abaaababbbaa |
| 12. | aabbaababbaaa ⇒ aaaab |
| 13. | ababbaabbaaaaab ⇒ aabbaaa |
| 14. | ababbaababbaaa ⇒ abaaab |
| 15. | aabbaababbaabbaa ⇒ aaaababb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 65 | lf:52,lp:8,ls:5,rf:41,rp:8,rs:9,lprp:7,lsrp:3,lprs:5 |
|---|---|---|---|
| [2/1] | ab | 53 | lf:43,lp:7,ls:3,rf:29,rp:6,rs:4,lprp:5,lsrp:1,lprs:2 |
| [2/2] | ba | 33 | lf:33,rf:24 |
| [2/3] | bb | 27 | lf:20,ls:7,rf:14,rs:1 |
| [3/0] | aab | 32 | lf:26,lp:3,ls:3,rf:16,rp:5,rs:4,lsrp:1,lprs:1 |
| [3/1] | aaa | 30 | lf:21,lp:5,ls:4,rf:16,rp:3,rs:2,lprp:1,lsrp:1 |
| [3/2] | abb | 27 | lf:20,ls:7,rf:12,rs:1 |
| [3/3] | aba | 27 | lf:20,lp:7,rf:13,rp:6,lprp:5 |
| [3/4] | baa | 24 | lf:23,ls:1,rf:17,rs:7 |
| [3/5] | bba | 13 | lf:13,rf:11 |
| [3/6] | bab | 10 | lf:10,rf:7 |
| [4/0] | aabb | 22 | lf:12,lp:3,ls:7,rf:5,rp:5,lsrp:3,a:1 |
| [4/1] | aaab | 15 | lf:11,lp:1,ls:3,rf:7,rs:4,lprs:1 |
| [4/2] | bbaa | 14 | lf:13,ls:1,rf:11,rs:4 |
| [4/3] | abaa | 14 | lf:10,lp:4,rf:6,rp:2,rs:3,lprp:1,lprs:1,a:2 |
| [4/4] | baaa | 14 | lf:10,ls:4,rf:6,rs:2 |
| [4/5] | abab | 13 | lf:10,lp:3,rf:7,rp:4 |
| [4/6] | abba | 13 | lf:13,rf:9 |
| [5/0] | abbaa | 14 | lf:13,ls:1,rf:9,rs:2 |
| [5/1] | baabb | 12 | lf:7,ls:5,a:7 |
| [5/2] | ababb | 11 | lf:8,lp:3,rf:7,rp:4,rs:1 |
| [5/3] | bbaaa | 11 | lf:7,ls:4,rf:4,rs:2 |
| [5/4] | aaaab | 10 | lf:5,lp:4,ls:1,rf:5,rp:3,rs:3,re:1,lprp:1,a:3 |
| [5/5] | babba | 8 | lf:8,rf:4 |
| [5/6] | aabba | 8 | lf:5,lp:3,rf:5,rp:5,a:1 |
| [6/0] | ababba | 11 | lf:8,lp:3,rf:4,rp:4 |
| [6/1] | abbaaa | 11 | lf:7,ls:4,rf:4,rs:2 |
| [6/2] | abaabb | 10 | lf:5,ls:5,a:8 |
| [6/3] | aabbaa | 9 | lf:5,lp:3,ls:1,rf:5,rp:5,rs:1,re:1,a:1 |
| [6/4] | babbaa | 8 | lf:8,rf:4,rs:1 |
| [6/5] | abaaab | 6 | lf:3,lp:3,rf:2,rp:2,rs:1,re:1,lprp:1,a:2 |
| [6/6] | aaaaba | 6 | lf:3,lp:3,rf:2,rp:2,lprp:1,a:7 |
| [7/0] | ababbaa | 11 | lf:8,lp:3,rf:4,rp:4,rs:1,re:1 |
| [7/1] | babbaaa | 9 | lf:5,ls:4,rf:2,rs:1 |
| [7/2] | aabaabb | 6 | lf:3,ls:3,a:8 |
| [7/3] | aababba | 5 | lf:5,a:2 |
| [7/4] | baababb | 4 | lf:4,a:2 |
| [7/5] | babaabb | 4 | lf:2,ls:2,a:10 |
| [7/6] | aabbaab | 4 | lf:2,lp:2,rf:2,rp:2,a:3 |
Considering [length 3 / frequency 2] abb=c.
Rewriting system is complete. See ⟨a, b | ababbaaab=a⟩.