Morphocompletion for #1729 ⟨a, b | aabbbaaab=a

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaaab ⇒ aabbbaa
2. aaaababbb ⇒ a
3. aabbbaaa ⇒ aaaababb
4. abaaaba ⇒ aaaabab
5. aaaababbababbb ⇒ aabbba
6. aaaabbbbaaa ⇒ aaaabaababb
7. aaaabaababbba ⇒ aaaab
8. aaaababaababb ⇒ abaaa
9. aaaababababbba ⇒ abaaab
10. aaaababbaababb ⇒ abbaaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aba, [3/2] aab, [3/3] abb, [3/4] bab, [3/5] bba, [3/6] bbb
Length 4:[4/0] aaaa, [4/1] aaba, [4/2] abab, [4/3] aaab, [4/4] babb, [4/5] abbb, [4/6] baaa
Length 5:[5/0] aaaab, [5/1] ababb, [5/2] aaaba, [5/3] aabab, [5/4] babbb, [5/5] bbaaa, [5/6] abbba
Length 6:[6/0] aaaaba, [6/1] aababb, [6/2] ababbb, [6/3] aaabab, [6/4] bbbaaa, [6/5] babbba, [6/6] baabab
Length 7:[7/0] aaaabab, [7/1] baababb, [7/2] ababbba, [7/3] aaababb, [7/4] aababbb, [7/5] bababbb, [7/6] aaaabaa

Considering [length 3 / frequency 0] aaa=c.

Step 2

Rewriting system is complete. See a, b | aabbbaaab=a.