| Back: | ⟨a, b | abababaab=a⟩ |
|---|
Solved by morph:2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaabba ⇒ aabaab |
| 2. | aaabbba ⇒ abaaabb |
| 3. | abababa ⇒ aabaabb |
| 4. | aaababba ⇒ aabaabab |
| 5. | aabaabba ⇒ aababaab |
| 6. | aababaabb ⇒ a |
| 7. | aaababbba ⇒ abaaababb |
| 8. | aabaabbba ⇒ abaabaabb |
| 9. | aaabababba ⇒ aabaababab |
| 10. | aabaababba ⇒ aababaabab |
| 11. | aabaababbba ⇒ abaabaababb |
| 12. | aaaabababbba ⇒ aabaaabababb |
| 13. | aabaabababba ⇒ aababaababab |
| 14. | aababaababba ⇒ aaab |
| 15. | abaaabababbba ⇒ ababaaabababb |
| 16. | aababaababbba ⇒ abaababaababb |
| 17. | aababaabababba ⇒ aaabab |
| 18. | aababaaabaabbbba ⇒ aaababab |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb |
|---|---|
| Length 3: | [3/0] aba, [3/1] aab, [3/2] bba, [3/3] bab, [3/4] abb, [3/5] aaa, [3/6] baa |
| Length 4: | [4/0] aaba, [4/1] abab, [4/2] abba, [4/3] bbba, [4/4] abaa, [4/5] baba, [4/6] aaab |
| Length 5: | [5/0] aabab, [5/1] ababa, [5/2] abbba, [5/3] babba, [5/4] aabaa, [5/5] ababb, [5/6] abaab |
| Length 6: | [6/0] aababa, [6/1] ababba, [6/2] aabaab, [6/3] babbba, [6/4] aaabab, [6/5] ababab, [6/6] abaaba |
| Length 7: | [7/0] aababaa, [7/1] ababbba, [7/2] aabaaba, [7/3] aababba, [7/4] bababba, [7/5] abaabab, [7/6] aababab |
Considering [length 2 / frequency 0] ba=c.
Rewriting system is complete. See ⟨a, b | abababaab=a⟩.