Morphocompletion for #1719 ⟨a, b | aabbabaab=a

Solved by morph:5/0,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababaab ⇒ aabbaba
2. aaabab ⇒ ababaa
3. aabbabaab ⇒ a
4. aabaabab ⇒ aabbabaa
5. ababaaaab ⇒ aaaabbaba
6. ababaaabbaba ⇒ aaab
7. aabbabaaaab ⇒ aabaaabbaba
8. ababaaabaab ⇒ aaabaabbaba
9. aabbabaaabbaba ⇒ aabaab
10. ababaaaaaab ⇒ aaaaaabbaba
11. ababaaaaabbaba ⇒ aaaaab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] aaa, [3/3] bab
Length 4:[4/0] abab, [4/1] baba, [4/2] aaab, [4/3] abaa
Length 5:[5/0] ababa, [5/1] aabba, [5/2] babaa, [5/3] bbaba
Length 6:[6/0] ababaa, [6/1] aabbab, [6/2] abbaba, [6/3] babaaa

Considering [length 5 / frequency 0] ababa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cba ⇒ abc
2. aa ⇒ cc
3. aac ⇒ ccc
4. aabc ⇒ ccbc
5. cca ⇒ acc
6. abca ⇒ cbcc
7. cabba ⇒ ccbbc
8. cabab ⇒ a
9. aaba ⇒ cabc
10. ababa ⇒ c
11. ababcc ⇒ ca
12. ccac ⇒ accc
13. ccabc ⇒ accbc
14. cbcabcb ⇒ aba
15. abcac ⇒ cbccc
16. acabcb ⇒ ca
17. ccbca ⇒ acbcc
18. ccbbaba ⇒ cab
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ab, [2/1] ca, [2/2] ba, [2/3] cc, [2/4] bc, [2/5] cb, [2/6] ac
Length 3:[3/0] aba, [3/1] abc, [3/2] cab, [3/3] bca, [3/4] bab, [3/5] cca, [3/6] cac
Length 4:[4/0] abab, [4/1] cbca, [4/2] cabc, [4/3] baba, [4/4] abcb, [4/5] caba, [4/6] acab
Length 5:[5/0] cabcb, [5/1] acabc, [5/2] cbcab, [5/3] ccbba, [5/4] ababc, [5/5] babcc, [5/6] bbaba

Considering [length 2 / frequency 0] ab=d.

Step 3

Rewriting system is complete. See a, b | aabbabaab=a.