| Back: | ⟨a, b | abababaab=b⟩ |
|---|
Solved by morph:2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabb ⇒ baab |
| 2. | aababb ⇒ babaab |
| 3. | abababab ⇒ bababaab |
| 4. | abababaab ⇒ b |
| 5. | aabababb ⇒ bababaab |
| 6. | bababaabaab ⇒ abb |
| 7. | abbababb ⇒ bababbab |
| 8. | abbababab ⇒ bababbaab |
| 9. | abababbab ⇒ bbababaab |
| 10. | abababbaab ⇒ bb |
| 11. | bababbaabaab ⇒ abbb |
| 12. | abbbababb ⇒ bababbbab |
| 13. | abababbbaab ⇒ bbb |
| 14. | bababbbaabaab ⇒ abbbb |
| 15. | abababbbbaab ⇒ bbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 71 | lf:52,lp:9,ls:10,rf:24,rp:3,rs:8,lsrp:3,lprs:5,lsrs:3 |
|---|---|---|---|
| [2/1] | ba | 43 | lf:40,lp:3,rf:21,rp:7 |
| [2/2] | bb | 24 | lf:19,ls:5,rf:17,rp:4,rs:6,re:1,a:2 |
| [2/3] | aa | 16 | lf:13,lp:3,rf:6 |
| [3/0] | bab | 36 | lf:30,lp:3,ls:3,rf:15,rp:6,rs:2,lsrp:2 |
| [3/1] | aba | 34 | lf:28,lp:6,rf:10 |
| [3/2] | aab | 23 | lf:13,lp:3,ls:7,rf:6,rs:6,lprs:12 |
| [3/3] | abb | 22 | lf:14,lp:3,ls:5,rf:6,rp:3,rs:1,re:1,a:2 |
| [3/4] | baa | 10 | lf:10,rf:6,rp:1 |
| [3/5] | bba | 9 | lf:9,rf:4,rp:1,a:6 |
| [3/6] | bbb | 5 | lf:5,rf:7,rp:2,rs:4,re:1,a:7 |
| [4/0] | abab | 31 | lf:23,lp:6,ls:2,rf:6 |
| [4/1] | baba | 20 | lf:17,lp:3,rf:10,rp:6 |
| [4/2] | baab | 17 | lf:10,ls:7,rf:6,rp:1,rs:6,re:1 |
| [4/3] | babb | 14 | lf:10,ls:4,rf:3,a:6 |
| [4/4] | abba | 7 | lf:5,lp:2,rf:2,a:6 |
| [4/5] | aaba | 7 | lf:5,lp:2,a:2 |
| [4/6] | abbb | 5 | lf:4,lp:1,rf:3,rp:2,rs:1,re:1,a:7 |
| [5/0] | babab | 20 | lf:15,lp:3,ls:2,rf:6,rp:5,lsrp:2 |
| [5/1] | ababa | 17 | lf:11,lp:6,rf:3 |
| [5/2] | ababb | 14 | lf:10,ls:4,rf:3,a:6 |
| [5/3] | abaab | 9 | lf:5,ls:4,rf:4,rs:4 |
| [5/4] | bbaab | 8 | lf:5,ls:3,rf:1,rs:1,a:6 |
| [5/5] | abbab | 6 | lf:3,lp:2,ls:1,rf:1,rs:1,lprs:1,a:13 |
| [5/6] | abbba | 4 | lf:3,lp:1,rf:1,a:14 |
| [6/0] | ababab | 17 | lf:9,lp:6,ls:2 |
| [6/1] | bababb | 14 | lf:9,lp:2,ls:3,rf:3,rp:3,lsrp:2,a:6 |
| [6/2] | aabaab | 6 | lf:3,ls:3,a:2 |
| [6/3] | bbbaab | 5 | lf:3,ls:2,a:14 |
| [6/4] | bababa | 5 | lf:4,lp:1,rf:3,rp:2 |
| [6/5] | abbaba | 4 | lf:2,lp:2,a:22 |
| [6/6] | ababbb | 3 | lf:3,rf:1,a:14 |
| [7/0] | abababb | 10 | lf:5,lp:4,ls:1,a:6 |
| [7/1] | baabaab | 6 | lf:3,ls:3,a:2 |
| [7/2] | bababbb | 4 | lf:3,lp:1,rf:1,rp:1,a:14 |
| [7/3] | bbababb | 4 | lf:2,ls:2,a:22 |
| [7/4] | abbabab | 4 | lf:2,lp:2,a:22 |
| [7/5] | bababab | 4 | lf:2,ls:2,a:1 |
| [7/6] | bababba | 4 | lf:3,lp:1,rf:2,rp:2,a:6 |
Considering [length 2 / frequency 0] ab=c.
Rewriting system is complete. See ⟨a, b | abababaab=b⟩.