Morphocompletion for #1783 ⟨a, b | abababaab=a

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabba ⇒ aabaab
2. aaabbba ⇒ abaaabb
3. abababa ⇒ aabaabb
4. aaababba ⇒ aabaabab
5. aabaabba ⇒ aababaab
6. aababaabb ⇒ a
7. aaababbba ⇒ abaaababb
8. aabaabbba ⇒ abaabaabb
9. aaabababba ⇒ aabaababab
10. aabaababba ⇒ aababaabab
11. aabaababbba ⇒ abaabaababb
12. aaaabababbba ⇒ aabaaabababb
13. aabaabababba ⇒ aababaababab
14. aababaababba ⇒ aaab
15. abaaabababbba ⇒ ababaaabababb
16. aababaababbba ⇒ abaababaababb
17. aababaabababba ⇒ aaabab
18. aababaaabaabbbba ⇒ aaababab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] bba, [3/3] bab, [3/4] abb, [3/5] aaa, [3/6] baa
Length 4:[4/0] aaba, [4/1] abab, [4/2] abba, [4/3] bbba, [4/4] abaa, [4/5] baba, [4/6] aaab
Length 5:[5/0] aabab, [5/1] ababa, [5/2] abbba, [5/3] babba, [5/4] aabaa, [5/5] ababb, [5/6] abaab
Length 6:[6/0] aababa, [6/1] ababba, [6/2] aabaab, [6/3] babbba, [6/4] aaabab, [6/5] ababab, [6/6] abaaba
Length 7:[7/0] aababaa, [7/1] ababbba, [7/2] aabaaba, [7/3] aababba, [7/4] bababba, [7/5] abaabab, [7/6] aababab

Considering [length 2 / frequency 0] ba=c.

Step 2

Rewriting system is complete. See a, b | abababaab=a.