| Back: | ⟨a, b | abababaab=a⟩ |
|---|
Solved by morph:2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaabba ⇒ aabaab |
| 2. | aaabbba ⇒ abaaabb |
| 3. | abababa ⇒ aabaabb |
| 4. | aaababba ⇒ aabaabab |
| 5. | aabaabba ⇒ aababaab |
| 6. | aababaabb ⇒ a |
| 7. | aaababbba ⇒ abaaababb |
| 8. | aabaabbba ⇒ abaabaabb |
| 9. | aaabababba ⇒ aabaababab |
| 10. | aabaababba ⇒ aababaabab |
| 11. | aabaababbba ⇒ abaabaababb |
| 12. | aaaabababbba ⇒ aabaaabababb |
| 13. | aabaabababba ⇒ aababaababab |
| 14. | aababaababba ⇒ aaab |
| 15. | abaaabababbba ⇒ ababaaabababb |
| 16. | aababaababbba ⇒ abaababaababb |
| 17. | aababaabababba ⇒ aaabab |
| 18. | aababaaabaabbbba ⇒ aaababab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ba | 69 | lf:52,ls:17,rf:38,a:2 |
|---|---|---|---|
| [2/1] | ab | 55 | lf:53,lp:2,rf:55,rp:6,rs:9,lprp:1,a:2 |
| [2/2] | aa | 53 | lf:37,lp:16,rf:35,rp:11,lprp:10,a:2 |
| [2/3] | bb | 27 | lf:26,ls:1,rf:8,rs:8,a:2 |
| [3/0] | aba | 39 | lf:36,lp:2,ls:1,rf:38,rp:6,lprp:1,a:2 |
| [3/1] | aab | 38 | lf:28,lp:10,rf:28,rp:8,rs:3,lprp:3,lprs:2,a:2 |
| [3/2] | bba | 32 | lf:16,ls:16,a:7 |
| [3/3] | bab | 23 | lf:23,rf:21,rs:6,a:2 |
| [3/4] | abb | 18 | lf:17,ls:1,rf:8,rs:8,a:2 |
| [3/5] | aaa | 15 | lf:9,lp:6,rf:7,rp:3,a:9 |
| [3/6] | baa | 12 | lf:12,rf:17,a:2 |
| [4/0] | aaba | 32 | lf:22,lp:10,rf:22,rp:8,lprp:3,a:2 |
| [4/1] | abab | 24 | lf:23,lp:1,rf:21,rp:1,rs:6,a:2 |
| [4/2] | abba | 16 | lf:8,ls:8,a:7 |
| [4/3] | bbba | 16 | lf:8,ls:8,a:8 |
| [4/4] | abaa | 13 | lf:12,lp:1,rf:17,rp:5,a:2 |
| [4/5] | baba | 13 | lf:12,ls:1,rf:10,a:2 |
| [4/6] | aaab | 13 | lf:8,lp:5,rf:7,rp:3,rs:1,re:1,a:9 |
| [5/0] | aabab | 21 | lf:16,lp:5,rf:15,rp:3,rs:3,lprs:1,a:2 |
| [5/1] | ababa | 14 | lf:12,lp:1,ls:1,rf:10,rp:1,a:2 |
| [5/2] | abbba | 14 | lf:7,ls:7,a:8 |
| [5/3] | babba | 12 | lf:6,ls:6,a:10 |
| [5/4] | aabaa | 11 | lf:6,lp:5,rf:7,rp:5,a:3 |
| [5/5] | ababb | 11 | lf:11,rf:5,rs:5,a:10 |
| [5/6] | abaab | 10 | lf:10,rf:13,rp:3,rs:2,a:2 |
| [6/0] | aababa | 15 | lf:10,lp:5,rf:9,rp:3,a:2 |
| [6/1] | ababba | 12 | lf:6,ls:6,a:10 |
| [6/2] | aabaab | 11 | lf:6,lp:5,rf:6,rp:4,rs:1,re:1,a:3 |
| [6/3] | babbba | 10 | lf:5,ls:5,a:13 |
| [6/4] | aaabab | 8 | lf:5,lp:3,rf:5,rp:2,rs:1,re:1,a:16 |
| [6/5] | ababab | 7 | lf:6,lp:1,rf:5,rs:3,a:3 |
| [6/6] | abaaba | 6 | lf:6,rf:9,rp:3,a:8 |
| [7/0] | aababaa | 10 | lf:5,lp:5,rf:4,rp:3,a:2 |
| [7/1] | ababbba | 10 | lf:5,ls:5,a:13 |
| [7/2] | aabaaba | 6 | lf:3,lp:3,rf:3,rp:2,a:11 |
| [7/3] | aababba | 6 | lf:3,ls:3,a:10 |
| [7/4] | bababba | 6 | lf:3,ls:3,a:18 |
| [7/5] | abaabab | 6 | lf:6,rf:7,rp:1,rs:2,a:10 |
| [7/6] | aababab | 5 | lf:5,rf:5,rs:3,a:18 |
Considering [length 2 / frequency 0] ba=c.
Rewriting system is complete. See ⟨a, b | abababaab=a⟩.