Morphocompletion for #1784 ⟨a, b | abababaab=b

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabb ⇒ baab
2. aababb ⇒ babaab
3. abababab ⇒ bababaab
4. abababaab ⇒ b
5. aabababb ⇒ bababaab
6. bababaabaab ⇒ abb
7. abbababb ⇒ bababbab
8. abbababab ⇒ bababbaab
9. abababbab ⇒ bbababaab
10. abababbaab ⇒ bb
11. bababbaabaab ⇒ abbb
12. abbbababb ⇒ bababbbab
13. abababbbaab ⇒ bbb
14. bababbbaabaab ⇒ abbbb
15. abababbbbaab ⇒ bbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] bab, [3/1] aba, [3/2] aab, [3/3] abb, [3/4] baa, [3/5] bba, [3/6] bbb
Length 4:[4/0] abab, [4/1] baba, [4/2] baab, [4/3] babb, [4/4] abba, [4/5] aaba, [4/6] abbb
Length 5:[5/0] babab, [5/1] ababa, [5/2] ababb, [5/3] abaab, [5/4] bbaab, [5/5] abbab, [5/6] abbba
Length 6:[6/0] ababab, [6/1] bababb, [6/2] aabaab, [6/3] bbbaab, [6/4] bababa, [6/5] abbaba, [6/6] ababbb
Length 7:[7/0] abababb, [7/1] baabaab, [7/2] bababbb, [7/3] bbababb, [7/4] abbabab, [7/5] bababab, [7/6] bababba

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See a, b | abababaab=b.