| Back: | ⟨a, b | aabbabbaa=a⟩ |
|---|
Solved by morph:2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | abbaaa ⇒ aaabba |
| 2. | abbabbaa ⇒ aabbabba |
| 3. | aaabbabba ⇒ a |
| 4. | aaabbaabbabba ⇒ abbaa |
| 5. | aaabbaabbaabbabba ⇒ abbaabbaa |
| 6. | aaabbaabbaabbaabbabba ⇒ abbaabbaabbaa |
| 7. | aaabbaabbaabbaabbaabbabba ⇒ abbaabbaabbaabbaa |
| 8. | aaabbaabbaabbaabbaabbaabbabba ⇒ abbaabbaabbaabbaabbaa |
| 9. | aaabbaabbaabbaabbaabbaabbaabbabba ⇒ abbaabbaabbaabbaabbaabbaa |
| 10. | aaabbaabbaabbaabbaabbaabbaabbaabbabba ⇒ abbaabbaabbaabbaabbaabbaabbaa |
| 11. | aaabbaabbaabbaabbaabbaabbaabbaabbaabbabba ⇒ abbaabbaabbaabbaabbaabbaabbaabbaa |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb |
|---|---|
| Length 3: | [3/0] bba, [3/1] abb, [3/2] aab, [3/3] baa, [3/4] aaa, [3/5] bab |
| Length 4: | [4/0] abba, [4/1] aabb, [4/2] bbaa, [4/3] baab, [4/4] aaab, [4/5] bbab, [4/6] babb |
| Length 5: | [5/0] aabba, [5/1] abbaa, [5/2] bbaab, [5/3] baabb, [5/4] babba, [5/5] aaabb, [5/6] abbab |
| Length 6: | [6/0] bbaabb, [6/1] baabba, [6/2] abbaab, [6/3] aabbaa, [6/4] bbabba, [6/5] aaabba, [6/6] abbabb |
| Length 7: | [7/0] bbaabba, [7/1] abbaabb, [7/2] aabbaab, [7/3] baabbaa, [7/4] abbabba, [7/5] aaabbaa, [7/6] aabbabb |
Considering [length 2 / frequency 0] aa=c.
Rewriting system is complete. See ⟨a, b | aabbabbaa=a⟩.